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Ask QuestionPosted by Aditya Kumar 6 years, 2 months ago
- 7 answers
?❤Armààñ Màlík'S Fàñ❤? 6 years, 2 months ago
?❤Armààñ Màlík'S Fàñ❤? 6 years, 2 months ago
?❤Armààñ Màlík'S Fàñ❤? 6 years, 2 months ago
Posted by ?❤Armààñ Màlík'S Fàñ❤? 6 years, 2 months ago
- 2 answers
Gaurav Seth 6 years, 2 months ago
Let the age of A = x
age of B = x+2
since, A's father D is twice as old as A
So, age of D = 2×x = 2x
and since B is twice as old as his sister
So, age of C = age of B / 2 = (x+2)/2
according to the question,
The ages of D and C differ by 40yrs.
it means,
age of D - age of C = 40
=> 2x - [(x+2)/2] = 40
=> 2x - (x+2)/2 = 40
=> 4x/2 - (x+2)/2 = 40
=> (4x - x + 2)/2 = 40
=> 3x+2/2 = 40
=> 3x + 2 = 40 × 2
=> 3x = 80 - 2
=> x = 78/3
= 26
So, age of A = x = 26 years
age of B = x + 2 = 26 + 2 = 28 years
Posted by Prince Sharma 6 years, 2 months ago
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- 1 answers
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- 4 answers
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- 2 answers
Posted by Pushkar Sahi 6 years, 2 months ago
- 1 answers
Sia ? 6 years, 2 months ago
Let us assume that <m:omath><m:r>√</m:r></m:omath>3 is rational.
That is, we can find integers a and b (<m:omath><m:r>≠0)</m:r></m:omath> such that a and b are co-prime
{tex}\style{font-family:Arial}{\begin{array}{l}\sqrt3=\frac ab\\b\sqrt3=a\\on\;squaring\;both\;sides\;we\;get\\3b^2=a^2\end{array}}{/tex}
Therefore, a2 is divisible by 3,
it follows that a is also divisible by 3.
So, we can write a = 3c for some integer c.
Substituting for a, we get 3b2 = 9c2, that is, b2 = 3c2
This means that b2 is divisible by 3, and so b is also divisible by 3
Therefore, a and b have at least 3 as a common factor.
But this contradicts the fact that a and b are co-prime.
This contradiction has arisen because of our incorrect assumption that <m:omath><m:r>√</m:r></m:omath>3 is rational.
So, we conclude that <m:omath><m:r>√</m:r></m:omath>3 is irrational.
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Aadya Singh ? 6 years, 2 months ago
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