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  • 0 answers
  • 2 answers

Roshan Jain 6 years, 2 months ago

n2

Gaurav Seth 6 years, 2 months ago

Given that,

S7 = 49
S17 = 289
S7

 = 7/2 [2a + (n - 1)d]
S7 = 7/2 [2a + (7 - 1)d]
49 = 7/2 [2a + 16d]
7 = (a + 3d)
a + 3d = 7 ... (i)
Similarly,
S17 = 17/2 [2a + (17 - 1)d]
289 = 17/2 (2a + 16d)
17 = (a + 8d)
a + 8d = 17 ... (ii)
Subtracting equation (i) from equation (ii),
5d = 10
d = 2
From equation (i),
a + 3(2) = 7
a + 6 = 7
a = 1
Sn = n/2 [2a + (n - 1)d]
= n/2 [2(1) + (n - 1) × 2]
= n/2 (2 + 2n - 2)
= n/2 (2n)
= n

  • 2 answers

Aadya Singh ? 6 years, 2 months ago

No, we can't multiply with 0.

Priyanshu Sinha 6 years, 2 months ago

We can't equate a problem by multiplying 0 on both side because, when We multiply a number on both side, The division of both the number should be equal to 1. For example;. 3x+y=k. If we multiply 0 by both side. 0(3x+y)=0k. Here the division of 0 by 0 is undefined in maths .0/0 is indeterminate means it can't be defined
  • 2 answers

Priyanshu Sinha 6 years, 2 months ago

No it is not wrong

Moxit Rewar 6 years, 2 months ago

Please check your question. I think it's wrong???
  • 3 answers

Moxit Rewar 6 years, 2 months ago

By finding the value of x and y

Viraj Baldaniya 6 years, 2 months ago

If equation is x+y=2 then how can you find thier quadrant?

Dhruv ... 6 years, 2 months ago

By findind the value of ordinate and abscissa i.e.(x,y)
  • 1 answers

Rachit Agarwal 6 years, 2 months ago

Because if multiply anything with 0 we will always get 0 Like 10/5 = 5+5/5= 5/5+5/5= 1+1=2 But 10/0 we cant express in the form of zero There will be infinite zero . Thats why we say its not defined
  • 5 answers

Dhruv ... 6 years, 2 months ago

Number in the form of p/q where q is not equal to zero...and p and q are integers.

Mona Mittal 6 years, 2 months ago

The numbers of the form p/q ,where p and q are integers, and q is not 0 are called rational no.

Aadya Singh ? 6 years, 2 months ago

The number written in the form of p/q , where p and q are integers and q isn't equal to 0.

Payal .....?? 6 years, 2 months ago

No. Which we can write in the form of p/q wher p and q are integers and q is not equal to 0

Secret Girl... ? 6 years, 2 months ago

Those nos that can be expressed as questient or fraction p/q of 2 integers
  • 4 answers

Harshal Dhawale 6 years, 2 months ago

Refer RD Sharma

Pushkar Sahi 6 years, 2 months ago

maths ka har formula ache se yad kar lo uske baad bahut easy ho jayega

Bhavi Chauhan 6 years, 2 months ago

Maths is easy.Pahle ncert complete kro uske baad exemplar and support material provided by cbse online...this will help u

Shristi Arya?? 6 years, 2 months ago

Padhkar
  • 2 answers

Rachit Agarwal 6 years, 2 months ago

You just see ch 6 triangles and theorem 6.1

Pushkar Sahi 6 years, 2 months ago

bahut lamba question h bhai apna number de do bhej denge
  • 1 answers

Bhavi Chauhan 6 years, 2 months ago

An=6n+5 An+1=6n+5+1 =6n+6
  • 3 answers

Ansh Singh Singh 6 years, 2 months ago

Cos^2 67- Sin^2 23 Cos^2(90-23) - Sin^2 23 Sin^2 23 -Sin^2 23 0 Hence proved...

Pushkar Sahi 6 years, 2 months ago

cos sq67 - sin sq23 =cos sq(90-23) - sin sq23 =sin sq23-sin sq23 =0

Payal .....?? 6 years, 2 months ago

Cos²a 67 - cos²(90 - 23).................. Cos²a67 - cos² 67................ 0 is the answer
  • 20 answers

Secret Girl... ? 6 years, 2 months ago

Excuse me!!

Piyush Patidar 6 years, 2 months ago

Mere answers reply kro

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Maine kr diya answer

Pushkar Sahi 6 years, 2 months ago

polarity wala question h

Pushkar Sahi 6 years, 2 months ago

science wala me dekhiye

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Question kya h??

Pushkar Sahi 6 years, 2 months ago

mera answer

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Sab gye ..!! Ok...bye..

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Hello payal...?

Payal .....?? 6 years, 2 months ago

Hii. Shreya and ziddi ji.... ???

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Kya question h apka..??

Pushkar Sahi 6 years, 2 months ago

mera science wala question ka answer kisi ne nahi diya mujhe??????

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Maine august mai join kiya h isko

Ziddi Akshit?????? ??? 6 years, 2 months ago

Jo marzi keh lo #pushkar

Ziddi Akshit?????? ??? 6 years, 2 months ago

Tum nayi ho kya yaha par

Pushkar Sahi 6 years, 2 months ago

acha ye app personal chat ke liye h kya

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Ziddi..???

Payal .....?? 6 years, 2 months ago

Nhi... But itna ziddi kon hota hhh...... ???????

Ziddi Akshit?????? ??? 6 years, 2 months ago

Hasne ki kya baat h

Payal .....?? 6 years, 2 months ago

Ziddi....??
  • 4 answers

Aaditya Choudhary 6 years, 2 months ago

Cos 1

Shreya... #Be Positve Be Happy 6 years, 2 months ago

Cos A

Payal .....?? 6 years, 2 months ago

CosA....

Manak Fangirl 6 years, 2 months ago

Sin (90-A) = Cos A
  • 5 answers

Ansh Singh Singh 6 years, 2 months ago

Cosec(4A)=Sec(A-20) Cosec(4A)=Sec{90-(A-20)} Cosec(4A)=Cosec(90-A+20) Cosec(4A)=Cosec(110-A) 4A=110-A 5A=110 A=22 Solved....

Sakshi Banitia 6 years, 2 months ago

cosec(4a)=sec(a-20) sec(90-4a)=sec(a-20) 90-4a=a-20 -4a-a=-20-90 -5a=-110 a=22

Manak Fangirl 6 years, 2 months ago

A=22

Payal .....?? 6 years, 2 months ago

Cosec (4a) = cosec (90-(a- 20))......... Cosec (4a) = cosec (110 - a)......... (4a) = 110-a...... 5a=110..... a= 22...... Hope it will help u....
22
  • 3 answers

Ansh Singh Singh 6 years, 2 months ago

LHS= Sin^4A- Sin^2A Taking Sin^2A common we get, Sin^2A( Sin^2-1) (1-cos^2A) (-cos^2A) On multiplying we get, -Cos^2A + Cos^4A Cos^4A - Cos^2A Hence proved.

Payal .....?? 6 years, 2 months ago

Lhs........... So...... Sin⁴a -sin²a ===== (1-cos²a) ² - 1- cos²a........ 1- cos⁴a -1-cos²a...... Cos⁴a -cos²a.... Hence proved. ..

Payal .....?? 6 years, 2 months ago

Ye prooff krna hhh n
  • 1 answers

Madhup Chandrashekhar 6 years, 2 months ago

cot=7/8 (1+sin)(1-sin)/(1+cos)(1-cos) =1^2-sin^2/1^2-cos^2 =cos^2/sin^2 [sin^2+cos^2=1] =cot^2 =(7/8)^2 49/64
  • 8 answers

Ansh Singh Singh 6 years, 2 months ago

A=2 D=5 T10 = A+(n-1)D 2+9*5 2+45 47

Anmol Tyagi 6 years, 2 months ago

A=2,d=5,n=10 an=? By using this formula,,an=a+(n-1)d =2+(10-1)5 =2+(9)5 =2+45 =47

Manak Fangirl 6 years, 2 months ago

47

Pushkar Sahi 6 years, 2 months ago

a=2, d=5 , T10=? we know, Tn= a+(n-1)d T10=2+(10-1)5 =2+9*5 =2+45 =47

Madhup Chandrashekhar 6 years, 2 months ago

a=2 d=t2-t1=7-2=5 n=10 T10=a+(n-1)d =2+(10-1)5 =2+45 =47

Kunal Lambha 6 years, 2 months ago

47

Payal .....?? 6 years, 2 months ago

Hiii
47
  • 1 answers

Madhup Chandrashekhar 6 years, 2 months ago

LHS = tanA/1+secA-tanA/1-secA = tanA-tanAsecA-(tanA+tanAsecA)/1^2-sec^2 = -2tanAsecA/-tan^2 [tan^2+1=sec^2] = 2secA/tanA =2cosecA
  • 2 answers

Gaurav Seth 6 years, 2 months ago

Basic Proportionality Theorem was first stated by Thales, a Greek mathematician. Hence it is also known as Thales Theorem. Thales first initiated and formulated the Theoretical Study of Geometry to make astronomy a more exact science. What is this theorem that Thales found important for his study of astronomy? Let us find it out.


Basic Proportionality Theorem (can be abbreviated as BPT) states that, if a line is parallel to a side of a triangle which intersects the other sides into two distinct points, then the line divides those sides in proportion.


Basic Proportionality Theorem

In the figure alongside, if we consider DE is parallel to BC, then according to the theorem,


ADBD=AECE


Let’s not stop at the statement, we need to find a proof that its true. So shall we begin?

PROOF OF BPT


Given: In  ΔABC, DE is parallel to BC


Line DE intersects sides AB and PQ in points D and E, such that we get triangles A-D-E and A-E-C.


To Prove: ADBD=AECE


Construction: Join segments DC and BE


Proof:


In ΔADE and ΔBDE,


A(ΔADE)A(ΔBDE)=ADBD                 (triangles with equal heights)


In ΔADE and ΔCDE,
A(ΔADE)A(ΔCDE)=AECE                  (triangles with equal heights)
Since ΔBDE and ΔCDE have a common base DE and have the same height we can say that,
A(ΔBDE)=A(ΔCDE)
Therefore,
A(ΔADE)A(ΔBDE)=A(ΔADE)A(ΔCDE)
Therefore,
ADBD=AECE

Aadya Singh ? 6 years, 2 months ago

If a line is drawn parallel to 1 side of a traingle to intersect the other 2 sides in distinct point, then the other 2 sides are divided in the same ratio.
  • 0 answers

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