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Yogita Ingle 6 years, 4 months ago
By elimination method
x + y =5 ……….(1)
2x –3y = 4 ………(2)
Multiplying equation (1) by 2, we obtain
2x + 2y = 10 ………..(3)
2x –3y = 4 ………(2)
Subtracting equation (2) from equation (3), we obtain
5y = 6
y = 6/5
Substituting the value in equation (1), we obtain
x = 5 - (6/5) = 19/5
So our answer is x = 19/5 and y = 6/5
By substitution method
x + y =5 ……….(1)
subtract y both side we get
x = 5 - y ……..,(4)
plug the value of x in equation second we get
2(5 – y ) – 3y = 4
-5y = - 6
y = -6/-5 = 6/5
Plug the value of y in equation 4 we get
x = 5 – 6/5
x = 19/5
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According to the question, tan {tex}\alpha{/tex} = {tex}\frac{5}{12}{/tex}
We know that, sec {tex}\alpha{/tex} = {tex}\sqrt{1 + tan^2 \alpha}{/tex}
= {tex}\sqrt{1 + \frac{25}{144}}{/tex}
={tex}\sqrt{ \frac{144+25}{144}}{/tex}
={tex}\sqrt{ \frac{169}{144}}{/tex}
= {tex}\frac{13}{12}{/tex}
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Abhay Kumar 6 years, 4 months ago
1Thank You