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2 whole X upon X + 1 whole square - 5 X upon X + 1 + 2 equal to zero solve it using quadratic formula

Posted by Anshu Chauhan 6 years, 3 months ago

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D is the midpoint of side BC of a ∆ABC. AD is bisected at point Eand BE produced cuts AC at point X.Prove that BE:EX=3:1

Posted by 621311 ?? 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

Given:-In fig., {tex}\Delta{/tex}ABC D is the mid-point of BC and E is the mid-point of AD.

To prove:- BE : EX = 3 : 1
Construction: Through D, draw DF parallel to BX.
Proof:- In {tex}\Delta{/tex}AEX and {tex}\Delta{/tex}ADF
{tex}\angle EAX = \angle DAF{/tex} [Common]
{tex}\angle AXE = \angle AFD{/tex} [Corresponding angles]
Then, {tex}\Delta{/tex}AEX ~ {tex}\Delta{/tex}ADF [By AA similarity]
{tex}\therefore \frac{{EX}}{{DF}} = \frac{{AE}}{{AD}}{/tex} [Corresponding parts of similar {tex}Triangle{/tex}are proportional]
{tex}\Rightarrow \frac{{EX}}{{DF}} = \frac{{AE}}{{2AE}}{/tex} [AE = ED given]
{tex}\Rightarrow{/tex} DF = 2EX ....(i)
In {tex}\Delta{/tex}CDF ~ {tex}\Delta{/tex}CBX
{tex}\angle C = \angle C{/tex} [Common]
{tex}\angle CDF = \angle CBX{/tex} [Corresponding angles]
Then, {tex}\Delta{/tex}CDF ~ {tex}\Delta{/tex}CBX [By AA similarity]

Therefore ,{tex} \frac{{CD}}{{CB}} = \frac{{DF}}{{BX}}{/tex} [Corresponding parts of similar {tex}\Delta{/tex}are proportional]
{tex}\Rightarrow \frac{1}{2} = \frac{{DF}}{{BE + EX}}{/tex} [BD = DC given]
{tex}\Rightarrow{/tex} BE + EX = 2DF
{tex}\Rightarrow{/tex} BE + EX = 4EX [By using (i)]
{tex}\Rightarrow{/tex} BE = 4EX - EX
{tex}\Rightarrow{/tex} BE = 3EX{tex}{/tex}
{tex}\Rightarrow \frac{{BE}}{{EX}} = \frac{3}{1}.{/tex}

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In figure. 6.19 DE||ACand DF||AE.prove that BF/FE = BF/EC

Posted by Nirankar Sharma 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

In {tex}\triangle ABE,{/tex} we have {tex}DE||AE,{/tex}then
{tex}\frac{{BD}}{{AD}} = \frac{{BF}}{{FE}}\,{/tex} [By BPT] ...... (i)
In {tex}\triangle ABC,{/tex} we have {tex}DE||AC,{/tex} then
{tex}\frac{{BD}}{{AD}} = \frac{{BE}}{{EC}}\,{/tex} [By BPT] ...... (ii)
From (i) and (2), We get
{tex}\frac{{BF}}{{FE}} = \frac{{BE}}{{EC}}{/tex}

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Xsqure-2x-8 find zeros of guadratic equation and verify the relationship between the zeros and cofficients

Posted by Varinderjit Kaur 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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⛩️Singh Empire? (Believe In Study) 6 years, 3 months ago

4 and -2

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If cosecant a + cot a = m show that m square minus one by m square + 1 = cos a

Posted by Mohamed Abdullah Suhaib 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Harathi Kallem 6 years, 3 months ago

Lhs (CosecA+cotA)^2-1/(cosecA+cotA)^2+1 CosecA^2+cotA^2+2cosecAcotA-1/ CosecA^2+cotA^2+2cosecACotA+1 (CosecA^2-1)+cotA^2+2cosecACotA/ CosecA^2+(cotA^2+1)+2cosecAcotA CotA^2+cotA^2+2cosecACotA/ CosecA^2+cosecA^2+2cosecAcotA 2cotA^2+2cosecACotA/ 2cosecA^2+2cosecACotA 2cotA(cotA+cosecA)/ 2cosecA(cosecA+cotA) After cancellation CotA/cosecA CosA/sinA*1/sinA Which is cosA Hence proved

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Why sodium chloride have high melting point?

Posted by Manish Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

⛩️Singh Empire? (Believe In Study) 6 years, 3 months ago

Because of its rigid structure due to strong ionic force of attrectio........

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Priksha Sangwan 6 years, 3 months ago

Sodium chloride means Nacl As its ionic bond is very high it means its structure is very rigid So to break up this high temperature is required That's why it has high melting point

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Mayank Sharma 6 years, 3 months ago

Nacl make ionic bond we know that ionic bond are only solid that's Nacl has high melting point.

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In triangle ABC,AB=AC side BC is produced to triangle• prove that (AD2-AC2)=BD×CD

Posted by Arvind Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Graph of quadratic polynomial is

Posted by Sachin Sherawat 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Ram ? 6 years, 3 months ago

Parabola

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Sachin Sherawat 6 years, 3 months ago

Parabola

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Find the quadratic polynomial whose zeros are 2+√3 and 2-√3.

Posted by Diya Paul 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Ram ? 6 years, 3 months ago

X^2-4x+1

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Jatin Kumar 6 years, 3 months ago

Sum of zero is 2+√3 Product of zero is 2-√3 X^2+(2+√3)x+(2-√3) X^2+2+√3x+2-√3

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Mayank Sharma 6 years, 3 months ago

Let one zero be alpha and other be beeta. Alpha=2+√3 and beeta=2-√3. Sum of zero= Alpha+ beeta. 2+√3+2-√3=4... Product of zero= alpha× beeta= 2+√3×2-√3= (2)²-(√3)²= 4-3=1. X²- sum of zero(x)+ product of zero X²- 4x+1.

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Irrational number √5

Posted by Ashok Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

⛩️Singh Empire? (Believe In Study) 6 years, 3 months ago

Yes √5 is irrational number......

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Exercise 4D question no 9

Posted by Sapna Maurya 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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What is the formula of sector

Posted by Anjali Balhara 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

❇❇Diya❇❇ 6 years, 3 months ago

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Dheeraj Malhotra 6 years, 3 months ago

Minor sector-πr²×thita/360°and major sector — πr²-πr²×thita/360°

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Mayank Sharma 6 years, 3 months ago

Minor sector area of circle is ∅÷360×πr²... Major sector area of circle = 360-∅÷360×πr²

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The number of polynomials having zeroes as-2 and 5 is

Posted by Sonal Jain 6 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Sonal Jain 6 years, 3 months ago

A1 b2 c3 dmore than 3

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Vanshika Tanwar 6 years, 3 months ago

Infinite

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Swapana Sebastian 6 years, 3 months ago

More than 3

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Vibhor Kashyap 6 years, 3 months ago

X^2+3x-10 is the quad. Polynomial

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The ratio of the areas of two similar triangles is equal to the squares of the ratio of their corresponding sides

Posted by B.Ramesh Ramesh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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If secthita +tan thita = x then sec thita=

Posted by Aakriti Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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If A+B=90° prove that √tanAtanB+tanAcotB/sinAsecB--sin²B/cos²= tanA

Posted by Piyush Dev Jha 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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1.) Which term of an A.P .21,42,63,... is 210? 2.) Find the 6th term from the end of A.P. -11,-8,-5,...,49 3.)Write the LCM of 13,17and 19. 4.) Solve : A(5,-3) ,B(_9,-2) with the help of distance formula.

Posted by Jatin Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Piyush Dev Jha 6 years, 3 months ago

(4) distance formula=√(x2-x1) +(y2-y1) X1=5;x2=9;y1=-3;y2=-2 √(9-5)²+(-2-3)² √(4)²+(-5)² √16+25 √41

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Piyush Dev Jha 6 years, 3 months ago

(1) d=21;a=21;an=210 an=a+(n-1)d 210=21+(n-1)21 210-21=21n-21 189=21n-21 189+21=21n n=210/21 n=10

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Vanshika Tanwar 6 years, 3 months ago

May be the answer of question 2 is 64.

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Vanshika Tanwar 6 years, 3 months ago

10th term of this A.P would be 210

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1.) Prove that : 1/sec A + tan A-1/cos A=1/cosA-1/sec A - tan A

Posted by Jatin Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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If equilateral triangle are drawn on the side of the right triangle show that area of a triangle of a hypoteneus is equal to the sum of the area of the triangle(using similarity)

Posted by Mehul Prasad 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Lakshya Nama 6 years, 3 months ago

Use pgt in it

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The shadow of a tower standing on a level ground is found to be 30m longer than the suns altitude is 30• than when it is 60•.find the height of the tower

Posted by Hariabi2 Hariabi2 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Find the area of a triangle whose vertices are (1 -1) (-4 6) (-3 -5).

Posted by Jatin Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Om Jee Tiwary 6 years, 3 months ago

6 is the answer

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Supriya Kotwal 6 years, 3 months ago

Use the formula 1/2{x1(y2-y1)+x2(y3-y1)+x3(y1-y2)}

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What is Section formula

Posted by Om Jee Tiwary 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajat Richa 6 years, 3 months ago

(m1x2 +m2x1\m1+m2 ,m1y2+m2y1\m1+m2)

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What should be subtracted from 1lakh to get largest 4 digit number

Posted by Tanishka Sharma 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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If the squared difference of roots of an equation x2 + px +45 is 144 find the value of p

Posted by Mansi Sanpal 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Navneet Chaudhari 6 years, 3 months ago

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7 is a polynomial of degree?

Posted by Sapna Grg 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Jatin Kumar 6 years, 3 months ago

The degree of polynomial of 7 is zero

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Krishna Prajapati 6 years, 3 months ago

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Yogita Ingle 6 years, 3 months ago

As we know that the degree of any polynomial is calculated based on on the the value of highest exponent of the variable. In the given question we can see there is no variable and and a constant that is root 7 is given.

For all constants the degree is always zero.

i.e. x⁰ = 1

Therefore the degree for the polynomial root 7 is "zero".

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The sum of two number is15 and the sum of their reciprocal is 3/10.find the numbers

Posted by Jitendra Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

??Geetha Sree ?? 6 years, 3 months ago

One number (x)=5. Other number(y)=10.

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Diksha ... 6 years, 3 months ago

One no is 5and the other one is 10

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Shashi Kumar 6 years, 3 months ago

One number is x other number be Y . X+y =15 .1/x+1/y =3/10 solve this equation by his own mind

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if in triangle abc and d e f are similar and BC:EF that is 7:8 then the ratio of perimeter of triangle ABC is

Posted by Rajani Barik 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Prove that Two plus under root five is an irrational number

Posted by Kumar Nishu 6 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Prove under root 5 is irrational?

Posted by Abhishek Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 3 months ago

Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are integers.
so, √5 = p/q
p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an integer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.

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The LCM of three numbers 28,44,132 is

Posted by Param Gehal 6 years, 3 months ago

CBSE > Class 10 > Mathematics