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  • 1 answers

Sankalp Dinesh 2 years, 6 months ago

What is the Question??
  • 1 answers

Taniya . 2 years, 6 months ago

Given that α & β are zero of polynomial f(x)=x2−3x−2 therefore α+β=3 αβ=−2 Now, the zero of the required quadratic polynomial are, 2α+β1​ & 2β+α1​ Sum of the roots- 2α+β1​+2β+α1​=(2α+β)(2β+α)2β+α+2α+β​=4αβ+2α2+2β2+αβ3(α+β)​ =4×(−2)+2[(α+β)2−2αβ]+(−2)3×3​ =−10+2[9+2×2]9​ =−10+269​ =169​ Products of roots:- 2α+β1​×2β+α1​=4αβ+2[(α+β)2−2αβ]+αβ1​=161​ Now Req eq. x2−(sum of roots)x+ Product of roots=0 =x2−169​x+161​=0 =16x2−9x+16=0.
  • 1 answers

Jasmeen Kaur 2 years, 6 months ago

After reading this chapter, three students drew different conclusion. Whi
  • 3 answers

Shalu Dubey 2 years, 6 months ago

A tangent pq at a point p of a circle of radius 5 cm meets a line through

Alok Jha 2 years, 6 months ago

The cost of each pencil is ₹3 and cost of pen is ₹5

Kavi Kavi 2 years, 6 months ago

X be cost of pencil and y be cost of pen. 5x+7y=50;7x+5y=46 solve by elimination method. x=3.y =5
  • 1 answers

Jiya Ray 2 years, 7 months ago

First we will take out prime factors of both numbers that is 336 and 54 .. 336=2⁴×3×7 , 54=2×3³ now we know that HCF= product of common terms with lowest power so we multiply 2×3=6 and now LCM = product of prime factors with highest power so we multiply 2⁴×3³×7=3024. And now We will verify so LCM×HCF=product of two numbers 3024×6=336×54 18144=18144.
  • 1 answers

Alok Jha 2 years, 6 months ago

The value of x is 36 and y is 13
  • 1 answers

Anonymous 2 years, 6 months ago

This is ncert question
  • 1 answers

Jasmeen Kaur 2 years, 7 months ago

x²+x-2x-2=x²+3-x-3 x²+x-2x-2-x² -3x +x +3 x-2x-3x+x-2+3 -x-2x-3x+x-2+3 -x-2x+1=0 -3x+1=0 Hence, given equation is not quadratic equation
  • 3 answers

Mukundhan S 2 years, 7 months ago

Because negative can't be squre rooted

Mukundhan S 2 years, 7 months ago

No it is not possible

Jasmeen Kaur 2 years, 7 months ago

Using formula b²-√4ac/2
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  • 2 answers

Ankit Class 2 years, 7 months ago

Tum kis class mein ho

Ankit Class 2 years, 7 months ago

x^2= 8. x=2√2 and -2√2.
  • 3 answers

Ankit Class 2 years, 7 months ago

5p^2+20

Khushi Kushwaha 2 years, 7 months ago

√4

Khushi Kushwaha 2 years, 7 months ago

20 + 5p^2 , by taking common factor = 5(4+p^2)
  • 1 answers

Ankit Class 2 years, 7 months ago

Using trigonometric ratio like sinA = p/ h , cosA= b/ h etc
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  • 0 answers
  • 3 answers

Ansh Singh Rajput 2 years, 7 months ago

Why are you take so much interest in solving all the questions Khushi...?

Ansh Singh Rajput 2 years, 7 months ago

Are you the topper of your class...!

Khushi Kushwaha 2 years, 7 months ago

4x + 3y = 17 { decimals will be removed 4/10x + 3/10y = 17/10 ( here, all the 10 will be cancel out) } ----(i) Similarly: 7x - 2y = 8 will be form by removing decimals in the same manner .----(ii) From equation --(i) ------> X = 17-3y/4 Putting value of x in 7x - 2y = 8 7(17-3y/4) - 2y = 8 119 - 21y/4 - 2y = 8 (by solving brackets) 119 - 21y - 8y /4 =8 (by taking LCM.) 119 - 29y /4 = 8 119 - 29y = 32 ( by multiplying 4 on the left hand side) - 29y = 32 - 119 -29y = - 87 ( subtract sign will be cancled ) y = 87/29 y = 3 Now finding value of x X = 17 - 3y /4 X = 17 - 3(3)/4 X = 17 -9 /4 X = 8 /4 X= 2
  • 5 answers

Palak Singh 2 years, 6 months ago

a²+2ab+b²

Mukundhan S 2 years, 7 months ago

A²+B²+2AB

Shashank Yadav 2 years, 7 months ago

a² + b² + 2ab

Lakshya Agrawal 2 years, 7 months ago

a^2+b^2+2ab

Arpita Mishra 2 years, 7 months ago

a2+ b2+2ab
  • 3 answers

Fahad Siddiqui 2 years, 7 months ago

LCM=3 ki power 5 and 5 ki power 2

Ankit Class 2 years, 7 months ago

HCF = 3 , LCM = 6075

Shreesh Singh 2 years, 7 months ago

U
  • 1 answers

Ankit Class 2 years, 7 months ago

Using integretion
  • 1 answers

Rudra Pratap Singh 2 years, 7 months ago

We have a and b are two odd positive integers such that a & b but we know that odd numbers are in the form of 2n+1 and 2n+3 where n is integer. so, a=2n+3, b=2n+1, n∈1 Given ⇒ a>b now, According to given question Case I: 2 a+b ​ = 2 2n+3+2n+1 ​ = 2 4n+4 ​ =2n+2=2(n+1) put let m=2n+1 then, 2 a+b ​ =2m ⇒ even number. Case II: 2 a−b ​ = 2 2n+3−2n−1 ​ 2 2 ​ =1 ⇒ odd number. Hence we can see that, one is odd and other is even.

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