CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

The given equations are
{tex}6x + 5y = 7x + 3y + 1 = 2(x + 6y -1){/tex}
Therefore,we have
{tex}6x + 5y = 2(x + 6y -1){/tex}
{tex}6x + 5y = 2x + 12y - 2{/tex}
{tex}6x - 2x + 5y -12y = -2{/tex}
{tex}4x - 7y = -2 {/tex}......(i)
Also,
{tex}7x + 3y + 1 = 2(x + 6y - 1){/tex}
{tex}7x + 3y + 1= 2x + 12y -2{/tex}
{tex}7x - 2x + 3y -12y = -2 -1{/tex}
{tex}5x - 9y = -3 {/tex}.........(ii)
Multiplying (i) by 9 and (ii) by 7, we get
{tex}36x - 63y = -18{/tex} ......(iii)
{tex}35x - 63y = -21{/tex} .....(iv)
Subtracting (iii) and (iv),we get
{tex}x = 3{/tex}
Substituting x = 3 in (i),we get
{tex}\Rightarrow4 \times 3 - 7 y = - 2\\ \Rightarrow - 7 y = - 2 - 12{/tex}
{tex}\Rightarrow-7y = -14{/tex}
{tex}\Rightarrow{/tex}y = 2
{tex}\therefore{/tex} Solution is x = 3, y = 2

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If the HCF of 210 and 55 is expressible in the form 210×5+55y then find y..

Posted by Vivek Pal 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Devagalla Satyanarayana 6 years, 8 months ago

210=55×3+45...........(1) 55=45×1+10..............(2) 45=10×4+5................(3) 10=5×2+0 So here HCF (210,55)=5 From equation (3), 5 can be written as 5=45—10×4..........(4) Now from (2) 10=55—45×1,now this value substitute in equation (4) in place of 10 Then we get, 5=45—(55—45×1)×4 After simplifying we will get 5=45×5—55×4.......(5) Now,from (1) 45=210—55×3, this value substitute in equation (5) 5=(210—55×3)×5—55×4, after simplifying we will get 5=210×(5)+55×(-19)....Now this one compare with given equation that 5=210×5+55×x Then X=–19 is the answer

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55x +67y =311 67x +55y =299

Posted by Abhi Khatri 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Vivek Pal 6 years, 8 months ago

For this type of questions. We simple first + the both terms and then substract the both equation. So we get 2 short equations. After that solve the both equation by eliminating method or substitution method. This is only work when coffecient of x is equal to coffecient of y in 2nd equation and coffecient y in 1st equation is equal to coffecient of x in 2nd equation. Hope you like the answer.

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Find two consecutive positive integers, sum of whose square is 365

Posted by Anand Rawat 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Krishna Singla 6 years, 8 months ago

13 and 14

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Find the hcf of the samllest composite prime number

Posted by Shubham Verma 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

The smallest prime number is 2 and the smallest composite number is {tex}4=2^2{/tex}
Hence the required HCF (4 , 2) = 2

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Who is laks****@***** ...jo b h wo sirf thanks kr rha h ...

Posted by Miss. Chocolover..??? 6 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Rohit Sahani ? 6 years, 8 months ago

Don't know

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Bestie Sahiba ??? 6 years, 8 months ago

Pata ni

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Sb gye ke ....

Posted by Miss. Chocolover..??? 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Rohit Sahani ? 6 years, 8 months ago

Not

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A man is seven by two times as old old as his son if the sum of square of their age is 13 25 find the age of the father and son

Posted by Harsh Agarwal 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Hii....koi h. ...

Posted by Miss. Chocolover..??? 6 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Miss. Chocolover..??? 6 years, 8 months ago

Riya

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Rowdy(Khushi)? ?Hk? 6 years, 8 months ago

Aapka name??...

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Miss. Chocolover..??? 6 years, 8 months ago

Khushi*

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Miss. Chocolover..??? 6 years, 8 months ago

Hii khishi

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Rowdy(Khushi)? ?Hk? 6 years, 8 months ago

Hii

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In right tri. ABC right angled at C if tan A =1 then verify that 2 sin A cos A=1

Posted by Sarbash Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

In {tex} \triangle A B C{/tex},
{tex}\tan A = 1{/tex}
{tex}\Rightarrow \quad \frac { B C } { A C } = 1{/tex}
{tex}\Rightarrow {/tex} BC = x and AC = x
Using Pythagoras theorem,
{tex}\Rightarrow A B ^ { 2 } = A C ^ { 2 } + B C ^ { 2 }{/tex}
{tex}\Rightarrow \quad A B ^ { 2 } = x ^ { 2 } + x ^ { 2 }{/tex}
{tex}\Rightarrow \quad A B = \sqrt { 2 } x{/tex}
{tex}\therefore \quad \sin A = \frac { B C } { A B } = \frac { x } { \sqrt { 2 } x } = \frac { 1 } { \sqrt { 2 } } \text { and } \cos A = \frac { A C } { \sqrt { 2 } x } = \frac { x } { \sqrt { 2 } x } = \frac { 1 } { \sqrt { 2 } } {/tex}

2 sin A cos A {tex}= 2 \times \frac { 1 } { \sqrt { 2 } } \times \frac { 1 } { \sqrt { 2 } } = 1{/tex}

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1253^1469-1258^1471

Posted by S Ali Hussain 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Shubham Verma 6 years, 8 months ago

,Trjdkdidnssmdjkdjskjdjdjjd

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The length of the shadow of tower standing on level plane is found to be 2y meters longer when the sun's altitude is 30°than when it was 45°.prove that the height of the tower is y(√3+1) meters

Posted by Anandita Sahoo 6 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Raunak ??? 6 years, 8 months ago

Ek aur sahoo !!

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Suna hai yaha par sabne laughing gass smell kar li hai ......kaho toh tear gass bhi spary kar du yaha .....hasna rona sab ek sath bada maza ayega ???

Posted by Raunak ??? 6 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Raunak ??? 6 years, 8 months ago

⛽⛽⛽⛽⛽⛽⛽tear gass spray ho rahi hai. ....

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Raunak ??? 6 years, 8 months ago

?kyo kya kehte ho ??

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Miss. Chocolover??❤️ 6 years, 8 months ago

????

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Yo Yo Anurag... ??? 6 years, 8 months ago

Sab pagla gye ho kya???

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(a+b)^3 +(b+c)^3 +(c+a)^3 -3(a+b) (b+c) (c+a)=2(a^3+b^3+c^3-3abc)

Posted by S K 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let a + b =x, b + c =y and c + a = z. Then,
(a + b)³ + (b + c)³ + (c + a)³ - 3(a + b)(b + c) (c + a)
= x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx)
= {(a + b) + (b + c) + (c + a)} {(a + b)² + (b + c)² + (c + a)²- (a + b)(b + c) - (b + c)(c + a) - (c + a) (a + b)}
= 2(a + b + c) {a² + b² + 2ab + b² + c² + 2bc + c² + 2ca + a²- (ab + ac + b²+ bc) - (bc + ba + c² + ca) - (ca + cb + a² + ab)}
= 2(a + b + c) (a² + b²+ c² - ab - bc - ca) = 2(a³ + b³ + c³ - 3abc)

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Trait is distungishing quality or characteristics to a person my grandson is about as many days is as many months as ion in ears my grandson my daughter and I to gather are 120 years can you tell me my age in years

Posted by Rajshaker H 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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5\3÷2=

Posted by Alen Rajan 6 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Hlo guys plz help me in this question what is electrolysis

Posted by Priyanshi Kushwaha 6 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Pm Madewar 6 years, 8 months ago

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Gaurav Seth 6 years, 8 months ago

Electrolysis is the process of chemical decomposition produced by passing an electric current through a liquid or solution containing ions.

The process is carried out in an electrolytic cell, an apparatus consisting of positive and negative electrodes held apart and dipped into a solution containing positively and negatively charged ions.