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  • 2 answers

Sia ? 6 years, 6 months ago

The general term of an AP is given by an=a+(n-1)d and Sn={tex}\frac{n}{2}{/tex}[2a+(n-1)d].
Given that a2=14 and a3=18
So, d=a3-a2=18-14=4
Now, a2=14 {tex}\Rightarrow{/tex}a+4=14 {tex}\Rightarrow{/tex}a=10
Also, S51={tex}\frac{{51}}{2}{/tex}[2(10)+(50)4]
{tex}\Rightarrow{/tex}S51={tex}\frac{{51}}{2}{/tex}[20+200]
{tex}\Rightarrow{/tex}S51={tex}\frac{{51}}{2}{/tex}[220]
{tex}\Rightarrow{/tex}S51=51{tex}\times{/tex}110
{tex}\Rightarrow{/tex}S51=5610

Soyab Khan 6 years, 6 months ago

Tayyaua
  • 1 answers

Tarun Pandey 6 years, 6 months ago

5th term of the AP is zero
  • 0 answers
  • 2 answers

Gaurav Seth 6 years, 6 months ago

Let √2 be a rational number 

Therefore, √2= p/q  [ p and q are in their least terms i.e., HCF of (p,q)=1 and q ≠ 0

On squaring both sides, we get 
                   p²= 2q²                                                                                    ...(1)
Clearly, 2 is a factor of 2q²
⇒ 2 is a factor of p²                                                                    [since, 2q²=p²]
⇒ 2 is a factor of p

 Let p =2 m for all m ( where  m is a positive integer)

Squaring both sides, we get 
            p²= 4 m²                                                                                          ...(2)
From (1) and (2), we get 
           2q² = 4m²      ⇒      q²= 2m²
Clearly, 2 is a factor of 2m²
⇒       2 is a factor of q²                                                      [since, q² = 2m²]
⇒       2 is a factor of q 

Thus, we see that both p and q have common factor 2 which is a contradiction that H.C.F. of (p,q)= 1

     Therefore, Our supposition is wrong

Hence √2 is not a rational number i.e., irrational number.

Inayat Khan 6 years, 6 months ago

Its an example of ncert
  • 2 answers

Killer Theorem 6 years, 6 months ago

because this number can be written in the form of more than 2 factors

Manish Singh 6 years, 6 months ago

7*11*13+13 13(7*11+1) 13*78 13*13*2*3 Therefore, 7*11*13+13 is composite number 7*6*5*4*3*2*1+5 5(7*6*4*3*2*1+1) 5(1009) 5*1009*1 Therefore, 5*1009*1 is composite number.
  • 2 answers
5

Inayat Khan 6 years, 6 months ago

x(x-5)=0. =x-5=0. = x=5. Hope this will help you.
  • 4 answers

Secret Girl..... ? 6 years, 6 months ago

Right

Krishna Gupta 6 years, 6 months ago

If anyone scores well in basic exam and wants to opt Maths in 11th then they have to appear for Compartement Exam and have to pass in Maths Standard Paper..

Inayat Khan 6 years, 6 months ago

Anyone who scores well in basic can opt standart by giving the compartment exam

Secret Girl..... ? 6 years, 6 months ago

U r talking about optional maths??
  • 0 answers
  • 1 answers

Inayat Khan 6 years, 6 months ago

Ch 1to 7,14,15
  • 1 answers

Piyush Bhardwaj 6 years, 6 months ago

_Make your anklet feel special by adorning with these American Diamond Gold Plated Pendant with Earrings, Haathphool and Ring . Flaunt your arms with these sparkling bajubandh._ Catalog Name : *Ruby Emerald American Diamond Gold Plated Jewellary Sets* Material: Alloy Size: Free Size Description: It Has 1 Piece Of Necklace, 1 Pair of Earnings with 1 Piece of Haathphool & 1 Piece of Ring Work: Stone Work Dispatch: 2 – 3 Days Designs: 7 Easy Returns Available in Case Of Any Issue
  • 1 answers

Rakesh Kumar Tiwari 6 years, 6 months ago

Common difference ko kahte hain. "Samantar shredhi k Kinhi bhi do kramagat pado ke antar ko sarva antar kahte hain." "Difference between any two consecutive terms of an A.P."
  • 4 answers

Inayat Khan 6 years, 6 months ago

an =a+(n-1)d

Inayat Khan 6 years, 6 months ago

Sn where an is given: sn=n/2[a+l] where l=an

Sharique Abdullah 6 years, 6 months ago

Sn = n/2(2a+(n-1)d)

Anugya Gautam 6 years, 6 months ago

a+(n-1)d
  • 1 answers

Inayat Khan 6 years, 6 months ago

Let √5 be rational such that √5=p/q where p nd q are co prime numbers. Now;√5=p/q. q√5=p . Squaring both sides; 5q^2=p^2. .......(1) also;p =5s for some integer s;putting p=5s in (1) 5q^2=(5s)^2. 5q^2=25s^2. From (1) nd(2) weconclude that 5is a common factor of p^2as well as p nd q^2as well as q.Hence;our assumption that p nd q are co prime integers is wrong.therefore √5is irrational by contradiction. Hope it will help u.
  • 2 answers

Ashwani Kumar 6 years, 6 months ago

45 degree

Diksha . 6 years, 6 months ago

45 degree
  • 1 answers

Aayush Kumar 6 years, 6 months ago

Yes , that is basic proportional theorem.
  • 4 answers

Poonam Mahato 6 years, 6 months ago

1

? Queen ? 6 years, 6 months ago

Sin²A + Cos²A = 1.
1 is the answer

Sarvagya Porwal 6 years, 6 months ago

1
  • 0 answers
  • 1 answers

Inayat Khan 6 years, 6 months ago

2(-5)'^2+p(-5)-15=0. 2*25-5p-15=0. 50-5p-15=0. 35-5p=0. p=-35/-5. p=7. Now;p(x^2+x)=-k. Putting p=7; 7x^2+7x=-k. 7x^2+7x+k=0. Since it has equal roots; so;b^2-4ac=0. (7)^2-4*7*k=0. 49-28k=0. k=-49/-28 =7/4. Hope this will help u dear.
  • 3 answers
There is a rule that state that the ratio of perimeter of two similar triangle is equal to the ratio of their corresponding sides......apply this who got it....

621311 ?? 6 years, 6 months ago

How did you get it??? Can you please send me whole solution.
15
  • 3 answers

Inayat Khan 6 years, 6 months ago

Ikrar is my elder brother

Aayush Kumar 6 years, 6 months ago

We use distance formula for finding the distance between two points (like distance between A to B )& we use section formula to find the rotio of the sector of line which is divided into two (or more) parts , for ex; suppose AB is a line and P is the point on AB so by section formula we can find the distance AP and BP and its coordinates also.
To find the distance btw two point ......if we have to find the ratio in which line joining btw two coordinate is divided by a coordinate we use section formula.....
  • 4 answers

Gaurav Pandey 6 years, 6 months ago

No

? Queen ? 6 years, 6 months ago

What No???.

Aayush Kumar 6 years, 6 months ago

No

Secret Girl...... ? 6 years, 6 months ago

Wlcm
  • 2 answers

Aayush Kumar 6 years, 6 months ago

You can read summary page (pg -116 of NCERT book ) at the end of chapter.

Inayat Khan 6 years, 6 months ago

Read ncert summary at the last of chapter or prefer to support material
  • 4 answers

Vishal Gurjar 6 years, 6 months ago

Thanks.

Aayush Kumar 6 years, 6 months ago

It is the point on graph where X and Y coordinate intersect each other and form O (0,0). In other words we can say that it is the center of graph or mean point .

Balasundar K 6 years, 6 months ago

The point of intersection of x and y axes is called origin

Secret Girl...... ? 6 years, 6 months ago

Of maths?
  • 2 answers

Dhairya Singh 6 years, 6 months ago

In basic maths exam questions will be 1 level easy than standard exam Those people who will not opt for maths in future should take basic maths

Abul Fazal X Factor 6 years, 6 months ago

Nothing
  • 1 answers

Ankit Kumar 6 years, 6 months ago

Which one

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