CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

The number in the form of p/q where p is numerator and q is denominator is called fraction. & The number in the form of p/q where q≠0, is known as rational number.

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Mr Thunder 1 year, 9 months ago

same ...

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Strive not to be a success, but rather to be of value.

Posted by Mahir Kumar 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Mahir Kumar 1 year, 9 months ago

Strive not to be a success, but rather to be of value.

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Sum of the ages of father and the sonia 40 years. If father age is 3times that of his son then find their respective ages?

Posted by Abhinav Abhinav 1 year, 9 months ago

CBSE > Class 10 > Mathematics

4 answers

A B 1 year, 9 months ago

sorry son age =10

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A B 1 year, 9 months ago

sonia age =10 father age =30

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Vipan Kaur 1 year, 9 months ago

Let the Sonia age = x years AND his father age = 3 times the Sonia age = 3x According to our question , 3x + x = 40 4x = 40 X = 10 Therefore,Sonia age = 10 years And his father age = 3× 10 = 30 years

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Arnav Som 1 year, 9 months ago

Let son be x Father will be 3 x ATQ 3x+x=40 4x=40 x=10 Son - 10 years Father - 30 years

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The distance of the point (4,7) from the y-axis is

Posted by Rahul Prajapati 1 year, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

Atharv Wankhade 1 year, 9 months ago

7 is best anwer because (x,y)=(4,7) y=7 hence distance from y axis is 7

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Vaibhav Gupta 1 year, 9 months ago

Lol 4

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Vaibhav Gupta 1 year, 9 months ago

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Deepak Sharma 1 year, 9 months ago

4 unit

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Arnav Som 1 year, 9 months ago

4 units

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How to pass

Posted by Abell Thankachan 1 year, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

Ayush Mishra 1 year, 9 months ago

By study

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Deepak Sharma 1 year, 9 months ago

Study

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Ankush Pandey 1 year, 9 months ago

To using mobile

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Aniket Tanwar 1 year, 9 months ago

Study

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Shoumik Meow 1 year, 9 months ago

NCERT thoroughly

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D is midpoint on the side bc of triangle ABC such that ADC=bac show that ca2=cb.cd

Posted by Yash Malik 1 year, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

K. Hema 1 year, 9 months ago

Given, D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. In ΔADC and ΔBAC, ∠ADC = ∠BAC (Already given) ∠ACD = ∠BCA (Common angles) ∴ ΔADC ~ ΔBAC (AA similarity criterion) We know that corresponding sides of similar triangles are in proportion. ∴ ��=��CBCA=CACD ⇒ CA2 = CB.CD. Hence, proved.

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Abell Thankachan 1 year, 9 months ago

I don't know

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Shaurya made a map of his locality on a coordinate plane kartik house park OY

Posted by Yash Sahu 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Bilal Shaikh 1 year, 9 months ago

What is meaning of Pythagoras

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Shaurya made a map of his locality on a coordinate plane kartik's house park oy

Posted by Yash Sahu 1 year, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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SinA+cosecA2 +cosA + secA2 =7+tan2A+ cot2A

Posted by Aryan Sharma 1 year, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Renuka Sahoo 1 year, 9 months ago

=Sin²A+Cosec²A+2SinA.CosecA+Cos²A+Sec²A+2CosA.SecA =Sin²A+Cosec²A+Cos²A+Sec²A+4 =Sin²A+Cos²A+4+Cosec²A+Sec²A =1+4+Cosec²A+Sec²A =5+1+Cot²A+1+Tan²A =7+tan²A+Cot²A

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V R 1 year, 9 months ago

That is a wrong questions... Right questions is (SinA+cosecA)^2 +(cosA + secA)^2=(7+tan2A+ cot2A)

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What is cot

Posted by Sejal Yadav Yadav 1 year, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

V R 1 year, 9 months ago

It is a trigonometry ratio. Which is (cotA=cosA/sinA)

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Parth Yadav 1 year, 9 months ago

Trignometric ratio Cot= cos/sin

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How many terms are there in AP. 7,13,19,........205

Posted by Piyush Chhuria 1 year, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

Gautam Bansal 1 year, 9 months ago

Let an=205 , d =a2-a1=6 a+(n-1)d =205 7+(n-1)6=205 (n-1)6= 205-7 (n-1)6 =198 n-1 =198/6 n-1 =33 n=34 Ans.

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Aryan Sharma 1 year, 9 months ago

34 terms

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Ayush Garg 1 year, 9 months ago

7,13,19..........205 a=7 , d=13-7=19-13=6 an= a+(n-1)d 205=7+(n-1)6 (205-7)/6=n-1 198/6=n-1 33=n-1 34=n answer

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Manika Sharma 1 year, 9 months ago

7,13,19........205 a=7. d = 13 - 7 = 6. an = 205 an = a + (n -1) d 205 = 7 + ( n -1) 6 205 - 7 = (n -1) 6 198/6 = ( n - 1) 33 = ( n - 1) n = 34

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Jayant Khanna 1 year, 9 months ago

n = 34

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Prove that: (cosec- sin) (sec- cos) (tan- cos)= 1

Posted by Nandni Gupta 1 year, 9 months ago

CBSE > Class 10 > Mathematics

4 answers

A B 1 year, 9 months ago

after tan,it will be placed..

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A B 1 year, 9 months ago

Sorry, but this question is wrong. here it will be +cot on the place of -cos ....then you can solve it..

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Vivek Prajapati 1 year, 9 months ago

Tum 3 bracket mein cot kardo uske baad cosec ko sin mein sec ko cos mein aur tan ko cot mein kardo ho jayega girl

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Vivek Prajapati 1 year, 9 months ago

R u sure 3 bracket mein tan ke aage cos hoga ya cot

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Define Factor theorem of Arithmetic

Posted by Mohammad Amaan 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 9 months ago

In mathematics, factor theorem is used when factoring the polynomials completely. It is a theorem that links factors and zeros of the polynomial. According to factor theorem, if f(x) is a polynomial of degree n ≥ 1 and 'a' is any real number, then, (x-a) is a factor of f(x), if f(a)=0.

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49x + 51y =499 51x +49y =501

Posted by Malti Yadav 1 year, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Arham Jain 1 year, 9 months ago

Step. 1 add both eq. So we get , X+y=10 ...................................(I) Step. 2 substract eq 2 from 1 So, we get, X-y=1............................... (II) Now add both above eq So we get the value of x = 11/2 And value of y=9/2...

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Himanshi Yadav 1 year, 9 months ago

Step. 1 add both eq. So we get , X+y=10 ............. (I) Step. 2 substract eq 2 from 1 So, we get, X-y=1.......... (II) Now add both above eq So we get the value of x = 11/2 And value of y=9/2...

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Important questions for boards

Posted by Krishnakshi Sharma 1 year, 9 months ago

CBSE > Class 10 > Mathematics

4 answers

Vipan Kaur 1 year, 9 months ago

First complete all NCERT ,then solve sample papers and then previous year question paper + sample paper for board exams

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Dev Sharma 1 year, 9 months ago

Questions bank on cbse site

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Nayra Shrivastava 1 year, 9 months ago

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Aleeza Siddique 1 year, 9 months ago

Previous years question papers

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If angle 1 = angle 2 and ∆NSQ congrent to ∆MTR then prove that ∆PTS congrent to ∆PRQ

Posted by Mayur Patel 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 9 months ago

Since {tex}\triangle {/tex} NSQ {tex}\cong{/tex} {tex}\triangle {/tex}MTR
{tex}\therefore {/tex} {tex}\angle{/tex} SQN = {tex}\angle{/tex} TRM
{tex}\Rightarrow {/tex} {tex}\angle{/tex} Q= {tex}\angle{/tex} R(in {tex}\triangle {/tex}PQR)
{tex}\angle Q{/tex} = 90^o- {tex}\frac{1}{2}\angle P{/tex}
Again 1 = {tex}\angle{/tex} 2 [given in {tex}\triangle {/tex} PST](Isosceles property)
{tex}\therefore {/tex} {tex}\angle{/tex} 1= {tex}\angle{/tex} 2 = {tex}\frac{1}{2}\left( {{{180}^ \circ } - \angle P} \right){/tex}
{tex}= {90^ \circ } - \frac{1}{2}\angle P{/tex}
Thus, in {tex}\triangle {/tex}PTS and {tex}\triangle {/tex}PRQ
{tex}\angle{/tex} 1 = {tex}\angle{/tex} Q [Each = 90° - {tex}\frac{1}{2}\angle P{/tex}]
{tex}\angle{/tex} 2 = {tex}\angle{/tex} R, {tex}\angle{/tex} P= {tex}\angle{/tex} P(Common)
{tex}\triangle {/tex} PTS {tex}\cong{/tex} {tex}\triangle {/tex}PRQ

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if alpha and beeta are the zeroes of p(x)=3x2+2x+1,find the polynomial whose zeroes are 1-alpha/1+alpha and 1-beeta/1+beeta

Posted by Goransh Upadhyay 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 9 months ago

Since {tex}\alpha \text { and } \beta{/tex} are the zeroes of polynomial 3x² + 2x + 1.
Hence, {tex}\alpha + \beta = - \frac { 2 } { 3 }{/tex}
and {tex}\alpha \beta = \frac { 1 } { 3 }{/tex}
Now, for the new polynomial,
Sum of zeroes = {tex}\frac { 1 - \alpha } { 1 + \alpha } + \frac { 1 - \beta } { 1 + \beta }{/tex}
{tex}= \frac { ( 1 - \alpha + \beta - \alpha \beta ) + ( 1 + \alpha - \beta - \alpha \beta ) } { ( 1 + \alpha ) ( 1 + \beta ) }{/tex}
{tex}= \frac { 2 - 2 \alpha \beta } { 1 + \alpha + \beta + \alpha \beta } = \frac { 2 - \frac { 2 } { 3 } } { 1 - \frac { 2 } { 3 } + \frac { 1 } { 3 } }{/tex}
{tex}\therefore{/tex} Sum of zeroes = {tex}\frac { 4 / 3 } { 2 / 3 } = 2{/tex}
Product of zeroes = {tex}\left[ \frac { 1 - \alpha } { 1 + \alpha } \right] \left[ \frac { 1 - \beta } { 1 + \beta } \right]{/tex}
{tex}= \frac { ( 1 - \alpha ) ( 1 - \beta ) } { ( 1 + \alpha ) ( 1 + \beta ) }{/tex}

{tex}=\frac{1-(\alpha+\beta)+\alpha \beta}{1+(\alpha+\beta)+\alpha \beta}{/tex}
{tex}{/tex} {tex}={/tex} {tex}\frac { 1 + \frac { 2 } { 3 } + \frac { 1 } { 3 } } { 1 - \frac { 2 } { 3 } + \frac { 1 } { 3 } } = \frac { \frac { 6 } { 3 } } { \frac { 3 } { 3 } } = 3{/tex}
Hence, Required polynomial = x² - (Sum of zeroes)x + Product of zeroes
= x² - 2x + 3

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The sum of first n terms of an AP is 210 and sum of its first (n-1) terms is 171.if the first term is 3 then write the arithmetic progression

Posted by Nayana M S 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 9 months ago

To find the AP if the sum of first n terms of arithmetic progression is 210 and sum of its first (n-1) terms is 171. If the first term is 3 .

As we know that if AP has n terms,then after removing (n-1) terms,we are left with the last term.

ACF, last term is 210-171

l= 39

a= 3

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Two poles, 30 feet and 50 feet tall, are 40 feet apart and perpendicular to the ground. The poles are supported by wires attached from the top of each pole to the bottom of the other, as in the figure. A coupling is placed at C where the two wires cross. (i) What is the horizontal distance from C to the taller pole? (ii) How high above the ground is the coupling ? (iii) How far down the wire from the smaller pole is the coupling ?

Posted by Manvi Sahay 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Yashika Yashu 1 year, 9 months ago

Fight against

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A cone of height 24 cm and radius of base 6 cm is made up of modelling clay a child reshape it in the form of sphere find the radius of the sphere

Posted by Youcancallmesam Shami 1 year, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Manish Verma 1 year, 9 months ago

6 cm is the right answer

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Arya Jain 1 year, 9 months ago

Vol of cone = vol of sphere 1/3πr^h = 4/3πr^3

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What is the zero of the polynomial 2x-4

Posted by Sudha Kashyap 1 year, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

Vivek Prajapati 1 year, 9 months ago

-2;+2

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Sruti .S 1 year, 9 months ago

Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
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Mukul Singh 1 year, 9 months ago

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Taniya . 1 year, 9 months ago

Therefore, the zero of the polynomial 2x - 4 is 2.

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Deepak Sharma 1 year, 9 months ago

Only one

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Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
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Posted by Sudha Kashyap 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Shrikanth Madki 1 year, 9 months ago

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If I study Rd Sharma and rs Agarwal can I score a+

Posted by Nizin Nizin 1 year, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

Aditya Yadav 1 year, 9 months ago

Pass ho jauga Mai

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Adiba Mansuri 1 year, 9 months ago

After solving rd Sharma, solve previous year papers...

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Sejan Suhail 1 year, 9 months ago

Tuhamar fail hona paka hai🤣🤣

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Sahil Rawat 1 year, 9 months ago

After doing Rd sharma Solve sample paper

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Tarun Singh Rathour 1 year, 9 months ago

Yes you can but you have to study with concentration

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5-√3is a irrational number

Posted by Rocky ☯️ 1 year, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Taniya . 1 year, 9 months ago

Let us assume, 5−√3 is a rational number ⇒5−√3=qp, where p,q∈z,q=0 5−qp=√3 ⇒q5q−p=√3 ⇒√3 is a rational number ∵q5q−p is rational but √3 is not a rational number. This gives us a contradiction. ∴ our assumption that 5−√3 is a rational number is wrong ⇒5−√3 is an irrational number.

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Aditya Verma 1 year, 9 months ago

Let we assume that 5-√3 is rational.so we can write is on p/q where pq are coprime and q not equal to 0 5-√3=p/q √3=p/q-5 So p/q is integers so therefore √3 is rational But we know the fact that √3 is irrational Our assumption get wrong so therefore 5-√3 is irrational Hence proved....

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A floor designed is made by 2 dimensional geometrical figures Find the coordinates of mid point of PP' Find the distance of point P from y axis

Posted by Preeti Fulara 1 year, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Basavachetan Biradar 1 year, 9 months ago

😅🤣😂

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Naman Sharma 1 year, 9 months ago

Bro pls ask right questions

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Mukesh Chaudhary 1 year, 9 months ago

😆😆

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Tan A÷1-cotA + cotA÷1-tanA. =. 1+secAcosecA

Posted by Priyansh Bairwa 1 year, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Vinita Chauhan 1 year, 9 months ago

Sin A/cosA÷sinA-cosA/sinA +cosA/sinA÷cosA-sinA/cosA =sin²A÷cos(sin-cos)+cos²÷sin(cos-sin) Rest you can solve

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If the sum of first m term of an a.p is the same as the sum it's first n term show that the sum of its first m+n term is zero

Posted by Ashutosh Singh 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 8 months ago

Let a be the first term and d be the com m on difference of the given A.P. Then,
S_m= S_n
{tex}\Rightarrow \frac{m}{2}{/tex}{2a + (m - 1) d} = {tex}\frac{n}{2}{/tex}{2a + (n - 1) d}
{tex}\Rightarrow{/tex} 2a(m - n) + {m(m - 1) - n(n - 1)} d = 0
{tex}\Rightarrow{/tex} 2a(m - n) + [(m²- n²) - (m - n)d = 0
{tex}\Rightarrow{/tex} (m - n){2a + (m + n - 1)d = 0
{tex}\Rightarrow{/tex} 2a + (m + n - 1)d = 0 [{tex}\because{/tex} m - n {tex}\ne{/tex} 0] ...(i)
{tex}\therefore {/tex} S_m+n= {tex}\frac{m+n}{2}{/tex} {2a + (m + n - 1) d} = {tex}\frac{m+n}{2} \times {/tex} 0 = 0 [Using (i)]
Hence proved on basis of above equation.