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- 2 answers
Posted by Khushi Rawat 6 years, 8 months ago
- 1 answers
Posted by Surya Prakash 6 years, 8 months ago
- 1 answers
Posted by V Charlene 6 years, 8 months ago
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Posted by Pranjul Singh 6 years, 8 months ago
- 2 answers
Yogita Ingle 6 years, 8 months ago
let root 5 be rational
then it must in the form of p/q [q is not equal to 0][p and q are co-prime]
root 5=p/q
=> root 5 × q = p
squaring on both sides
=> 5×q×q = p×p ------> 1
p×p is divisible by 5
p is divisible by 5
p = 5c [c is a positive integer] [squaring on both sides ]
p×p = 25c×c --------- > 2
sub p×p in 1
5×q×q = 25×c×c
q×q = 5×c×c
=> q is divisble by 5
thus q and p have a common factor 5
there is a contradiction
as our assumsion p &q are co prime but it has a common factor
so √5 is an irrational
Posted by Chinmaya Senapati 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
Let the cubic polynomial be ax3 + bx2 +cx + d
and its zeroes be {tex}\alpha ,\beta {/tex} and {tex}\gamma{/tex}.
Then, {tex}\alpha + \beta + \gamma= 2 = \frac { - b } { a }{/tex}
{tex}\alpha \beta + \beta \gamma + \gamma \alpha = - 7 = \frac { C } { a }{/tex}
and {tex}\alpha \beta \gamma = - 14 = \frac { - d } { a }{/tex}
If a = 1, then b = -2, c = -7, d = 14
So, one cubic polynomial which fits the given
conditions is x3 - 2x2 - 7x + 14.
Posted by Ajeet Singh 6 years, 8 months ago
- 1 answers
Yogita Ingle 6 years, 8 months ago
2√45+2√20/2√5
2√3×3×5 + 2√2×2×5/2√5
2×3√5 + 2×2√5/2√5
6√5 + 4√5/2√5
= 10√5/2√5
5
hence it is rational number
Posted by Neev Soni 6 years, 8 months ago
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Posted by Shreya Dubey 6 years, 8 months ago
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Posted by Chaitanya Jaybhaye 6 years, 8 months ago
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Posted by Ujwala Nikam 6 years, 8 months ago
- 2 answers
Posted by Juhu Panda 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
Since {tex}\alpha \text { and } \beta{/tex} are the zeroes of the polynomial, then
{tex}{/tex}{tex}\alpha + \beta = - \frac { \text { Coefficient of } x } { \text { Coefficient of } x ^ { 2 } }{/tex}{tex}{/tex}
{tex}{/tex}{tex}\Rightarrow\ \alpha + \beta = - \left( \frac { - 1 } { 1 } \right) = 1{/tex}.........(i)
Given, {tex}\alpha - \beta = 9{/tex}...............(ii)
Solving (i) and (ii), {tex}\alpha = 5 , \beta = - 4{/tex}
{tex}\alpha \beta = \frac { \text { Constant term } } { \text { Coefficient of } x ^ { 2 } }{/tex}
{tex}\Rightarrow\ \alpha \beta = - k{/tex}
{tex}\Rightarrow\ {/tex}(5)(-4) = -k
{tex}\Rightarrow{/tex}k = 20
So,required value of k is 20
Posted by Yukthanoyal Yukthanoyal 6 years, 8 months ago
- 3 answers
Pk . 6 years, 8 months ago
Posted by Tech Really 6 years, 8 months ago
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Posted by Vedanshi Gupta 6 years, 8 months ago
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Posted by Piyush Bhumiputra 6 years, 8 months ago
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Posted by Kritika Tyagi 6 years, 8 months ago
- 2 answers
Posted by Naman Arora 6 years, 8 months ago
- 4 answers
Kanika Sehgal 6 years, 8 months ago
Please note given set of equations have infinte solutions
?D? ??Wish Me At 12Pm...?? 6 years, 8 months ago
Pk . 6 years, 8 months ago
Posted by Bhavesh Tilkar 6 years, 8 months ago
- 1 answers
Posted by Awasthi Sir 6 years, 8 months ago
- 2 answers
Yogita Ingle 6 years, 8 months ago
Rational numbers can be written as ab where a and b are integers. Also remember that rational numbers include terminating decimal numbers. Therefore −√8;3,3231089...;3+√2;π are all irrational.
Posted by Priyansh Bhardwaj 6 years, 8 months ago
- 2 answers
Posted by ????? ?????? 6 years, 8 months ago
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Posted by Karan Choudhary 6 years, 8 months ago
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Posted by Dazzling Alka 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
The LCM of 28 and 32
28 = 2× 2 × 7=22×7
32 = 2 × 2 × 2 × 2 × 2=25
LCM = 25 × 7 = 224
Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32
= LCM of 8 & 12 = 224 - 20 = 204
Therefore, 204 is smallest number which when divided by 28 and 32 leaves remainder 8 and 12 respectively.
Posted by Anurag Yadav 6 years, 8 months ago
- 0 answers
Posted by Vijaya Ragavan 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
Let speed of ritu in still water = x km/h
Speed of stream = y km/h
Then downstream speed of ritu = x + y
Upstream speed of ritu = x - y
According to question
{tex}\frac{20}{x+y}=2{/tex}
{tex}\Rightarrow{/tex} x +y = 10 .... (1)
Also,
{tex}\frac{4}{x-y}=2{/tex}
{tex}\Rightarrow{/tex} x - y = 2 ..... (2)
Add (1) and (2)
2x = 12
{tex}\Rightarrow{/tex} x = 6
From (1), we get
6 + y = 10
{tex}\Rightarrow{/tex} y = 4
Therefore, Speed of ritu in still water = 6km/h
Speed of stream = 4km/h
Posted by Riya Rai 6 years, 8 months ago
- 1 answers
Yogita Ingle 6 years, 8 months ago
38220>196 we always divide greater number with smaller one.
Divide 38220 by 196 then we get quotient 195 and no remainder so we can write it as
38220 = 196 × 195 + 0
As there is no remainder so deviser 196 is our HCF
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Isheta Singh 6 years, 8 months ago
1Thank You