CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

f( x)=ax^2+bx+c. a+b+c=0 . c=-a-b. Let zeroes are k and l. K+ l= -b/ a. Kl= c/a. Kl= -a-b/ a. Kl= b. (K- l )^2= (k+l)^2-4 kl. (K-l)^2= b^2/a^2 - 4b. K- l= √b^2 - 4a^2b/ a. k =( √b^2-4a^2b -b )/2 a.

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Ankit Class 2 years, 7 months ago

Exam khatam toh kya question kare🤣🤣🤣

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B.S Chauhan 2 years, 7 months ago

Good morning

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Determine the ratio in which the line 2x+y-4=0 divdes the line segment joining the points A(2,-2) and B (3, 7)

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Jasmeen Kaur 2 years, 7 months ago

Excuse me the ratio is given or not we assuming the ratio or given ratio

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Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 2 years, 7 months ago

in the ratio m₁: m₂ is given by the Section Formula. P (x, y) = [(mx₂ + nx₁) / (m + n) , (my₂ + ny₁) / (m + n)] Let the given line 2x + y - 4 = 0 divide the line segment joining the points A(2, - 2) and B(3, 7) in a ratio k: 1 at point C. Coordinates of the point of divison C (x, y) = [(3k + 2) / (k + 1), (7k - 2) / (k + 1)] Hence, x = (3k + 2) / (k + 1), y = (7k - 2) / (k + 1) This point C also lies on 2x + y - 4 = 0 .....(1) By substituting the values of C(x, y) in Equation(1), 2[(3k + 2) / (k + 1)] + [(7k - 2) / (k + 1)] - 4 = 0 [6k + 4 + 7k - 2 - 4k - 4] / (k + 1) = 0 (By Cross multiplying & Transposing) 9k - 2 = 0 k = 2/9 Therefore, the ratio in which the line 2x + y - 4 = 0 divides the line segment joining the points A (2, 2) and B (3, 7) is 2:9 internally.

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The angles of elevation of the top of a tower from two points at a distance of 4m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Shubham Kumar Kumar 2 years, 7 months ago

Thanks

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Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 2 years, 7 months ago

Let AB be the height of tower and x be the one of the complementry angle. So, (90-x) be the another complementary angle. C and D be the two points with distance 4 m and 9 m from the base respectively. As per question, In right ΔABC, ⇒tan x=AB/BC ⇒tan x=AB/4 ⇒AB=4 tan x...(i) Also, In right ΔABD, tan (90∘−x)=AB/BD ⇒ cot x=AB/9 ⇒AB=9 cot x...(ii) Multiplying equation (i) and (ii) AB²=9 cot x×4 tan x ⇒AB²=36 ⇒AB= ±6 Height cannot be negative. Therefore, the height of the tower is 6m.

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ANSWER

Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Half the perimeter of a rectangle garden. whose lenght is 4 m more than it's width, is 36 m. Find the dimension of the garden

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 2 years, 7 months ago

Given : Half the perimeter of a garden whose length is 4 m more than its width is 36 m. To do: We have to find the dimensions of the garden. Solution : Perimeter of a rectangle of length l and breadth b=2(l+b). Let the length of the rectangle be l and the width of the rectangle be b. Therefore, Half the perimeter of rectangle = 2 (l + b) 2 Half the perimeter of rectangle =l+b. Given that half the perimeter of the rectangular garden =36 m. l+b=36 m......(i) It is given that, length of the rectangular garden is 4 m more than its width. This implies, l=b+4.......(ii) Substituting (ii) in (i), we get, b+4+b=36 2b=36−4 2b=32 b= 32/2 b=16 m Substitute b=16 in (ii) l=16+4 l=20 m Therefore, the length of the rectangular garden is 20 m and the width of the rectangular garden is 16 m.

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Ankit Class 2 years, 7 months ago

Let length be l and breadth be b of rectangular garden. l= b+4. (l+b)/2 = 36 . l+b= 72. b+4 + b = 72. 2b+4= 72. 2b= 68. b= 34 m. l=b+4 = 34+4= 38 m.

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In each of following find the value of 'ne for which the points are collinear. (7, -2), (5, 1), (3, k)

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the area of the triangle whose vertices are : (2, 3), (-1, 0), (2, -4,) (-5, -1) , (3-5), (5, 2)

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Evaluate the following: (1) sin 60°cos 30°+sin 30° cos 60° (2) 2tan²45° + cos²30°- -sin² 60°

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which term of the AP:121, 117,113,...,is it's first negative term? [Hint:find n for a/n<0]

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Class 2 years, 7 months ago

a=121 , d= -4 let l=o . a+ (n-1)d = l . 121+(n-1)x-4= 0. (n-1)=121/4. n= 30.25+1. n = 31.25 , Here we know that n always be natural number hence n should be 31. n= 31.

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ANSWER

Exercise 1.1 q 2

Posted by Sharvan Verma 2 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Jasmeen Kaur 2 years, 7 months ago

Let 'a' be a postive odd integer also. Let 'q' be quotient and 'r' be the remainder after dividing by six. Then a=6q+r, where 0<r<6. Postive integer are 1,2,3,4,5 a=6q+0, 6q+1, 6q+2, 6q+3, 6q+4, 6q+5. But a=6q, 6q+2 and 6q+4 are even. When a is add it is the form 6q+1, 6q+3, 6q+5 for some integer q. .°. Hence proved...

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Find the value of a and p for which the following pair of linear equation has infinite solutions 2x + 3y=7 ax +(a+p)y=28

Posted by Ansika Shetty 2 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Class 2 years, 7 months ago

(2/a )=(3/a+p)= (7/28). 2/a= 7/28 . 2/a= 1/4 . a= 8. (3/p+8)= 7/28. (3/p+8)= 1/4. P+8 = 12. P= 4 .

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ANSWER

From geometry, you are already familiar with the construction of angles of __°, _°and__°and__°.

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Ankit Class 2 years, 7 months ago

0° , 30° ,45° ,60° , 90° ,120° , 135° ,150° , 180° any many more

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Ankit Class 2 years, 7 months ago

😂

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If 3cot A=4 , right angled at B, if tan A=1/√3 find the value of : sin A cos C+ cos A sin C

Posted by Jasmeen Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashish Tiwari 2 years, 7 months ago

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ANSWER

Using Euclid's algorithm, find the largest number that divided 1251, 9377 and 15628 leaving remainder 1,2 and 3 respectively

Posted by Minato Uzmaki 2 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Class 2 years, 7 months ago

Subtract 1,2,3 from these no we get 1250, 9375, 15625 now use Euclid algorithm first in any of two then you get HCF of those two number then use again Euclid algorithm in HCF that you got with the third number

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If 2sinQ=1 find the value of Q

Posted by Ishu Bhagat Singh Agarwal 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Prince Sharma 2 years, 7 months ago

2sinQ=1 =>sinQ=1/2 =>sinQ=sin30° [On comparing] =>Q=30°

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Ishu Bhagat Singh Agarwal 2 years, 7 months ago

Sin30°

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If the distance between the points (4,p) and (1,0) is 5, then the Value of p is

Posted by Sukhmandeep Kaur 2 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Prince Sharma 2 years, 7 months ago

(4 -1)² +(p - 0)² = 5². => 9 + p² =25. => p² = 16. => p = 4

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Bishu Chourasia 2 years, 7 months ago

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Jasmeen Kaur 2 years, 7 months ago

P=3

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ANSWER

The distance between the point P(-11/3,5) and Q(-2/3,5)

Posted by Anshuman Behera 2 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Ankit Class 2 years, 7 months ago

D=√ (-11+2/3)^2 +(5-5)^2 . D= √ 9 . D= 3 unit

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Ankit Class 2 years, 7 months ago

I don' t like much calculation because l am little weak in calculation 🤣

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Ankit Class 2 years, 7 months ago

Use distance formula

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ANSWER

What is trigonometry ratio

Posted by Vishwaraj Kumar 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Ankit Class 2 years, 7 months ago

Ratio of any two side in a right angle triangle whose specific name was kept by their specific ratio like p/ h , b/ h , p/ b etc

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Sukhmandeep Kaur 2 years, 7 months ago

Sin - Sine Cos - Cosine Tan - Tangent Cosec - Cosecant Sec - Secant Cot - Cotangent

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ANSWER

Factorisation of 5x²-4-8x=0

Posted by Srishti Kumari 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Maya Shukla 2 years, 7 months ago

x=2 and -2/5

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Prince Sharma 2 years, 7 months ago

5x²-8x-4=0 => 5x²-10x+2x-4=0 => 5x(x-2) + 2(x-2)=0 => (x-2)(5x+2)=0 => x=2,-2/5

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ANSWER

If A=2n+13 B=n+7 Where n is any natural no. Find HCF of A and B

Posted by Vinjul Gaming 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Ankit Class 2 years, 7 months ago

HCF (A,B) = 1 . Because you can check by taking any natural number in place of n .

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Prem Latha 2 years, 7 months ago

Ans

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ANSWER

Find HCF of 660 and 704 by prime factorization.

Posted by Dikshant Yaduvanshi 2 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Maya Shukla 2 years, 7 months ago

Question acha hai 🤟

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Maya Shukla 2 years, 7 months ago

660- 2,2,3,5,11. 704-2,2,2,2,2,2,11. Answer hai 22

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ANSWER

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60°. The angle of elevation of the top of second tower from the foot of the first tower is 30°. Find the distance between two towers and the height of the other tower. Also, find the length of the wire attached to the tops of both the towers.

Posted by Utkarsh Kumar Yadav 2 years, 7 months ago

CBSE > Class 10 > Mathematics

5 answers

Preeti Dabral 2 years, 7 months ago

Let distance between the two towers = AB = x m
and height of the other tower = PA = h m
Given that, height of the tower = QB = 30 m and {tex}\angle{/tex}QAB = 60°, {tex}\angle{/tex}PBA = 30°.

Now, in {tex}\Delta Q A B, \tan 60^{\circ}=\frac{Q B}{A B}=\frac{30}{x}{/tex}
{tex}\Rightarrow \sqrt{3}=\frac{30}{x}{/tex}
{tex}x=\frac{x^{2}}{3}-\frac{x}{3}-\frac{x-3}{3}-x+0.5 \pi{/tex}
and in {tex}\Delta P B A{/tex}
{tex}\tan 30^{\circ}=\frac{P A}{A B}=\frac{h}{x}{/tex}
{tex}\Rightarrow \frac{1}{\sqrt{3}}=\frac{h}{10 \sqrt{3}}{/tex} {tex}[\because x=10 \sqrt{3} \mathrm{m}]{/tex}
{tex}\Rightarrow h = 10 m{/tex}
Hence, the requied distance and height are {tex}10\sqrt3{/tex} and 10m, respectively.