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Gaurav Seth 6 years, 3 months ago
69, 67, 71
Let ( a - d ) , a , ( a + d ) are three parts are in A.p
according to the problem given ,
a - d + a + a + d = 207
3a = 207
a = 207 / 3
a = 69
product of two smaller parts = 4623
( a - d ) × a = 4623
( 69 - d ) × 69 = 4623
69 - d = 4623/69
69 - d = 1541/23
69 - d = 67
-d = 67 - 69
- d = - 2
d = 2
Therefore ,
required three parts are ,
a - d = 69 - 2 = 67
a = 69
a + d = 69 + 2 = 71
Posted by Yadav Monu 6 years, 3 months ago
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Gaurav Seth 6 years, 3 months ago
Qustion: If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A.
Solution:
Sin 3A = cos (A-26 )
cos (90 - 3A) = cos (A-26) [ sinA = cos (90- A )
By comparison
90-3A = A-26
90+26=A+3A
116=4A
A= 29
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Rishi Raj Singh Jadon 5 years, 11 months ago
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