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  • 0 answers
  • 2 answers

Varun Jakhar 5 years, 4 months ago

Root 7

Yogita Ingle 5 years, 4 months ago

3x² + 11 + 10 =  0

3x² + 21  = 0

3 (x2 + 7) = 0

x2 + 7 = 0

x2 = 7

x= √7

  • 1 answers

Vaishnavi Borade 5 years, 4 months ago

Q is of the form 2 raised to n multiplied by 5 raise to m and m and n are non negative
  • 3 answers

Ishika ? 5 years, 4 months ago

Mera toh bahaut krab....what about you☺️

Sana(Silent Love).. ?? 5 years, 4 months ago

Nhi saare frnds ki yaad aa rhi h..

Sana(Silent Love).. ?? 5 years, 4 months ago

Mt poocho ... aapka kaisa chal rha h
  • 5 answers

Lucifer ? Morningstar? 5 years, 4 months ago

Sorry, but it secret.

Sana(Silent Love).. ?? 5 years, 4 months ago

Nothing

Sana(Silent Love).. ?? 5 years, 4 months ago

What's your real name..

Lucifer ? Morningstar? 5 years, 4 months ago

Hey what's happen sna? Why are u sad?

Sana(Silent Love).. ?? 5 years, 4 months ago

Ye kya h
  • 2 answers

Anshak . 5 years, 4 months ago

Bro 0/0 is infinity, not 2 So, it is not possible to prove that........ Question is not valid

Vishvajit Yadav 5 years, 4 months ago

solution from LHS let (100-100)/(100-100) = ( 10^2-10^2)/10(10-10) = ( 10+10)(10-10)/10(10-10). {a^2-b^2=(a+b) (a-b )} = 20/10 = 2 RHS prove
  • 1 answers

Vishvajit Yadav 5 years, 4 months ago

solution= from LHS = sin^2@+cos^2@ = (p/h)^2+(b/h)^2 = (p/h×p/h)+(b/h×b/h) = p^2/h^2+b^2/h^2 = p^2+b^2/h^2 = h^2/h^ =1 RHS prove
  • 1 answers

Vivek Agnihotri 5 years, 4 months ago

H2 = P2 + B2
  • 2 answers

Ayush Pandey 5 years, 4 months ago

Number which can be written in the form of p/q where p and q are integers and q does not equal to 0.

Khushi Gangwani 5 years, 4 months ago

Any number that can be written in p/q form or in a fractional form is called a rational number
  • 2 answers

Anshika Dhankhar 5 years, 4 months ago

-1,0,1,2,3,4,5........

Gagandeep Singh 5 years, 4 months ago

1 2 3 4 5
  • 4 answers

Kyōka ( Demon Snow ) 5 years, 4 months ago

RD Sharma.

Ansh Chaudhary 5 years, 4 months ago

Standard math rd Sharma

Gagandeep Singh 5 years, 4 months ago

Rd Sharma

Khushi Jain 5 years, 4 months ago

RD sharma
  • 0 answers
  • 1 answers

Tanisha ?? 5 years, 4 months ago

This is the quadratic formula to find the value of x.
  • 2 answers

Kunal Thakur 5 years, 4 months ago

No, because first of all u can write 6n =2×3. you know that the digit can be possible end of zero that condition is necessary = (2×5). U can see clearly here this is not that co dition form

Vishvajit Yadav 5 years, 4 months ago

solution: no 6^0=1 6^1=6 6^2=36 6^3=216
  • 1 answers

Khushboo Tiwari 5 years, 4 months ago

( 1+cot ² @ = cosec ²@ ) sin ² @ (Cosec ² @ = 1/sin ²@ ) sin ²@ = 1 is your answer
  • 2 answers

Gagandeep Singh 5 years, 4 months ago

2m

? Pranali.A.P ? 5 years, 4 months ago

For some integer m, every even integer is of the form. Solution : We know that, even integers are 2,4,6… So, it can be written in the form of 2m.
  • 1 answers

Khushboo Tiwari 5 years, 4 months ago

Your new equation after simplyfy 3x² -x- 6 = 0 Zeros are 3 and -2 Sum of zeros 3 + (-2) =
  • 5 answers

Lucifer ? Morningstar? 5 years, 4 months ago

Option (b)

Rishi Kishore 5 years, 4 months ago

They have asked the possibilitys of the value r right. Not value of r and q. If u need options:- a)0,1,2,3. b)0,1,2,3,4,5. c)2,3,5. d)1,2,3.

Aditya Kumar Arya 5 years, 4 months ago

q=19 ,r=2

Ishita Khadpe 5 years, 4 months ago

Since, b=6 :. r=5

Lucifer ? Morningstar? 5 years, 4 months ago

r=8
  • 5 answers
Hi gud morning ??

Tina ? 5 years, 4 months ago

Good morning nisha?

Raman Upadhyay 5 years, 4 months ago

Good morning?

Ishika ? 5 years, 4 months ago

Good morning nisha....☺️

? Pranali.A.P ? 5 years, 4 months ago

Very fresh good morning ? nisha
  • 2 answers

Kritika Dhiman 5 years, 4 months ago

Non terminating but repeating

? Pranali.A.P ? 5 years, 4 months ago

It is a non terminating and repeating decimal
  • 2 answers

? Pranali.A.P ? 5 years, 4 months ago

Don't know

Vishal Saminathan 5 years, 4 months ago

.
  • 2 answers

Kunal Kumar 5 years, 4 months ago

If you have to find HCF or LCM of only two numbers then you can use the identity (LCM*HCF=a*b) So; b=(HCF *LCM)/a =(113*56952)/904 =7119

Nisha???????? Bharti 5 years, 4 months ago

let, a and b are the two numbers Where a =904 Lcm=56952, HCF=113 Formula (a×b)=LCM×HCF 904×b=56952×113 b=56952×113/904 b=56952/8 b=7119 Hence, the other number is 7119 ans___"

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