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Ankesh ...... 6 years, 2 months ago
___ Alone _____ 6 years, 2 months ago
Priya Singh 6 years, 2 months ago
Posted by Ankesh ...... 5 years, 11 months ago
- 100 answers
Ankesh ...... 6 years, 2 months ago
Ankesh ...... 6 years, 2 months ago
Ankesh ...... 6 years, 2 months ago
Ankesh ...... 6 years, 2 months ago
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Priya Singh 6 years, 2 months ago
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Ankesh ...... 6 years, 2 months ago
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Ankesh ...... 6 years, 2 months ago
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Shreya ... 6 years, 2 months ago
Shreya ... 6 years, 2 months ago
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Ankesh ...... 6 years, 2 months ago
Ankesh ...... 6 years, 2 months ago
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Ankesh ...... 6 years, 2 months ago
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Posted by Vishnu Kumar 6 years, 2 months ago
- 1 answers
Chitresh Khandal 6 years, 2 months ago
Posted by Dofld Mittal 6 years, 2 months ago
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Posted by Roshan Singh 6 years, 2 months ago
- 3 answers
Posted by Roshan Singh 6 years, 2 months ago
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Parishi Thada 6 years, 2 months ago
Posted by Parthiv K.Jyothish 6 years, 2 months ago
- 3 answers
Yogita Ingle 6 years, 2 months ago
A non-leap year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364 days .
365– 364 = 1day extra.
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 sundays = 1 / 7.
∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7.
Posted by Abhay Mishra 6 years, 2 months ago
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Posted by Aman Verma 6 years, 2 months ago
- 1 answers
Roshan Singh 6 years, 2 months ago
Posted by Satender Rathour 6 years, 2 months ago
- 4 answers
Yogita Ingle 6 years, 2 months ago
Cut a right circular cone with a plane parallel to the base of the cone, then the solid shape between the plane and the base of the cone is called the frustum of a cone.
Volume of the frustum of a cone = (1/3) πh (r12 + r22 + r1 r2)
Posted by Shraddha ☺️☺️ 6 years, 2 months ago
- 2 answers
Kanti Devi 6 years, 2 months ago
Posted by Sreeya Mohapatro 6 years, 2 months ago
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Shivani Sharma 6 years, 2 months ago
Posted by Mrunalini Awasare 6 years, 2 months ago
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Shivani Yadav 6 years, 2 months ago
Silent Girl Happy 6 years, 2 months ago
Posted by Ritika Kaushik 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
We have seen that a quadratic polynomial is of the form:
p(x):ax2+bx+c,a≠0,
We assume that a, b and c are real numbers. In general, this polynomial has two zeroes. For example, the polynomial p(x):x2−3x+2 has the zeroes x=1,2
.For some quadratic polynomials, the two zeroes might be equal. For example, the polynomialp(x):x2−4x+4
can be rewritten as p(x):(x−2)2. Thus, we can say that this polynomial has the two zeroes: x=2,2,
which happen to be identical.
There might also be quadratic polynomials which have no real zeroes. Consider the polynomial p(x):x2+1
. For no real value of x can this polynomial take zero value, which means that this has no real zeroes. Note that this does not mean that the polynomial does not have any zeroes. Of course this polynomial has (two) zeroes – however, those zeroes are just not real numbers.
Posted by Ritika Kaushik 6 years, 2 months ago
- 1 answers
Himanshu Kumar 6 years, 2 months ago
Posted by Mrunalini Awasare 6 years, 2 months ago
- 1 answers
Mrunalini Awasare 6 years, 2 months ago
Posted by Pardeep Khullar 6 years, 2 months ago
- 2 answers
Sunita Jagdale 6 years, 2 months ago
Posted by Mohd Imad 6 years, 2 months ago
- 1 answers
Posted by Sachin Singh 6 years, 2 months ago
- 2 answers
Posted by Avani Sompura 6 years, 2 months ago
- 1 answers
Chitresh Khandal 6 years, 2 months ago
Posted by Jinay Shah 6 years, 2 months ago
- 3 answers
Yogita Ingle 6 years, 2 months ago
Cut a right circular cone with a plane parallel to the base of the cone, then the solid shape between the plane and the base of the cone is called the frustum of a cone.
e.g. Flower pots have a shape as the frustum of a cone.
The surface area and the volume of the frustum of a cone can be calculated using standard formulae.
CSA of the frustum of a cone = πl( r1 + r2).
where r1 = radius of the larger circular face of the frustum, r2 = radius of the smaller circular face of the frustum, and l = slant height of the frustum.l = h2+(r1-r2)2 and h is the height of the frustum.
TSA of a frustum of a cone = πl(r1 + r2) + πr12 + πr22
Posted by Suman Verma 6 years, 2 months ago
- 2 answers
Posted by Simi Pagaria 6 years, 2 months ago
- 3 answers
Yogita Ingle 6 years, 2 months ago
Given numbers are 455 and 42
Here, 455 > 42
So, we divide 455 by 42
By using Euclid’s division lemma, we get
455 = 42 × 10 + 35
Here, r = 35 ≠ 0.
On taking 42 as dividend and 35 as the divisor and we apply Euclid’s division lemma, we get
42 = 35 × 1 + 7
Here, r = 7 ≠ 0
So, on taking 35 as dividend and 7 as the divisor and again we apply Euclid’s division lemma, we get
35 = 7 × 5 + 0
The remainder has now become 0, so our procedure stops. Since the divisor at this last stage is 7, the HCF of 455 and 42 is 7.
Posted by Nikitha Chowdary 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
3x-y-5=0
so 3x-y=5 (1st equation)
now multiply the equation by 2
(3x-y=5)×2
= 6x-2y=10
but as per the question
6x-2y-p=0
6x-2y=p
substitute the equations
p=10
Posted by Babita Rathor 6 years, 2 months ago
- 1 answers

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