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  • 1 answers

Swaran Singh 2 years, 4 months ago

Let assume that √2 is an rational number and √2/1 = a/b , where a and b are integers and co-prime , b ≠0 . b√2 = a By squaring both sides, we get 2b²= a² _ (1) Here, a² is divisible by 2 and a also divisible by 2. Now , let a=2c , where c is an integer . By squaring both sides, we get a²= 4 c² By Substituting it in eq ( 1) 2b²= 4c² b² = 2c² Here , b² is divisible by 2 , also b is divisible by 2. Therefore, 2 is a common factor of a and b . This contradicts the fact that a and b are not co - prime. Therefore , our assumption is wrong.
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Khwahis Parveen 2 years, 4 months ago

Firstly, 615-5= 610 963-7= 956 find the HCF of 610 and 956 then you get the answer
  • 1 answers

Mridupawan Patiri 2 years, 4 months ago

sin(90°-65°) cos 65°+cos(90°-65°) sin65° cos65°cos65°+sin65°sin65° (sin(90°-a) =cosa) (cos(90-a) =sina)
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Khwahis Parveen 2 years, 4 months ago

Let 16+17√3 be rational and let it's simplest form be p/q where p and q are integers and q≠0. Then, 16+17√3=p/q 17√3=p/q – 16 √3=p/q–16/17 …(i) Now, p/q is rational →(p/q–16/17) is rational [… difference of rational is rational] √3 is rational … from (i) The contradiction arises by assuming that √3 is rational. Hence, 16+17√3 is irrational.
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Ajay Kumar Sahu 2 years, 5 months ago

Let Y=0,0+X=14 x=14

Janeesh Kumar 2 years, 5 months ago

X+y=14 Let x=0 0+y=14 Y=0-14 Y=-14

Revati Shegaonkar 2 years, 5 months ago

RRR
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Anmol Kaur 2 years, 5 months ago

Let the 1√6+5 is rational number . 1√6+5=p/q 1√6=p/q-3 1√6=p/q-3q √1=p-3q/2q L.H.S = irrational number R.H.S = rational number L.H.S =|= R.H.s Our supposition is wrong . 1√6+5 is not rational number . 1√6+5 is an irrational number .
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Khwahis Parveen 2 years, 4 months ago

24÷2×100 →12×100 →1200(answer)

Ladli Kasaudhan 2 years, 5 months ago

1200

Anjali Kumari 2 years, 5 months ago

1200
  • 1 answers

Jaat Jaat 2 years, 4 months ago

The first equation: x-1/y =1/3 Do the cross multiplication It become: 3x-3= y 3x-y=3 (first equation) The second equation: x/y+8=1/4 Do the cross multiplication It become: 4x=y+8 4x-y=8 (second equation) Then solve it with elimination or substitution method.
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