No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 2 answers

Amit Kumar Chaurasia 5 years, 3 months ago

lcm (12,576; 4,052) = 12,739,488: least common multiple, calculated. The numbers have common prime factors.

Gaurav Seth 5 years, 3 months ago

12576 <a href="http://www.leastcommonmultiple.net/lcm-of-2/">2</a>
6288 <a href="http://www.leastcommonmultiple.net/lcm-of-2/">2</a>
3144 <a href="http://www.leastcommonmultiple.net/lcm-of-2/">2</a>
1572 <a href="http://www.leastcommonmultiple.net/lcm-of-2/">2</a>
786 <a href="http://www.leastcommonmultiple.net/lcm-of-2/">2</a>
393 <a href="http://www.leastcommonmultiple.net/lcm-of-3/">3</a>
131 131
1

LCM = 25. 31. 1311 = 12576

  • 0 answers
  • 1 answers

Gaurav Seth 5 years, 3 months ago

It is given that ,

x ,2x+k and 3x+6 are three consecutive terms .

we know that ,

Difference of any two consecutive terms is equal in A.P 

Now,

(2x+k)-x = (3x+6)-(2x+k)

=> 2x+k-x = 3x+6-2x-k

=> x+k = x+6-k

=> k+k = x+6-x

=> 2k = 6

=>k = 6/2

=> k = 3

Therefore,

If k = 3 then the given three consecutive terms x,2x+k and 3x+6 are in A.P

  • 2 answers

Mehul Patel 5 years, 2 months ago

Ok

Bhawna Koranga 5 years, 3 months ago

In Board exam mcq type 10or 20question will come
  • 1 answers

Gaurav Seth 5 years, 3 months ago



Given a ∆ABC such that D is the mid point of AB and DE || BC.

To Prove:              AE  = EC 
Proof:                    AD = DB        (given)
                      
In ∆ABC, we have
DE || BC
Therefore, by using Basic proportionality theorem, we have

Comparing (i) and (ii), we get
          
              

  • 0 answers
  • 5 answers

Sourav Keshri 5 years, 1 month ago

Thank's gourav seth

Sourav Keshri 5 years, 1 month ago

Kya re kya bol raha raha hai be

Sourav Keshri 5 years, 3 months ago

Thank bhai

Aniket Baghel 5 years, 1 month ago

MC kahi ke lodu

Gaurav Seth 5 years, 3 months ago

Let √2 be a rational number 

Therefore, √2= p/q  [ p and q are in their least terms i.e., HCF of (p,q)=1 and q ≠ 0

On squaring both sides, we get 
                   p²= 2q²                                                                                    ...(1)
Clearly, 2 is a factor of 2q²
⇒ 2 is a factor of p²                                                                    [since, 2q²=p²]
⇒ 2 is a factor of p

 Let p =2 m for all m ( where  m is a positive integer)

Squaring both sides, we get 
            p²= 4 m²                                                                                          ...(2)
From (1) and (2), we get 
           2q² = 4m²      ⇒      q²= 2m²
Clearly, 2 is a factor of 2m²
⇒       2 is a factor of q²                                                      [since, q² = 2m²]
⇒       2 is a factor of q 

Thus, we see that both p and q have common factor 2 which is a contradiction that H.C.F. of (p,q)= 1

     Therefore, Our supposition is wrong

Hence √2 is not a rational number i.e., irrational number.

  • 2 answers

Aniket Baghel 5 years, 3 months ago

Hk honey ki behen chod

Hk Honey 5 years, 3 months ago

Hey
  • 5 answers

Mahi..... ♾ 5 years, 3 months ago

39

Abhishek Thakur 5 years, 3 months ago

39

Kukatla Ajith Kumar Yadav Yadav 5 years, 3 months ago

30.9

Hk Honey 5 years, 3 months ago

Hey

Rishiraj Chahar 5 years, 3 months ago

39
  • 4 answers

Eshna Riwar 5 years, 3 months ago

4th part I can explain

Sainisaab Ji 5 years, 3 months ago

Write question also

Akash Singh Rajput 5 years, 3 months ago

Hello

Akash Singh Rajput 5 years, 3 months ago

2
  • 4 answers

Bhawna Koranga 5 years, 3 months ago

Question number 15 to 20 delete ho gaya ha

Tarannum Jahan 5 years, 3 months ago

15 to 20 delete hoa hai

Hk Honey 5 years, 3 months ago

Hey

Sainisaab Ji 5 years, 3 months ago

Do all
  • 2 answers

Hk Honey 5 years, 3 months ago

Hy

Ananya Nautiyal 5 years, 3 months ago

No the ans is totally wrong but u would get half
  • 3 answers

Lakshay Bansal 5 years, 3 months ago

Rational

Shubham Kumar 5 years, 3 months ago

Rational number

Monalisa Bhoi 5 years, 3 months ago

Rational number
  • 3 answers

Sandeep S 5 years, 3 months ago

(a+b)=a²+2ab+b²

Jags Sma 5 years, 3 months ago

Hey, here is the answer (a+b)²= a²+b²+2ab Some more ↓↓ (a-b)²=a²+b²-2ab a²-b²= (a+b)(a-b) Mark it as expert answer!! ;););)

Yogita Ingle 5 years, 3 months ago

(a + b)2 = (a + b) (a + b)

= a(a+b) + b(a +b)

= a2 + ab + ab + b2
= a2 + 2ab + b2

  • 1 answers

Tarannum Jahan 5 years, 3 months ago

A credit card is issued by a credit card provider, like Capital One, and they are designed to pay for things in shops or online. You can also use credit cards for balance transfers and taking out cash (also known as cash advance or cash withdrawal) from an ATM.
  • 2 answers

Jags Sma 5 years, 3 months ago

Here is your answer @diya Gupta Series - a,a+d,a+2d,a+3d,...... an= a+(n-1)d Sn = n/2 (a+an) Sn= n/2(2a+(n-1)d) Here are all Mark it as expert answer ;);)

Aastha Bhatt 5 years, 3 months ago

Refer to ncert mathematics book class 10 ch5
  • 5 answers

Amogh Kanamadi 5 years, 3 months ago

4

Nandani Arora 5 years, 3 months ago

4

Jags Sma 5 years, 3 months ago

4

Aastha Bhatt 5 years, 3 months ago

4

Lucy Kumari 5 years, 3 months ago

4
  • 5 answers

Bhawna Koranga 5 years, 3 months ago

Yes, every question is most important. In every subject.

Jags Sma 5 years, 3 months ago

Yes. If course practice it if u have standard maths ?❤️

Liv 5 years, 3 months ago

Yes some questions are most important.

Vidya Sagar Bonu 5 years, 3 months ago

Yes Because they didn't gave this exercise for exam but the questions will give in exam

Saumya Mundra 5 years, 3 months ago

For 2021 no
  • 0 answers
  • 2 answers

Jags Sma 5 years, 3 months ago

Any odd positive integer n can be written in form of 4q + 1 or 4q + 3.   If n = 4q + 1, when n2 - 1 = (4q + 1)2 - 1 = 16q2 + 8q + 1 - 1 = 8q(2q + 1) which is divisible by 8. If n = 4q + 3, when n2 - 1 = (4q + 3)2 - 1 = 16q2 + 24q + 9 - 1 = 8(2q2 + 3q + 1) which is divisible by 8. Here is the answer Mark it as expert answer ;);)

Gaurav Seth 5 years, 3 months ago

Show that n2 - 1 is divisible by 8, if n is an odd positive integer.

Any odd positive integer n can be written in form of 4q + 1 or 4q + 3.

 

If n = 4q + 1, when n2 - 1 = (4q + 1)2 - 1 = 16q2 + 8q + 1 - 1 = 8q(2q + 1) which is divisible by 8.

If n = 4q + 3, when n2 - 1 = (4q + 3)2 - 1 = 16q2 + 24q + 9 - 1 = 8(2q2 + 3q + 1) which is divisible by 8.

  • 2 answers

Bhawna Koranga 5 years, 3 months ago

Total distance=360km . let the speed of train be=xkm/h. total distance to cover 360at the speed of xkm/h =360h apon x(eqi no -1)if the speed of train more =4km. speed of train (x+4)km /h total time to cover 360km at the speed of(x+4)km/h=360h apon x+5(eqi no 2) according to question 360/x+4-360/x=2. 360(1/x+5-1/x)=2 than u can do yourself .Thanks

Bhawna Koranga 5 years, 3 months ago

Let I help u

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App