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Yogita Ingle 6 years, 2 months ago
Let a be the first term and d be c.d. of the A P .Then
Sm=n
n= m/2{2a+ (m-1) d}
2n= 2am+ m ( m-1)d. ........(1)
And
S n= m
m= n / 2{2a+ (n-1) d}
2m = 2an+ n (n-1) d. ...........(2)
Subtracting eq.(2)- (1), we get
2a (m -1) + { m ( m - 1)- n ( n-1)}d = 2 n - 2 m
2a (m-n) + {(m ^ 2-n ^ 2) - ( m-n ) }d = -2(m-n)
2a + (m+n-1) d = -2. [On dividing both sides by ( m - n)]………(3)
Now,
Sm + n = m + n / 2{2a + (m + n - 1) d}
Sm + n = m + n / 2 (-2) ………[using (3)]
Sm + n= - ( m + n)
Hence Proved.
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(y/r)^2+(x/y)^2=(y^2/r^2+x^2/r^2)
(x^2+y^2)/r^2 = r^2/r^2
=1
Sin^2€+cos^2€=1
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Ajay ???? 6 years, 2 months ago
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