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let the no. be x and x+1
then we have x²+(x+1)²=365
2x²+2x-364=0
x²+x-182=0
x²+14x-13x-182=0
(x+14)(x-13)=0
That gives x=13 Avoiding negative value
one number is 13 and other one 14.

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Posted by Ronak Sahu 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Iti Agarwal 5 years, 4 months ago

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Prove that 5 + √3 is an irrational number

Posted by Yashita Jaswal 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

Let us assume that 5 +√3 is rational.

Let ,
5 +√3 = r , where "r" is rational

5 + r = √3

Here,
LHS is purely rational.But,on the other hand ,RHS is irrational.
This leads to a contradiction.
Hence,5+√3 is irrational

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3x-5y-4=0 and 9x=2y+7

Posted by Preet Kaur 5 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Vishvajit Yadav 5 years, 5 months ago

3x-5y=4---------(1) 9x-2y=7---------(2) from Equation (2) we get, 9x-2y=7 9x=7+2y x=7+2y/9 putting the value of x in equation (1) 3x-5y=4 3×(7+2y/9)-5y=4 7+2y/3-5y=4 7+2y-15y =4 ________ 3 7-13y=. 4/1 ______ 3 cross multiplication 7-13y=12 -13y=12-7 -13y=5 13y =-5 y=-5/13 putting the value of y in eqution (3) x =7+2y/9 x=[7+2×(-5/13)]×1/9 x=[7-10/13]×1/9 x=[91-10/13] ×1/9 x=81/13×1/9 x=9/13 hence x=9/13and y-5/13

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Yogita Ingle 5 years, 5 months ago

3X - 5Y = 4----------(1)

9X - 2Y = 7-------------(2)

From EQUATION (1) we get,

3X - 5Y = 4

3X = 4+5Y

X = 4+5Y/3 -------------(3)

Putting the value of X in equation (2)

9X - 2Y = 7

9 × (4+5Y/3) - 2Y = 7

3(4+5Y) - 2Y = 7

12 + 15Y - 2Y = 7

13Y = 7 -12

13Y = -5

Y = -5/13

Putting the value of X in equation (3)

X = 4+5Y/3 => 3 + 5 × -5/13 = 3 - 25/13 /3

X = 39 - 25/13/3 = 14/13/3 => 14/13 × 1/3 => 14/9

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Samish Kumar 5 years, 5 months ago

y=5/17 and x=43/51

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Hi friends

Posted by Nisha???????? Bharti 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sana(Silent Love).. ?? 5 years, 5 months ago

Hii neha ????

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Sana(Silent Love).. ?? 5 years, 5 months ago

Hii ayush ??

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Drift? Boi? 5 years, 5 months ago

Hi nisha , sana , neha .??

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? Pranali.A.P ? 5 years, 5 months ago

Hello nisha and sana??

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Sana(Silent Love).. ?? 5 years, 5 months ago

Hii nisha ??

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If both the zeros of the quadratic polynomial ax2+bx+c are equal and opposite in sign, then find tge value of b

Posted by Aparna Pkannan 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sets chapter

Posted by Narendra Mecharapu 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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When cbse realese new slaybuss?for 2021 10th

Posted by Nishant Tiwari 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Nisha???????? Bharti 5 years, 5 months ago

After 3 july

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うぁた石フォrムーアオフむlちpぃかちおn

Posted by Sumedh Wahule 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sana(Silent Love).. ?? 5 years, 5 months ago

Not able to understand..

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Ishika ? 5 years, 5 months ago

Unable to understand this language........?????

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Jagrati Sharma?? 5 years, 5 months ago

What is this ???

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Sumedh Wahule 5 years, 5 months ago

のおね

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Where, abc are prime no. And xyz are Natural no. ,Then which of the following is true if p= q ? Explain with reason and process.. 1) a=b=c 2)x=y=z 3) a= 3x 4) a+c =2y

Posted by Life Is Full Of Struggle 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

? Pranali.A.P ? 5 years, 5 months ago

p = q Therefore , a^{x} b^{y} c^{z} = 3^{x} b^{4} 5^{z} Since a, b, c are prime numbers , We can directly compare the exponents. a = 3 and c = 5 . Also b^{y} = b^{4 , ==> y =4 Therefore a + c =8 = 2x 4 = 2y If p= q then a+c =2y

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If the zeroes of the polynomial xcube -3xsquare +x-1 are s/t , s and st , then the value of s is

Posted by Gloria Theressa 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

? Pranali.A.P ? 5 years, 5 months ago

the required value of a is 1 and that of b is ±√2.

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18,15 1/2,13,..,. ,-47 find the numbers of terms in each of the following APS

Posted by Rangaswamy Shreyas 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Aayush Rai 5 years, 5 months ago

here a=18 l=-47 d=2 1/2 l= a+[n-1]d now find n

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Which numbers lying between 1 and 100?

Posted by Priyanka Datt 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sundaram joined a company for a fixed salary per month. After few months, the management felt happy with his work and multiplied his salary by some n times. This happened every few months and his salary kept getting multiplied and he reached a salary of 360 zeds. Every time the management increased the salary by a prime number of times only and his initial salary was 5 zeds. Question: 1. How many times management did give incentive to Sundaram? 2. What is the maximum increment he got in his salary? 3. What is the least incentive he got? What would be his salary had he got the same type of increment every time?

Posted by Ruhi Rajput 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Levinsol Pawar 4 years, 6 months ago

nabbs

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How many times management did give incentive to Sundaram

Posted by Ruhi Rajput 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Trigonometry chapter

Posted by Aman Kumar 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Sana(Silent Love).. ?? 5 years, 5 months ago

Available in this app

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Aman Kumar 5 years, 5 months ago

ans

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Chapter trigono metry

Posted by Aman Kumar 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Find the zeroes of x²-x-2

Posted by Md.Aman Perwez 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Md.Aman Perwez 5 years, 5 months ago

x²-2x+x-2 x(x-2)1(x-2) (x-2)(x+1) x-2=0 x=2 x+1=0 x=(-1)

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What is zeroes

Posted by Yemte Samba 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Unknown One 5 years, 5 months ago

It means in what value of x we put in the given polynomial the result will be 0

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five year hence,the age of jocob will be there time that of son. five year ago. jacob's age was seven time that of his son. what are their present ages?

Posted by Jaya Sheela Victor 5 years, 5 months ago

CBSE > Class 10 > Mathematics

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Study Lover ?‍? ?‍? 5 years, 5 months ago

Let present age of jacob be x and his son be y. 5 year hence, Jacob age=x+5 and son age =y+5. A/q x+5=3(y+5) => x+5=3y+15 =>x=3y+10-------------------------(1) 5 year ago, Jacob age=x-5 and son age=y-5. A/q x-5=7(y-5) =>x-5=7y-35 =>3y+10=7y-30 (using (1)) =>(10)+30=7y-3y =>y=40/4=10. Son present age=10 and Jacob age=40year.

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Any two social issues name

Posted by My Style Is?? My Attitude ?? 5 years, 5 months ago

CBSE > Class 10 > Mathematics