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Ask QuestionPosted by # Mission Lbsnaa?? 6 years, 2 months ago
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Unique Girl.. ? 6 years, 2 months ago
Posted by Sharad Keshav 6 years, 2 months ago
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Posted by Abhishek Uttam 6 years, 2 months ago
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Posted by Abhishek Uttam 6 years, 2 months ago
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Posted by # Mission Lbsnaa?? 6 years, 2 months ago
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Posted by Divya Gupta 6 years, 2 months ago
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Pushkar Sahi 6 years, 2 months ago
Posted by Shivam Kumar 6 years, 2 months ago
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Sia ? 6 years, 2 months ago
Step by Step explanation.
a = b
a2 = 2b
d = c - d
c = -c
2b - 2c
{tex}\frac {c}{2c}{/tex}= {tex}\frac {1}{2}{/tex}
Posted by Kabir Khan 6 years, 2 months ago
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Priyanshu Raj 6 years, 2 months ago
Posted by # Mission Lbsnaa?? 6 years, 2 months ago
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# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
# Mission Lbsnaa?? 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Shreya... #Be Positve Be Happy 6 years, 2 months ago
Posted by Jai Verma 6 years, 2 months ago
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Posted by Rk Vishwakarma 6 years, 2 months ago
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Posted by Ravi N K E 6 years, 2 months ago
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Ã.P.W.B.Đ ⚡ 6 years, 2 months ago
Posted by Sri Shivani Sankar 6 years, 2 months ago
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Posted by Sri Shivani Sankar 6 years, 2 months ago
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Posted by Salini Rana 6 years, 2 months ago
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Posted by Salini Rana 6 years, 2 months ago
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Posted by Daggi Rime 6 years, 2 months ago
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Posted by Pragati Jain 6 years, 2 months ago
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Yogita Ingle 6 years, 2 months ago
The given point is P (4, -3).
Distance of point P from x-axis is -3 units.
Distance of point P from y-axis is 4 units.
Distance of point P from origin = OP, where O is the origin.
From P draw line A perpendicular to x-axis.
You can observe that OAP is a right angled triangle with OA = 4 units, AP = -3 units.
So, using Pythagoras theorem,
OP2 = 42 + (-3)2 = 25
=> OP = 5 units
Hence, the distance of point P from origin is 5 units.
Posted by Nandhu Siva 6 years, 2 months ago
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Nandhu Siva 6 years, 2 months ago
Posted by Shree Ravi 6 years, 2 months ago
- 2 answers
Posted by Meenaxi Misal 6 years, 2 months ago
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Gaurav Seth 6 years, 2 months ago
Theorem (Euclid’s Division Lemma):
For a pair of given positive integers ‘a’ and ‘b’, there exist unique integers ‘q’ and ‘r’ such that
a=bq+ra=bq+r, where 0≤r<b0≤r<b
Explanation:
Thus, for any pair of two positive integers a and b; the relation
a=bq+ra=bq+r, where 0≤r<b0≤r<b
will be true where q is some integer.
Posted by Kashish Sikka 6 years, 2 months ago
- 1 answers
Gaurav Seth 6 years, 2 months ago
Let √2 be a rational number
Therefore, √2= p/q [ p and q are in their least terms i.e., HCF of (p,q)=1 and q ≠ 0
On squaring both sides, we get
p²= 2q² ...(1)
Clearly, 2 is a factor of 2q²
⇒ 2 is a factor of p² [since, 2q²=p²]
⇒ 2 is a factor of p
Let p =2 m for all m ( where m is a positive integer)
Squaring both sides, we get
p²= 4 m² ...(2)
From (1) and (2), we get
2q² = 4m² ⇒ q²= 2m²
Clearly, 2 is a factor of 2m²
⇒ 2 is a factor of q² [since, q² = 2m²]
⇒ 2 is a factor of q
Thus, we see that both p and q have common factor 2 which is a contradiction that H.C.F. of (p,q)= 1
Therefore, Our supposition is wrong
Hence √2 is not a rational number i.e., irrational number.
Posted by Thejaswini Prakash 6 years, 2 months ago
- 1 answers
Gaurav Seth 6 years, 2 months ago
SecA+tanA=p ----------------------------(1)
We know that,
sec²A-tan²A=1
or, (secA+tanA)(secA-tanA)=1
or, p(secA-tanA)=1
or, secA-tanA=1/p -----------------------(2)
Adding (1) and (2) we get,
2secA=p+1/p
or, secA=(p²+1)/2p
∴, cosA=1/secA=2p/(p²+1)
∴, sinA=√(1-cos²A)
=√{1-4p²/(p²+1)²
=√{(p²+1)²-4p²}/(p²+1)²
=√(p⁴+2p²+1-4p²)/(p²+1)
=√(p²-1)²/(p²+1)
=(p²-1)/(p²+1) (Proved)
Posted by Rajesh Chaudhary 6 years, 2 months ago
- 1 answers
Praveen Mehta 6 years, 2 months ago
Posted by Diya Paul 6 years, 2 months ago
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Posted by Diya Paul 6 years, 2 months ago
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# Mission Lbsnaa?? 6 years, 2 months ago
1Thank You