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Preeti Dabral 2 years, 1 month ago
f(x) = 4x2 + 4x - 3
⇒f(12)=4(14)+4(12)−3
= 1 + 2 - 3 = 0
and f(−32)=4(94)+4(−32)−3
= 9 - 6 - 3 = 0
∴12,−32are zeroes of polynomial 4x2 + 4x - 3.
Sum of zeroes = 12−32=−1=−44
=− Coefficient of x Coefficient of x2
Product of zeroes = (12)(−32)=−34
= Constant term Coefficient of x2
Verified.
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Preeti Dabral 2 years, 1 month ago
17×5×11×3×2+2×11=17×5×3×22+22
=22(17×5×3+1)
=22(255+1)=2×11×256 -----(i)
Equation (i) is divisible by 2, 11 and 256, so it has more than 2 prime factors.
∴ (17×5×11×3×2+2×11) is a composite number.
Payal Kumari Kushwaha 2 years, 1 month ago
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Preeti Dabral 2 years, 1 month ago
Height of the cylinder (h) = 14 cm,
Base diameter = 7 cm
⇒ Radius of the base of the cylinder (r) = 3.5 cm
Volume of the cylinder = πr2h
= 227×3.5×3.5×14
= 22 ×3.5 ×3.5×14
= 539 cm3
Radius of the conical holes (r1) = 2.1 cm,
Height of the conical holes (h1) = 4 cm,
volume of the conical hole =13πr21h1
=13×227×2.1×2.1×4
= 18.48 cm3
Volume of the two conical hole = 2 ×18.48
= 36.96 cm3
Volume of the remaining solid = Volume of the cylinder - Volume of two conical hole
= 539 - 36.96
= 502.04 cm3
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Ayush Singh 2 years, 1 month ago
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