Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Gunjan Tanwar 2 years, 1 month ago
- 2 answers
Posted by Digrik Singh 2 years, 1 month ago
- 2 answers
Omya Aryan 2 years, 1 month ago
Posted by Mahir Kumar 2 years, 1 month ago
- 1 answers
Posted by Abhinav Abhinav 2 years, 1 month ago
- 4 answers
Vipan Kaur 2 years, 1 month ago
Arnav Som 2 years, 1 month ago
Posted by Rahul Prajapati 2 years, 1 month ago
- 5 answers
Atharv Wankhade 2 years, 1 month ago
Posted by Abell Thankachan 2 years, 1 month ago
- 5 answers
Posted by Yash Malik 2 years, 1 month ago
- 2 answers
K. Hema 2 years, 1 month ago
Posted by Yash Sahu 2 years, 1 month ago
- 1 answers
Posted by Yash Sahu 2 years, 1 month ago
- 0 answers
Posted by Aryan Sharma 2 years, 1 month ago
- 2 answers
Renuka Sahoo 2 years, 1 month ago
V R 2 years, 1 month ago
Posted by Sejal Yadav Yadav 2 years, 1 month ago
- 2 answers
Posted by Piyush Chhuria 2 years, 1 month ago
- 5 answers
Gautam Bansal 2 years, 1 month ago
Ayush Garg 2 years, 1 month ago
Manika Sharma 2 years, 1 month ago
Posted by Nandni Gupta 2 years, 1 month ago
- 4 answers
A B 2 years, 1 month ago
Vivek Prajapati 2 years, 1 month ago
Posted by Mohammad Amaan 2 years, 1 month ago
- 1 answers
Preeti Dabral 2 years, 1 month ago
In mathematics, factor theorem is used when factoring the polynomials completely. It is a theorem that links factors and zeros of the polynomial. According to factor theorem, if f(x) is a polynomial of degree n ≥ 1 and 'a' is any real number, then, (x-a) is a factor of f(x), if f(a)=0.
Posted by Malti Yadav 2 years, 1 month ago
- 2 answers
Arham Jain 2 years, 1 month ago
Himanshi Yadav 2 years, 1 month ago
Posted by Krishnakshi Sharma 2 years, 1 month ago
- 4 answers
Vipan Kaur 2 years, 1 month ago
Nayra Shrivastava 2 years, 1 month ago
Few rules to keep homework help section safe, clean and informative.
- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.
Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Posted by Mayur Patel 2 years, 1 month ago
- 1 answers
Preeti Dabral 2 years, 1 month ago
Since △ NSQ ≅ △MTR
∴ ∠ SQN = ∠ TRM
⇒ ∠ Q= ∠ R(in △PQR)
∠Q = 90o - 12∠P
Again 1 = ∠ 2 [given in △ PST](Isosceles property)
∴ ∠ 1= ∠ 2 = 12(180∘−∠P)
=90∘−12∠P
Thus, in △PTS and △PRQ
∠ 1 = ∠ Q [Each = 90° - 12∠P]
∠ 2 = ∠ R, ∠ P= ∠ P(Common)
△ PTS ≅ △PRQ
Posted by Goransh Upadhyay 2 years, 1 month ago
- 1 answers
Preeti Dabral 2 years, 1 month ago
Since α and β are the zeroes of polynomial 3x2 + 2x + 1.
Hence, α+β=−23
and αβ=13
Now, for the new polynomial,
Sum of zeroes = 1−α1+α+1−β1+β
=(1−α+β−αβ)+(1+α−β−αβ)(1+α)(1+β)
=2−2αβ1+α+β+αβ=2−231−23+13
∴ Sum of zeroes = 4/32/3=2
Product of zeroes = [1−α1+α][1−β1+β]
=(1−α)(1−β)(1+α)(1+β)
=1−(α+β)+αβ1+(α+β)+αβ
= 1+23+131−23+13=6333=3
Hence, Required polynomial = x2 - (Sum of zeroes)x + Product of zeroes
= x2 - 2x + 3
Posted by Nayana M S 2 years, 1 month ago
- 1 answers
Preeti Dabral 2 years, 1 month ago
To find the AP if the sum of first n terms of arithmetic progression is 210 and sum of its first (n-1) terms is 171. If the first term is 3 .
As we know that if AP has n terms,then after removing (n-1) terms,we are left with the last term.
ACF, last term is 210-171
l= 39
a= 3
Posted by Sudha Kashyap 2 years, 1 month ago
- 5 answers
Sruti .S 2 years, 1 month ago
Few rules to keep homework help section safe, clean and informative.
- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.
Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Posted by Sudha Kashyap 2 years, 1 month ago
- 1 answers
Posted by Nizin Nizin 2 years, 1 month ago
- 5 answers
Adiba Mansuri 2 years, 1 month ago
Tarun Singh Rathour 2 years, 1 month ago
Posted by Rocky ☯️ 2 years, 1 month ago
- 2 answers
Taniya . 2 years, 1 month ago
Aditya Verma 2 years, 1 month ago
Posted by Priyansh Bairwa 2 years, 2 months ago
- 1 answers
Vinita Chauhan 2 years, 1 month ago
Posted by Ashutosh Singh 2 years ago
- 1 answers
Preeti Dabral 2 years ago
Let a be the first term and d be the com m on difference of the given A.P. Then,
Sm = Sn
⇒m2{2a + (m - 1) d} = n2{2a + (n - 1) d}
⇒ 2a(m - n) + {m(m - 1) - n(n - 1)} d = 0
⇒ 2a(m - n) + [(m2 - n2) - (m - n)d = 0
⇒ (m - n){2a + (m + n - 1)d = 0
⇒ 2a + (m + n - 1)d = 0 [∵ m - n ≠ 0] ...(i)
∴ Sm+n = m+n2 {2a + (m + n - 1) d} = m+n2× 0 = 0 [Using (i)]
Hence proved on basis of above equation.
Posted by Mayur Raj 2 years, 2 months ago
- 2 answers
Taniya . 2 years, 1 month ago
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Dushyant Shukla 2 years, 1 month ago
0Thank You