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  • 2 answers

Sanjay Mahaddev 1 year, 4 months ago

Answer u = 3√3 - 4√2 v = √3(4-√6)

Sanjay Mahaddev 1 year, 4 months ago

It's difficult to type √ numbers
  • 1 answers

Manas Soni 1 year, 4 months ago

A(-3,10) A(x1, y1) B(6,-8) B(x2,y2) R(-1,6) R(x,y) Let the ratio m1:m2 be k:1 So, R(x)=(m1x2+m2x1)÷m1+m2 -1=[k×(6)+1×(-3)]÷k+1 By cross multiplication -1(k+1)=6k-3 -k-1=6k-3 By transportation -k-6k=-3+1 -7k=-2 7k=2 K=2/7 K/1=2/7 K:1=2:7 As we know that k:1=m1:m2 So, 2:7 is ratio
  • 0 answers
  • 2 answers

Navyashree Sunar 1 year, 5 months ago

Sir i am not understanding Trigonometry so can give any suggestions

Navyashree Sunar 1 year, 5 months ago

Gm sir
  • 1 answers

Anup Kumar 1 year, 5 months ago

Not a quadratic equation
  • 1 answers

Ritika Singh 1 year, 5 months ago

Let 2√3-1 be a rational number. 2√3-1= p/q [ where p and q are co-prime integers ]. 2√3 = p/q + 1. 2√3 = p + q / q. √3 = p + q / q × 2. √3 = p + q / 2q. Here, Rational = Irrational. This is not possible. Hence, our assumption was wrong. Therefore, 2√3-1 is irrational. Hope it helps you ✨.
  • 1 answers

Jashra Kausar 1 year, 5 months ago

There is nothing
  • 4 answers

Lvprt Ranu 1 year, 4 months ago

I need answer plz

Jasmine Class 10 1 year, 4 months ago

pl

Jasmine Class 10 1 year, 4 months ago

no get answer

Jasmine Class 10 1 year, 4 months ago

answer
  • 1 answers

Aditya Ranjan 1 year, 5 months ago

2.225
  • 2 answers

Abhinav Jain 1 year, 5 months ago

40 km/hr

Rohit Sharma 1 year, 5 months ago

Let the speed of the train be x km/hr. Then Time taken to travel a distance of 480km=x480​hr Time taken by the train to travel a distance of 480km with the speed (x−8)km/hr=x−8480​hr It is given that if the speed had been 8km/hr less, then the train would have taken 3 hours more to cover the same distance ∴x−8480​=x480​+3 ⇒x−8480​−x480​=3⇒x(x−8)480(x−x+8)​=3⇒x(x−8)480×8​=3 ⇒3x(x−8)=480×8⇒x(x−8)=160×8⇒x2−8x−1280=0
  • 1 answers

Rohit Sharma 1 year, 5 months ago

Class intervalFrequencyCumulative frequency  15−202 2  20−254 6  25−3018 24  30−3521 45  35−4033 78  40−4511 89  45−503 92  50−556 98  55−602 100 ⇒  N=100 then, 2N​=50 The cumulative frequency just greater then 50 is 78. ∴  Median class =35−40 Here, l=35,h=5,f=33,cf=45 Median=l+f2N​−cf​×h ⇒  Median=35+3350−45​×5 ⇒  Median=35+3325​=35.76
  • 2 answers

Vivek Solanki 1 year, 5 months ago

5x²-29x+20 5x²-25x-4x+20 5x(x-5)-4(x-5) (x-5) (5x-4) X=5,X=4/5 Let alpha be 5 and bita be 4/5 Alpha +bita =5+4/5 =24+4/5 =29/5 -b/a =-(-29)/5 =29/5 Hence proved,alpha +bita =-b/a Alpha bita =5(4/5) =4 c/a =20/5 =4 Hence proved, alpha bita =c/a

Vivek Solanki 1 year, 5 months ago

Alpha =5 and bita =4/5
  • 1 answers

Debayan Kar 1 year, 5 months ago

Hcf(51,85)=17 is the greatest length of tape
  • 1 answers
X2+2y3-1 X-y3=3
  • 2 answers

Deepesh Singh 1 year, 5 months ago

By elimination method 3x + y = 11 x - y = 1

Deepesh Singh 1 year, 5 months ago

Value of x will be 3
  • 2 answers

Nashi Norah 1 year, 5 months ago

1098

Nashi Norah 1 year, 5 months ago

1079
  • 1 answers

Abhinav Jain 1 year, 5 months ago

√(x2-x1)²(y2-y1)²

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