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4 x + 3 Y is equals to 2 and 7 x + 2 Y is equals to 1 solve the equation by substitution method

Posted by Samreen Ansari 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Solve 3x-5y=4

Posted by Tanushka Reddy 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Here given equations are
2x - y = 5 ..........(i)
3x - 5y = 4 ..............(ii)
Multiplying equation (i) by 3, we get
3 {tex}\times{/tex} (2x - y = 5)
{tex}\Rightarrow{/tex} 6x - 3y = 15 ...........(iii)
Multiplying equation (ii) by 2 , we get
2 {tex}\times{/tex} (3x - 5y = 4)
{tex}\Rightarrow{/tex} 6x - 10y = 8 ............(iv)
Subtracting equation (iv) from (iii), we get

{tex}\Rightarrow{/tex} y = 1
Put y = 1, equation (i) becomes
2x - 1 = 5
{tex}\Rightarrow{/tex} 2x = 6
{tex}\Rightarrow{/tex} x = 3
{tex}\therefore{/tex} x = 3, y = 1 is the solution of given system of equations.

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Represent 1+root 9.5 on number line

Posted by Abhishek Dwivedy 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Write whether every positive integer can be of the form 4q + 2 where q is an integer . Justify your answer.

Posted by Khyati Khandelwal 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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900000000000000000*45585556525845657/8556865455885+8565556545885225-856855585568425#552644555426542*55

Posted by Ved Patel 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

.... ♥ 6 years, 8 months ago

????

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Given that LCM(26,169)=338 write hcf (26,169)

Posted by Suruchirai Rai 6 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Nishant Kumar 6 years, 8 months ago

Hcf=product of given two no.s÷lcm 26×169÷338=13

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Vanshika Verma 6 years, 8 months ago

The answer will be LCM=338 HCF=? One number=26 Other number=169 LCM×HCF=Product of two numbers 338×HCF=26×169 HCF=26×169/338 HCF=13

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What is the formula

Posted by Atharva Parab 6 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Aleena Bi 6 years, 8 months ago

Kiska formula??

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Thanks Ki Baarish ........???? 6 years, 8 months ago

Not abhi abhi 1 month ago....?

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Solve these by quadratic formula. a²b²x²+b²x-a²x-1=0 x-1/x-2+x-3/x-4=10/3

Posted by Vanshika Verma 6 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Jansi Sabharwal 6 years, 8 months ago

Sorry for posting this I understand

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Jansi Sabharwal 6 years, 8 months ago

Hey kanika is there = only between the 2 equation

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To stick a shirt 2 m 15 cm cloth is needed out of 40 m cloth how many shirts can stitched and how much cloth with remain

Posted by Santosh Sahu 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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x-a/x-b +x-b/x-a = a/b + b/a.

Posted by Aman Anshuman 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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(18x)³

Posted by Vishal Vithalani 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Govind Ballabh 6 years, 8 months ago

(18x)^3=(18)^3×x^3=5832x^3

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Factorise x^6+18x^3+1

Posted by Vishal Vithalani 6 years, 8 months ago

CBSE > Class 10 > Mathematics

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5x/3+2/5=1

Posted by Manjyot Singh 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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If the HCF of 210 and 55 is expressible in the form 210 multiply 5 add 55 y , find y

Posted by Ritika Sharma 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 8 months ago

Let us first find the HCF of 210 and 55.

Applying Euclid division lemna on 210 and 55, we get

210 = 55 × 3 + 45

55 = 45 × 1 + 10

45 = 4 × 10 + 5

10 = 5 × 2 + 0

We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.

∴ 5 = 210 × 5 + 55y

⇒ 55y = 5 - 1050 = -1045

∴ y = -19

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If the diagonal of a cube is 3 cm . Then find its length

Posted by Jasmita Bellana 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhanushray Gupta 6 years, 8 months ago

3into3^1/2/3

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Term 1 ka syllabus kya hai What is the syllabus of term 1 2019 2020

Posted by Chandan Gupta 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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What is the lenth of a cylinder

Posted by Ayush Sharma 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Thanks Ki Baarish ........???? 6 years, 8 months ago

Hey Ayush here is ur answer!! The diameter, or the distance across a cylinder that passes through the center of the cylinder is 2R (twice the radius). The surface area of an open ended cylinder.....?

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Is Anyone have Coupon, promo Code ???

Posted by Hema Kashyab 5 years, 9 months ago

CBSE > Class 10 > Mathematics

4 answers

Aleena Bi 6 years, 8 months ago

Nooo?

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.... ♥ 6 years, 8 months ago

Sorry...me*

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.... ♥ 6 years, 8 months ago

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Hema K 6 years, 8 months ago

No??

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Write the degree of polynomial x+ 3/x =x²

Posted by Indu Goel 6 years, 8 months ago

CBSE > Class 10 > Mathematics

6 answers

Pearl Kayastha 6 years, 8 months ago

Take the LCM of x and3/x and cross multiply the equation we will get tge cubic polynomial with degree 3.

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Aleena Bi 6 years, 8 months ago

Hiii Indu ..... The degree of this polynomial is 2 and it's called quadratic polynomial...?

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Pearl Kayastha 6 years, 8 months ago

Answer is 3

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Bhanushray Gupta 6 years, 8 months ago

0Thank You

Thanks Ki Baarish ........???? 6 years, 8 months ago

Ryt Honey remember me?

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Vimla Devi 5 years, 9 months ago

First you tell me , Is it a polynomial?

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What is euclids divisiom lemma?

Posted by Last Bencher 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 8 months ago

For a pair of given positive integers ‘a’ and ‘b’, there exist unique integers ‘q’ and ‘r’ such that

`a=bq+r`, where `0≤r<b`

Explanation:

Thus, for any pair of two positive integers a and b; the relation

`a=bq+r`, where `0≤r<b`

will be true where q is some integer

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In the AP if the 12th term is - 13 and the sum of its first four terms is 24 find sum of first 10 term

Posted by Shweta Raghu 6 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Aastha .? 6 years, 8 months ago

a+11d=-13 ..............(i)., and 4a+6d=24.........(ii),............using elimination method.... We get, d= -2 and a=9 ......................... . .... put these value in Sn= n/2(2a+(n-1)d.................... S10= 5(2×9 + 9×(-2)).=5×0..................................... So,, S10=0

2Thank You

Vimla Devi 6 years, 8 months ago

Jeero , zzzzeeeeerrroooo 000000

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Aastha .? 6 years, 8 months ago

Correct ans is 0...

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Find the HCF of 1965 and 2096 by Euclids division algoritham

Posted by Anitha B S 6 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Vimla Devi 6 years, 8 months ago

Ryt aditi

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Thanks Ki Baarish ........???? 6 years, 8 months ago

The Hcf of 1965 &2096 is 131.

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Vimla Devi 6 years, 8 months ago

131

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Give me 1st chapter

Posted by Abinash Gaan 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Why is maths so tough

Posted by Varinder Sidhu 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Kumar Sharma 6 years, 8 months ago

Maths is not tough if you practice it daily

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How to solve y+4=0 by graphical methods and how to find value of x ??

Posted by Deepak Godara 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Solve by elimination method 10/x+y=4 ; 15/x+y-5/x-y=n

Posted by Jayesh Wagh 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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X ki power 3 + 2 x ki power 2- 11 x - 12 divide by -1

Posted by Manisha Takuli 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Aleena Bi 6 years, 8 months ago

Hiii manisha ......... If p(x)=x³+2x²-11x-12....& g(x)=-1 ........on solving by division method .....we got .... q(x)=-x³-2x²+11x+12.......& r(x)=0

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Find HCF and LCM of a and b for the number a=2^5 × 3^7× 5^2 × 7 and b=2^3 × 5^2 × 5^6 ×11.Also check if HCF (a,b) × LCM (a,b)=a×b

Posted by Harprit Kaur 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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If a= 2n + 13, b= n+ 7 where n is a natural number then hcf of a and b is A) 2. B) 1. C) 4. D) 3

Posted by V Charlene 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Taking different values of n, we find that A and B are co-prime.
When {tex}n = 1, A =1 5, B = 8{/tex}
When {tex}n = 2, A = 17, B = 9{/tex}
When {tex}n = 3, A = 19, B = 10{/tex} and so on....
Therefore, {tex}HCF = 1{/tex}

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If x=y then find value of a and b in polynomial ax+by=10

Posted by Krishna Chadha 6 years, 8 months ago

CBSE > Class 10 > Mathematics