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  • 5 answers

Khwahis Parveen 2 years, 4 months ago

HCF of 12 and 14 12=2×2×3 14=2×7 (In both 2 is common so HCF is 2)

Ladli Kasaudhan 2 years, 5 months ago

2

L.V.A Naidu 2 years, 5 months ago

2

Sakshi Kolekar 2 years, 5 months ago

2

Sachin Rajpoot 2 years, 5 months ago

2
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Sakshi Kolekar 2 years, 5 months ago

75

Tanishk Chauhan 2 years, 5 months ago

75
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Sakshi Kolekar 2 years, 5 months ago

Let , √2 is rational number √2=a,b(a,b,are coprime) √2b=a Squaring on both sides (√2b²)=a² 2b²=a²—1 b²=a²/2 'a²'is divisible by '2' 'a' is divisible by '2' a/2=m a=2m Putting in eq 1 2b²=a² 2b²=(2m)² 2b²=4m² b²=4m²/2 b²=2m² b²/2=m² m²= b²/2 'b²'is divisible by '2' 'b'is divisible by '2' But,a and b are coprime Our assumption was wrong Therefore, √2 is irrational number
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L.V.A Naidu 2 years, 5 months ago

24=1032*2+408*p 24=2064+408p -408p=2064-24 -408p=2040 p=2040/-408 p=-5

L.V.A Naidu 2 years, 5 months ago

-5

Santosh Sahani 2 years, 5 months ago

P=5.05882353
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  • 4 answers

Sakshi Kolekar 2 years, 5 months ago

Here , x=1, y=2 Now we will put values in equation 2x+ay=8 Then , we have to find the value of a=? In equation , (2×1)+a×2=8 2+2a=8 2a=8-2 2a=6 2a/6 a=3 Therefore,a=3

Virat Chauhan 2 years, 5 months ago

Here a=3

Ragini Dushadh 2 years, 5 months ago

Here given, x=1 and y=2 Now putting the value of x and y in equation 2x+ay=8 2*1+a*2=8 2+2a=8 2a=8-2 2a=6 a=6/2 a=3

Bhavya Raj 2 years, 5 months ago

Here, x=1 &y=2 A/q 2×1+2a=8 = 2a=8-2 = a=6/2 = a=3
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Ashish Kumar Singh 2 years, 5 months ago

n m + m n = mn m 2 +n 2 = mn (m+n) 2 −mn ⇒ n m + m n = mn (m+n) 2 −1.....(1) Given that m and n are the zeroes of the polynomial 3x 2 +11x−4. Therefore, Sum of zeroes =m+n=− a b =− 3 11 Product of zeroes =mn= a c = 3 −4 ∴ n m + m n = ( 3 −4 ) ( 3 −11 ) 2 −1=− 16 121 −1=− 16 137 Hence the value of n m + m n wil be − 16 137 .
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Haripriya K 2 years, 5 months ago

4x²-4x-1
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L.V.A Naidu 2 years, 5 months ago

LCM =pq HCF=1

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