CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Ask questions which are clear, concise and easy to understand.

Ask Question

Find the quadratic polynomial whose sum and product of zeros are 'underroot2+1and 1/underroot2+1

Posted by The Patel 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the values of a & b so that x^4+x^3+8x^2+ax+b,is exactly divisible by x^2+1

Posted by Mahima Pandit 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

If {tex}x^4+x^3+8x^2+ax +b{/tex} is exactly divisible by x² + 1, the remainder after division should be zero.
Now let us perform long division

We get, remainder = x (a - 1) + (b - 7)
x (a - 1) + (b - 7 ) = 0
{tex}\Rightarrow{/tex} x (a - 1) + (b - 7) = 0x + 0
{tex}\Rightarrow{/tex} a - 1 = 0 and b - 7 = 0 [On equating the coefficients of like powers of x]
{tex}\Rightarrow{/tex}a = 1 and b = 7

0Thank You

ANSWER

Find the zeros of the polynomial y^2 - √20 and verify the relationship between zeros and the coefficients .

Posted by Priyank Maheshwari 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove that 7√5 are irrational

Posted by Subhash Chandra Sneh Lata 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We can prove {tex}7 \sqrt { 5 }{/tex} irrational by contradiction.
Let us suppose that {tex}7 \sqrt { 5 }{/tex} is rational.
It means we have some co-prime integers a and b (b≠ 0)

such that
{tex}7 \sqrt { 5 } = \frac { a } { b }{/tex}
{tex}\Rightarrow \sqrt { 5 } = \frac { a } { 7 b }{/tex} .......(1)
R.H.S of (1) is rational but we know that {tex}\sqrt { 5 }{/tex} is irrational.
It is not possible which means our supposition is wrong.
Therefore, {tex}7 \sqrt { 5 }{/tex} cannot be rational.
Hence, it is irrational.

0Thank You

ANSWER

If -1 and 2 are two zeroes of the polynomial 2/

Posted by Meena Devi 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given polynomial is p(x) = 2x³- x²- 5x - 2
and -1 and 2 are zeroes of polynomial.

{tex}\therefore{/tex} {x - (-1)} (x - 2)= ( x + 1) (x - 2) = x² - 2x + x - 2 = x²- x - 2 is a factor of p(x)

For other zeroes, 2x + 1 = 0
{tex}\Rightarrow x = \frac { - 1 } { 2 }{/tex}
{tex}\therefore{/tex} Other zero = {tex}\frac { - 1 } { 2 }{/tex}

0Thank You

ANSWER

Chapter 2 2011 question

Posted by Manish Kumat 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which book is the best for class 10 maths, other than ncert

Posted by Anjali ?? 6 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Anjali ?? 6 years, 2 months ago

Ty?????

1Thank You

The Patel 6 years, 8 months ago

Every book has its own uniqueness.... But for my opinion K.C sinha ,S.chand are also good.

1Thank You

Nisha Kumari 6 years, 8 months ago

R.D sharma is best

1Thank You

Aish 753❤ 6 years, 8 months ago

R .D. Sharma 110%

2Thank You

?D? ??Wish Me At 12Pm...?? 6 years, 8 months ago

R.D. Sharma?

3Thank You

ANSWER

Find hcf of 81 and 237.exp

Posted by Raj Kumar 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Can anybody send me the solutions of exercise 3.6 from maths NCERT book.

Posted by Yogita Malik 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

You can check NCERT Solutions here : https://mycbseguide.com/ncert-solutions.html

0Thank You

ANSWER

prove that tana=sina/cosa

Posted by Radha Goyal 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Let triangle ABC similar to triangle DEF and their areas be respectively 64cm^2 and 121cm^2 if EF = 15.4cm find BC

Posted by Ishaa Vermaa 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 8 months ago

2Thank You

ANSWER

Which is best book for class 10 all subjects

Posted by Abul Fazal X Factor 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Define Real number, Primes number, Co-prime, Composite number. Explain with the help of examples.

Posted by Amit Patle 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 8 months ago

A natural number which has exactly two factors, i.e. 1 and the number itself, is a prime number. For example: 2, 3, 5, 7, 11, 19, 37, 41, 313, 241 etc.

Every non-prime number is a composite number. Composite numbers are those natural numbers which have more than two factors. Such numbers are divisible by other numbers as well. For example: 4, 6, 8, 10, 12, 14, 500, 6000 etc.
Numbers, which do not have any common factor between them other than one, are called co-prime numbers. For example 16 and 25 do not have any common factor other than one. Similarly 84 and 65 do not have any common factor and are hence co-prime.
All rational and all irrational number makes the collection of real numbers. It is denoted by the letter R . For example: 1, -2/3, 3/4, √2, √2 + 5

0Thank You

ANSWER

In a rectangular ABCD, AB=13,BC=7,AC=x+y,DA=3x+y, find x&y

Posted by Bijoy Seal 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 8 months ago

Here AC = x + y or CD = x + y

0Thank You

ANSWER

If there are two positive integers x and y express them in terms of primes as x=pq^3 and y=p^3q

Posted by Adithyan V.S 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If one zero of a polynomial (a^2 +9)x^2 +13x+ 6a is the reciprocal of the other, find the value of a

Posted by Adithyan V.S 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Amit Chaudhary 6 years, 8 months ago

0Thank You

ANSWER

use euclids division lemma to show that sqaure of any positive integer is either of form 3m , 3m+1 , for some integer m

Posted by Mahendar Singh 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 8 months ago

let us take, 'x'= 3q , 3q+1, 3q+2
when, x=3q
  x² = (3q) ²
   x² = 9q²
  x²  = 3(3q²)
we see that 3q²= m
so we have done the first equation 3m

when , x=3q+1
x²= (3q+1)² [since, (a+b)² = a²+2ab+b²]
   x²= 9q²+6q+1
x²= 3(3q+2q)+1
in this we see that 3q+2q= m
therefore, this satisfy the equation m+1

0Thank You

ANSWER

What is the maximum value of Sin thita?

Posted by Ankit Kumar 6 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Mahira Sharma 6 years, 8 months ago

realy

0Thank You

Puja Sahoo 6 years, 8 months ago

0Thank You

Esha Pal 6 years, 8 months ago

1Thank You

ANSWER

Find the greatest number of four digits which is exactily divisible by 15 ,24 and 36

Posted by S Devil 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Raj Kumar Raj 6 years, 8 months ago

first find lcm of 15 24and 36 and then divide by that number to 9999(greatest four digit number) then get remainder and substract from 9999 Hence that number will divide 15 24 and 36.

0Thank You

ANSWER

Prove that if x and y are both odd positive integer then x×x+y×y is even but not divisible by 4

Posted by Rahul 0941D 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Since x and y are odd positive integers, Then it should be in the form of 2x+1 (where x is a positive integer)
Let x = 2m + 1 and y = 2n + 1 ( where m and n positive integers)
Now x² + y²
= (2m + 1)² + (2n + 1)²

= 4m² + 4m + 1 + 4n² + 4n + 1

= 4(m² + n² + m + n) + 2 ....... (1)

from (1) we get

x² + y² = 2 {m² + n² + m + n) + 1} = 2t (t = 2(m² + n² + m + n) + 1 is a positive integer

Therefore it is clear that {tex}x^2+y^2{/tex} is an even number but not divisible by 4.

0Thank You

ANSWER

Prove that if x and

Posted by Rahul 0941D 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

$N€H!L J@@T ? 6 years, 8 months ago

Age

0Thank You

ANSWER

If the HCF of 152 and 272 is expressible in the form 272x8+152x find x

Posted by Yash Khalse 2 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

On applying the Euclid’s division lemma to find HCF of 152, 272, we get

{tex}272 = 152\times1 + 120{/tex}
Here the remainder = 0.
Using Euclid’s division lemma to find the HCF of 152 and 120, we get
{tex}152 = 120\times1 + 32{/tex}
Again the remainder = 0.
Using division lemma to find the HCF of 120 and 32, we get

{tex}120 = 32\times3 + 24{/tex}
Similarly,

{tex}32 = 24\times1 + 8{/tex}
{tex}24 = 8\times3 + 0{/tex}
HCF of 272 and 152 is 8.

272{tex}\times{/tex}8 + 152x = H.C.F. of the numbers
{tex}\Rightarrow {/tex} {tex}8 = 272\times8 + 152x{/tex}

{tex}\Rightarrow{/tex} {tex}8 - 272\times8 = 152x{/tex}
{tex}\Rightarrow 8(1- 272) = 152x{/tex}

{tex}\Rightarrow x = \frac { - 2168 } { 152 } = \frac { - 271 } { 19 }{/tex}

1Thank You

ANSWER

1+2+3+4+7+@+8

Posted by Rakesh Maheshwari 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the quadratic polynomial sum of whose zeroes is √3 and their product is (2/3).

Posted by Anuja Pandey 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is the 1/2 (x1(y2-y3)+x2(y3-y1)+x3(y1-y2)

Posted by Adarsh Raj 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Rocky Trickster 4 years, 9 months ago

this is the formula for area of triangle in coordinate geometry

3Thank You

ANSWER

Find zeroes of p(x)=4 underoot 3xsquare +5x-2 underoot 3 and verify the relationship between the zeroes and it's coefficient

Posted by Harsh Jha 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Anuja Pandey 6 years, 8 months ago

Here, 4√3×2√3=24 4√3xsq-5x-2√3 4√3sq-8x+3x-2√3 4√3x(x-2√3)+3(x-2√3) (X-2√3)(4√3x+3) X=2√3 ,3√3/12 Sum=2√3+(-3√3\12)=-5√3\12 =-b/a = -cofficient of x/cofficient of xsq Product=2√3×(-3√3\12)=-6√3\12= -2√3\4

2Thank You

ANSWER

(x+2)(2x-1) +3what is a dividend verify

Posted by Pooja Talwekar 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Pooja Talwekar 6 years, 8 months ago

2x square +3x+1

3Thank You

ANSWER

Find the quadratic polynomial whose zeroes are 2+root 3 and 2-root3

Posted by Navee .... 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

State where( underoot 6+underoot 9) is rational or irrational

Posted by Asha Joshi 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Asha Joshi 6 years, 8 months ago

Let root 6 + root 9 V rational root 9 equal to 3 root 6 + 3 equal to P by Q suppose P and Q have a common factor other than one root 6 + 3 equal to a upon B where A and B are co primes root 6 equal to a upon B + 3 root 6 equal to a + 3 B upon B since A and B are integers we get a + 3 B upon B is rational root 6 is rational but this contradict fact that root 6 is irrational this contradiction arise because of incorrect assumption that root 6 + root 3 is irrational hence root 6 + 3 is irrational

0Thank You

ANSWER

Can i get questions of chapter 3 from ncert Exampler

Posted by Sagar Singh 6 years, 8 months ago

CBSE > Class 10 > Mathematics