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Ask QuestionPosted by Madhav Jariwala 6 years, 2 months ago
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Posted by Ha R Meet 6 years, 2 months ago
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Harsh Mishra 6 years, 2 months ago
Answer Copied From www.brainly.com
mayank1524 Expert
Let unit digit = x
Tens digit = y
Number will 10 times the tens digit + unit times the unit digit
Hence number will 10 y + x
Sum of digits are 9
So that
X + y = 9 ………….(1)
nine times this number is twice the number obtained by reversing the order of the digits
9 (10 y + x ) = 2 (10 x + y )
90 y + 9 x = 20 x + 2y
88 y – 11 x = 0
Divide by 11 we get
8 y - x = 0 …………..(2)
X + y = 9 ………….(1)
Adding both equations we get
9 y = 9
Y = 9/9 = 1
Plug this value in equation first we get
X+ y = 9
X + 1 = 9
X = 8
So our original number is 10 y + x = 10*1 + 8 = 18
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Harsh Mishra 6 years, 2 months ago
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Yogita Ingle 6 years, 2 months ago
Let’s find mean of the data using assumed mean method.
We are using assumed mean method to avoid miscalculation and false answer, as xi's are large in this question.
First, construct a table for ease of calculation.
Mean is given by
{tex}\bf{Mean=A+\frac{\Sigma f_id_i}{\Sigma f_i}}{/tex}
Where A = assumed mean
{tex}\bf{Mean=325+\frac{-600}{50}}{/tex}
Mean = 325 – 12 = 313
Thus, mean daily wages of the workers is Rs. 313.
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