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Gaurav Seth 5 years, 4 months ago
FORMULA :
If the numbers a, b and c are in AP, then
b - a = c - b
=> 2b = a + c
SOLUTION :
The given three numbers (2p - 1), (3p + 1) and 11 are in AP.
Then,
2(3p + 1) = (2p - 1) + 11
=> 6p + 2 = 2p - 1 + 11
=> 6p + 2 = 2p + 10
=> 6p - 2p = 10 - 2
=> 4p = 8
=> p = 8/4
=> p = 2
So, the value of p is 2.
Then, the given numbers be
(2×2 - 1), (3×2 + 1) and 11
i.e., 3, 7 and 11.
So, we get an Arithmetic progression 3, 7, 11.
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Yogita Ingle 5 years, 4 months ago
3sin²20°-2tan²45°+2sin²70°
=3sin²20°-2×(tan45°)²+2{sin(90°×1)-20°}²
=3sin²20°-2×(1)²+2cos²20°
=3sin²20°+ 2cos²20°
Posted by Eramma Eachnal 5 years, 4 months ago
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Gagandeep Singh 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
x+y=14 ......... (i)
x-y=4 .......... (ii)
Adding (i) and (ii)
2x = 18
x = 18/2 = 9
Put x = 9 in (i)
9 + y = 14
y = 14 - 9
y = 5
Posted by Aishwarya Dhurgude 5 years, 4 months ago
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@S(Raj)Àĺì ???? 5 years, 4 months ago
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