CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

The formula to find the sample mean is: = ( Σ xi ) / n
The mode is the value that occurs the most often in a data set, and the range is the difference between the highest and lowest values in a data set.

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5+5+5=550

Posted by Palak Verma 6 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Palak Verma 6 years, 4 months ago

Always

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Nm ???? 6 years, 5 months ago

545+5=550

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Roshani Patidar 6 years, 5 months ago

545 +5 = 550

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( ) + ( ) + ( )=30 1,3,5,7,9,11,13,15 Ucan alao repeat the numbers

Posted by Md Hussain 6 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Umadevi St 6 years, 5 months ago

15+15(leave any one box blank)

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Kushal Kumawat 6 years, 5 months ago

It is no a solution due to the given ans. Is even and the given digit be odd

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Find the quadratic equation of 2 x square - 4 x minus 9

Posted by Karan Sahu 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Md Hussain 6 years, 5 months ago

This equation is not quadratic eqn. And no numbers which v multiply than 9 cum and than v subtract it come -4

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If a and b are two positive integer such that a=14b , then find the HCF (a,b)

Posted by Satrudhan Kunar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Parth Kanani 6 years, 5 months ago

41ab

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Karan Sahu 6 years, 5 months ago

41ab

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check whether 3n can end with digit 0 for any natural number n.

Posted by Arpita Agarwal 6 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Raj Singh 6 years, 5 months ago

Only when r=0-

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Raj Singh 6 years, 5 months ago

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√2+2√2=

Posted by Ashish Yadav 6 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Parth Kanani 6 years, 5 months ago

√2+2√2 2+√2+√2 2+2 4

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Miss Gayab (Khushi)? 6 years, 5 months ago

3√2

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Nakul Soni 6 years, 5 months ago

2√3

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A series has An =n×n +1is this AP or not

Posted by Sneha Mehta 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

a_n = n² - 1
Put n = 1, 2, 3, 4, ..... we get,
a₁ = 1² - 1 = 1 - 1 = 0
a₂ = 2² - 1 = 4 - 1 = 3
a₃ = 3² - 1 = 9 - 1 = 8
a₄ = 4² - 1 = 16 - 1 = 15, and so on.
Hence, the given sequence is 0, 3, 8, 15
a₂ - a₁ = 3 - 0 = 3
a₃ - a₂ = 8 - 3 = 5
As a₂ - a₁ {tex} \ne {/tex} a₃ - a₂, the given sequence is not an AP.

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2,7,12,...10પદ સુધી

Posted by Prajapati Amit 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Prove that in a right angle triangle the square of hypotenus is equal to the sum of square of other two side.

Posted by Aryan Bharadwaj 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

According to question, we are given a triangle ABC in which AC² = AB² + BC².
We need to prove that {tex}\angle B=90^{\circ}{/tex}
To start with, we construct a {tex}\Delta \mathrm{PQR}{/tex} right angled at Q such that PQ = AB and QR = BC.

Now, we observe that from {tex}\Delta{/tex}PQR, we have :
PR² = PQ² + QR² (Pythagoras Theorem, as {tex}\angle Q=90^{\circ}{/tex})
PR² = AB² + BC²..................(i) (By construction)
But, AC²= AB² + BC² ...............(ii) (given)
Therefore, AC = PR ................(iii) [From (i) and (ii)]
Now, in {tex}\Delta{/tex}ABC and {tex}\Delta{/tex}PQR,
AB = PQ (By construction)
BC = QR (By construction)
AC = PR [proved in (iii) above]
Therefore, {tex}\Delta ABC \cong \Delta PQR{/tex} (SSS congruence)
Hence, {tex}\angle{/tex}B = {tex}\angle{/tex}Q
But {tex}\angle{/tex}Q = {tex}{90^ \circ }{/tex} (By Construction)
Therefore, {tex}\angle{/tex}B = {tex}{90^ \circ }{/tex}

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I not understand ch-8 trigonomatry of 10th

Posted by Utkarsh Barange 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Kushal Kumawat 6 years, 5 months ago

Do more practice

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if 112=q×6+r then the possible values of r is what?

Posted by Raja Kumar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

0, 1, 2, 3, 4, 5

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I am not able to understand ch-7

Posted by Saksham Sehrawat 6 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

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Solution of chapter 4

Posted by Sobhana Jaiswal 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

You can check NCERT Solutions here : https://mycbseguide.com/ncert-solutions.html

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Is 3×7×51+21 are a composite number

Posted by Sweety Singh 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Kshitij Sonawane 6 years, 5 months ago

3×7×51+21 =21×51+21 =(51+1)21

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7x2+19x-6=0 find the quadratic equaction root of fsctorisation

Posted by Rahul Chouhan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Mamta Panghal 6 years, 5 months ago

7x2 +21x-2x-6=0 7x(x+3)-2(x+3)=0 (X+3) (7x-2)=0 X=-3. X=2/7

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Tan 1 degree, tan 10 degree, tan 20 degree, tan 70 degree, tan 80 degree, tan 89 degree = 1. Prove this.

Posted by Manshi Bisht 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Trignomatery

Posted by Balwinder Singh 6 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

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Write the polynomials whose zeroes are 2+root3 and 2-root3

Posted by Pranav .K 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Aryan Kothari 6 years, 5 months ago

Let alpha = 2 + root3 Beta = 2 - root 3 So alpha + beta = 4 Alpha × beta = 1 Ouadratic polynomial = K [ x^2 -(alpha + beta)x + alpha × beta] = K [ x^2 - 4x + 1] Let K = 1 So , quadratic polynomial = x^2 - 4x +1

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3x+5y=13 and 7x-2y=3 solve this by substitution method

Posted by Roshani Patidar 6 years, 5 months ago

CBSE > Class 10 > Mathematics