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Please send answer in _L_X_ legend Who not study maths

Posted by Arman Singh 1 year, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Any one who not study maths

Posted by Arman Singh 1 year, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the LCM and HCF a) 25 , 17 , 34

Posted by _L _X Legend 1 year, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Itz__Kritika Koli 🖤 1 year, 8 months ago

(1) The prime factorisation of 25 are 5 and 5. (2) 17 is a prime factor. (3) The prime factors of 34 are 2 and 17. (4) Build a prime factor table :- Determine the maximum number of times each prime factor (2,5,17) occurs in the factorization of the given numbers: Number 25 17. 34. Max occ Of Prime Factor 2. 0. 0. 1. 1 5. 2. 0. 0. 2 17. 0. 1. 1. 1 The prime factors 2 and 17 occur one time, while 5 occurs more than once. (5) Calculate the LCM The least common multiple is the product of all factors in the greatest number of their occurance. LCM = 2×5×5×17 LCM = 2×5²×17 LCM = 850 The least common multiple of 25, 17 and 34 is 850.

Harshita Saini 1 year, 8 months ago

HCF=17 LCM=850

Mohamed Fahith 1 year, 8 months ago

I dont know

ANSWER

Subtract 25x -10 from 55x-12 with proper steps

Posted by Antony Raj 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Karan Raj 1 year, 8 months ago

55x-12-(25x-10)=0 55x-12-25x+10=0 30x-2=0 30x=2 X=2/30 X=1/15 !!!!

ANSWER

How was social paper ?

Posted by Deadly Deadly 1 year, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Harshita Saini 1 year, 8 months ago

Good 👍 👍

Richa Mishra 1 year, 8 months ago

I was good as compared to other subjects

Itz__Kritika Koli 🖤 1 year, 8 months ago

Moderately difficult

ANSWER

those student who has selected maths standard in class 10th will be in which category in class 11th commerce or Science

Posted by Prathamesh Kharade 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Shanu Yadav 1 year, 8 months ago

Science

Itz__Kritika Koli 🖤 1 year, 8 months ago

I selected maths standard in class 10th...and I choose commerce in class 11th... What uhh will choose in class 11th commerce or science

ANSWER

Prove that √5 is an irrational no

Posted by Ayush Kumar Mehta 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashitha Saran 1 year, 8 months ago

Assuming √5 as a rational number, i.e., can be written in the form a/b where a and b are integers with no common factors other than 1 and b is not equal to zero. It means that 5 divides a2. This has arisen due to the incorrect assumption as √5 is a rational number. Therefore, √5 is irrational.

ANSWER

What is the square of 984615

Posted by Sk Siddiq 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Itz__Kritika Koli 🖤 1 year, 8 months ago

Square of 984615 is....969466698225

ANSWER

If two positive integers a and b are written as a = x^3y^2 and b=xy^3,where x and y are prime numbers then HCF( a,b )

Posted by Nimesh Jyoti Sahu 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Rithika S 1 year, 8 months ago

A=X×X×X×Y×Y B=X×Y×Y×Y HCF=XY^2

Rithika S 1 year, 8 months ago

HCF =xy^2

ANSWER

Number system ex 1.1

Posted by Geetha Sriram 1 year, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove that root3 is an irrational number.

Posted by Akshay Kumar 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Harshita Saini 1 year, 8 months ago

Let √3 is rotational number :- √3 = p/q are co prime integers & q is not equal to 0 = 3 = p²/q² = P² = 3 × q²......(1) 3 is a factor of p² = 3 is a factor of p...(2) So p=3×m [m is any integer] (let) :- form (1) 9m²=3q² = q²=3m² :- 3 is a factor of q² = 3 is a factor of q.....(3) From (2) and (3) 3 is a common factor of both p&q It contradicts our supposition that p&q are co prime integers. Hence are supposition is wrong. :- √3 is irrational Hence proved

Itz__Kritika Koli 🖤 1 year, 8 months ago

Let √3 is rotational number :- √3 = p/q are co prime integers & q is not equal to 0 = 3 = p²/q² = P² = 3 × q²......(1) 3 is a factor of p² = 3 is a factor of p...(2) So p=3×m [m is any integer] (let) :- form (1) 9m²=3q² = q²=3m² :- 3 is a factor of q² = 3 is a factor of q.....(3) From (2) and (3) 3 is a common factor of both p&q It contradicts our supposition that p&q are co prime integers. Hence are supposition is wrong. :- √3 is irrational Hence proved

ANSWER

Make a Quadritic polynomial equation whose root is 7,-2

Posted by Navleen Kaur 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Megha Tanwar 1 year, 8 months ago

Sum of roots =-b\a 7+(-2)=-5/1 Product of zeoes = c/a 7×-2=-14/1 So quadratic equation Ax^2-bX+c=0 1x^+5x-14=0

Omya Aryan 1 year, 8 months ago

x²-5x-14=0

ANSWER

Splitting method for 3x square-3root2 x+1

Posted by Lalith Roshan 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashitha Saran 1 year, 8 months ago

3x^2-3√3x+2 = 3x^2-√3x-2√3x+2 =√3x(√3x-1)-2(√3x-1) =(√3x-1)(√3x-2) 3x^2-3√3x+2 = 0 so (√3x-1)(√3x-2)=0 (√3x-1)=0 √3x=1 x=1/√3 (√3x-2)=0 √3x=2 x=2/√3x

ANSWER

5xsquare + 3x +k find the value of k is

Posted by Abid Ali 1 year, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Itz__Kritika Koli 🖤 1 year, 8 months ago

This ques..is incomplete

Tilak Raj 1 year, 8 months ago

There should be another equation or the zeros of the polynomial

Tilak Raj 1 year, 8 months ago

Bro ques is incomplete

ANSWER

Assume √3 is a rational

Posted by Aakash .B Aakash.B 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Sabari Ram 1 year, 8 months ago

Assume √3 as irrational So, √3=p/q (Where p and q are coprime) q√3 = p S.O.B.S (squarring on bot side) q²3=p²-----"1" q²= p²\3 (remember 1.3 rule) By 1.3 p/3=c ("c" can be any positive integer) p=3c-----------"2" Now by applying EQ 2 in 1 we get, q²3=(p/3)² (p=3c) q²3=p²9 q²=p²3 q²/3=p² (recall 1.3) Our assumption is our contradiction Our assumption is wrong Hence,√3 is irrational

Aakash .B Aakash.B 1 year, 8 months ago

P/q

ANSWER

In what ratio does the points p (2,-5) divide the line segment joining A(-3,5) and B(4 ,- 9)

Posted by Sahana Sahana 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Preeti Dabral 1 year, 8 months ago

Let the required ratio be k:1.
Then, by the section formula, the coordinates of P are
{tex}P \left( \frac { 4 k - 3 } { k + 1 } , \frac { - 9 k + 5 } { k + 1 } \right){/tex}
{tex}\therefore \quad \frac { 4 k - 3 } { k + 1 } = 2 \text { and } \frac { - 9 k + 5 } { k + 1 } = - 5{/tex} [{tex}\because{/tex} P(2, 5) is given]
{tex}\Rightarrow{/tex} 4k - 3 = 2k + 2 and -9k + 5 = -5k - 5
{tex}\Rightarrow{/tex} 2k = 5 and 4k = 10
{tex}\Rightarrow{/tex} {tex}k = \frac { 5 } { 2 }{/tex} in each case.
So, the required ratio is {tex}\frac { 5 } { 2 } : 1, {/tex} which is 5:2
Hence, P divides AB in the ratio 5:2.

Ashitha Saran 1 year, 8 months ago

A=(x1,y1)=(−3,5) and B=(x2,y2)=(4,−9) Let us assume that R(x,y)=(2,−5) divides AB in the ratio m:n, then using section formula: x=m+nmx2+nx1 2=m+n4m+(−3)n 2m−5n=0…(1) And, y=m+nmy2+ny1 −5=m+n−9m+5n 2m−5n=0…(2) In both the cases, we have: 2m=5n nm=25 ∴m:n=5:2

ANSWER

135+756

Posted by Rajyavardhan Singh 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Anjali Nagar 1 year, 8 months ago

891 itna bhi nhi aaya?

Aashna Parveen 1 year, 8 months ago

891

ANSWER

Find the LCM and HCF of 336 and 54 and varify the relationship between LCM and HCF

Posted by Nehru Nzua 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Satyaswarup Nayak 1 year, 8 months ago

HCF OF (336,54) : "6"; LCM OF (336,54) : "3024"; Relationship between LCM & HCF is : Product of two number = LCM × HCF => 336 × 54 = 6 × 3024 => 18144 = 18144 [@ PROVED]

ANSWER

Given the linear equation 2x+3y-8=0 write another linear equation in two variable such that the geometrical representation of the pair so formed is: (i) intersecting lines (ii) parallel lines (iii) coincident lines

Posted by Pushkar Lohiya 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 8 months ago

Given, linear equation is 2x + 3y - 8 = 0 ...(i)
Given: 2x + 3y - 8 = 0 ..... (i)

For intersecting lines, {tex}\frac { a _ { 1 } } { a _ { 2 } } \neq \frac { b _ { 1 } } { b _ { 2 } }{/tex}
{tex}\therefore{/tex} Any line intersecting with eq (i) may be taken as 3x + 2y - 9 = 0
or 3x + 2y - 7 = 0
For parallel lines, {tex}\frac { a _ { 1 } } { a _ { 2 } } = \frac { b _ { 1 } } { b _ { 2 } } \neq \frac { c _ { 1 } } { c_ { 2 } }{/tex}
{tex}\therefore{/tex} Any line parallel with eq(i) may be taken as 6x + 9y + 7 = 0
or 2x +3y - 2 = 0
For coincident lines, {tex}\frac { a _ { 1 } } { a _ { 2 } } = \frac { b _ { 1 } } { b _ { 2 } } = \frac { c _ { 1 } } { c_ { 2 } }{/tex}
{tex}\therefore{/tex} Any line coincident with eq (i) may be taken as 4x + 6y - 16 = 0
or 6x + 9y - 24 = 0

ANSWER

100x^2 - 20x +1

Posted by Harshita Buccha 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Vivek Mishra 1 year, 8 months ago

100x²-20x+1…100x²-10x-10x+1…10x(10x-1)-1(10x-1)…(10x-1)(10x-1)…10x=1…x=1/10.

Omya Aryan 1 year, 8 months ago

100x²-20x+1…100x²-10x-10x+1…10x(10x-1)-1(10x-1)…(10x-1)(10x-1)…10x=1…x=1/10.

ANSWER

Is it possible to design a rectangular mango grove whose length is twice its breadth and the area is 800 m2? If so, find its length and breadth.

Posted by Anu Varshini 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 8 months ago

Let the breadth of the rectangle be x metres
and the length is 2x metres.
So, area of rectangle is 800 sq.m.
(x)(2x) = 800
2x²= 800
x²= 400
x = {tex}\pm{/tex} 20
But breadth of rectangle cannot be negative, so x = 20
and yes, it is possible to design it.
So, Breadth is 20 m and length is 40 m.

ANSWER

2x2(6)+6

Posted by Kunal Anand 1 year, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Chinmayi P P 1 year, 8 months ago

30

Rahul Singh Bisht 1 year, 8 months ago

30

Aditya ... 1 year, 8 months ago

30

Debanshu Biswal 1 year, 8 months ago

30

Vanshika Singh 1 year, 8 months ago

30

ANSWER

is completing the square method ch 4 coming in board exam 2022-23?

Posted by Swastika Singhal 1 year, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Rahul Singh Bisht 1 year, 8 months ago

No never nothing

Aastik . 1 year, 8 months ago

Ni

Anshika Maurya 1 year, 8 months ago

No

ANSWER

What is the CSA of sphere??

Posted by Harsh . 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Anshika Maurya 1 year, 8 months ago

CSA= TSA

Mahi Kumari 1 year, 8 months ago

There is no any curved surface in sphere, so we will not able to calculate it's curved surface area, but we will able to calculate its TSA which will be 4πr²

ANSWER

if LCM(77,99)=693 then find their HCF(77,99)

Posted by Marwa Tabassum Ashraf . 1 year, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Angel Shibu Angel Shibu 1 year, 8 months ago

LCM x HCF=product of the numbers 639 x HCF= 77x99 HCF=77x99/639 HCF=7623/639 HCF = 11

Mahi Kumari 1 year, 8 months ago

We have given :- Let numbers a= 77 and b= 99 Formula to calculate:- HCF(a,b) × LCM(a,b) = a × b HCF(77,99) × 693 = 77 × 99 HCF(77,99) = (77 × 99)/693 Hence, HCF(77,99) = 11

ANSWER

The perimeter of a rectangle is 326 cm and its length is 98 cm. Find its breadth and area.

Posted by Vasanth Raj 1 year, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Sushamita Singh 1 year, 8 months ago

Breath = 65 Area = 6370

Kavi Kavi 1 year, 8 months ago

WKT perimeter=2(l+b) so 2(98+b)=326 196+b=326. b=326-196=130. area=l×b 98×130=12740cm square =127 msquare

Kavi Kavi 1 year, 8 months ago

Given perimeter:326

ANSWER

If one zero of the polynomial 2a^2-5a-(2k+1)is twice the other ,find both the zero of the polynomial and value of k

Posted by Gauri Nandana S 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 1 year, 8 months ago

Let {tex}\alpha{/tex} and 2{tex}\alpha{/tex} are the zeroes of the polynomial 2x² - 5x - (2k + 1).
Then, 2{tex}\alpha{/tex}² - 5{tex}\alpha{/tex} - (2k + 1) = 0
and 2 (2{tex}\alpha{/tex})² - 5(2{tex}\alpha{/tex}) - (2k + 1) = 0
{tex}\Rightarrow{/tex} 2{tex}\alpha{/tex}² - 5{tex}\alpha{/tex} = 2k + 1 ...(i)
and 8{tex}\alpha^2{/tex} - 10{tex}\alpha{/tex} = 2k + 1 ...(ii)
From Eqs. (i) and (ii), we get
2{tex}\alpha^2{/tex} - 5a = 8{tex}\alpha^2{/tex} - 10{tex}\alpha{/tex} {tex}\Rightarrow{/tex} 6{tex}\alpha^2{/tex} = 5{tex}\alpha{/tex} {tex}\Rightarrow{/tex} {tex}\alpha=\frac{5}{6}{/tex} {tex}[\because \alpha \neq 0]{/tex}
{tex}\therefore{/tex} 2{tex}\alpha{/tex} = {tex}\frac{5}{6} \times 2{/tex} {tex}=\frac{5}{3}{/tex}
Thus, the zeroes of the polynomial are {tex}\frac{5}{6}{/tex} and {tex} \frac{5}{3}{/tex}
Now, substituting {tex}\alpha=\frac{5}{6}{/tex} in Eq. (i), we get
2 {tex}\times{/tex} {tex} \frac{25}{36}-\frac{25}{6}{/tex} = 2k + 1
{tex}\Rightarrow{/tex} 2k + 1 = {tex}\frac{50-150}{36} {/tex} {tex}\Rightarrow 2 k+1{/tex} = {tex}-\frac{100}{36}{/tex}
{tex}\Rightarrow{/tex} 2k = {tex}-\frac{100}{36}-1{/tex} {tex} \Rightarrow{/tex} {tex} 2 k={/tex} {tex}-\frac{136}{36}{/tex}
{tex}\Rightarrow{/tex} k = - {tex}\frac{68}{36}{/tex} = {tex}\frac{-17}{9}{/tex}

ANSWER

Ch 13 very problem sir

Posted by Nitin Kumar 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Vanshika Singh 1 year, 8 months ago

Improve your English

ANSWER

Use Euclid's division lemma to show that the square of any positive integer is either the form 3m or 3m+1 for some integer m

Posted by Kaarthick Sinha 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Omya Aryan 1 year, 8 months ago

Not in syllabus

ANSWER

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Posted by Âťťíťůđē Bøý 1 year, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Âťťíťůđē Bøý 1 year, 8 months ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.

Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
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Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

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