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  • 3 answers

Anupama ?? 5 years, 3 months ago

Irrational number

Mega K 5 years, 3 months ago

It is a irrational number

Madhu Kaushik 5 years, 3 months ago

it is a irrational number
  • 1 answers

Yogita Ingle 5 years, 3 months ago

Let the present age of father = years and the present age of son = y years

According to question:

 x + y = 45  ...(1)

Again, 5 years ago, the product of their ages was 124, therefore,

(Age of man 5 years ago) × (Age of son 5 years ago) = 124

(x – 5) × (– 5) = 124

⇒ (45 – y - 5) ×(y – 5) = 124  [Using (1)]

⇒ 40y – y2 - 200 + 5y = 124  

⇒ y2  - 45y  + 324 = 0  

⇒ y2  - 36y  - 9y + 324 = 0

⇒ y(y - 36) -9 (y - 36) = 0

⇒ (y - 36)(y - 9) = 0

⇒ y = 36 or y = 9

For y = 36, x = 45 - 36 = 9 which is not possible.

For y = 9, x = 45 - 9 = 36

Therefore, the present age of father = 36 years and the present age of son = 9 years.

  • 1 answers

Gaurav Seth 5 years, 3 months ago

When a, b, c are real numbers, a 0: If = b² -4 a c = 0, then roots are equal (and real). If = b² -4 a c > 0, then roots are real and unequal. If = b² -4 a c < 0, then roots are complex.

  • 5 answers

Pranav K.P 5 years, 3 months ago

C. S. A of a cube is 4(s)² or (4×side×side) It means we take the area of a cube except the top and bottom side. In cube there are 6 squares in which we only take 4 of them. Hope it is helpful ✌

Anupama ?? 5 years, 3 months ago

4(s)*2

Mega K 5 years, 3 months ago

4[ side] 2

Mandaloju Bharath 5 years, 3 months ago

4(s)²

₷Āńïk₳ Dĥãpãtè ₯ 5 years, 3 months ago

The curved surface area or the lateral surface area of a cube is 4(side)². #Hope it is helpful..
  • 3 answers

Mandaloju Bharath 5 years, 3 months ago

X=2 X²-kx+10=0 2²-k(2)+10=0 4-2k+10=0 -2k+4+10=0 -2k+14=0 -2k=-14 K=-14/-2 K=7

₷Āńïk₳ Dĥãpãtè ₯ 5 years, 3 months ago

Given x-2=0.....so, x=2 2²-2k+10=0 -2k=-10-4 2k=14 (cancelling negative sign) k=14/2 k=7 #Hope it is helpful...

Yogita Ingle 5 years, 3 months ago

Put x = 2

x2-kx+10 = 0

 (2)2 - k(2) + 10 = 0
4 - 2k + 10 = 0
-2x +14 = 0

-2x = -14

x = 14/2 = 7

  • 1 answers

₷Āńïk₳ Dĥãpãtè ₯ 5 years, 3 months ago

⇒Let, the side of the first square be=x the side of the second square be=y According to the first condition, x²+y²=544 →① According to the second condition, 4x-4y=32 (x>y) x-y=8 →② x=8-y Now putting x value in eq.1 (8-y)²+y²=544 64-16y+y²+y²=544 2y²-16y-480=0 y²-8y-240=0 Appliying quadratic formula, y=-(-8)±√-8²-4(-240) -------------------------- 2 y=20 and -12 (ignoring negative sign) Now put the value of y in eq.2 x-y=32 x=32-20 x=12 #Hope it is helpful...
  • 1 answers

Sia ? 4 years, 6 months ago

Let A (x1, y1) and B (x2, y2) be the endpoints of the given line segment AB and C(x, y) be the point which divides AB in the ratio m : n. We want to find the coordinates (x, y) of C. Now draw perpendiculars of A, C, B parallel to Y coordinate joining at P, Q, and R on X-axis.

  • 2 answers

Rohit Kumar 5 years, 3 months ago

Third term =a+2d=1---(¡) and sixth term = a+5d=-11 ---(¡¡) subtract equation (¡)from(¡¡) we get d=-4 then put the value of d in equation I we get a = 9 then sum = n÷2×[2a+(n-1)×d] we get sum is -1696

Nitish Raj 5 years, 3 months ago

Answer= -1696
  • 3 answers

Prajnasree Behera 5 years, 3 months ago

If you solve this question by not saying unwanted advice I will obliged

Prajnasree Behera 5 years, 3 months ago

Thanku for ur advice

Sathwik Nannaware 5 years, 3 months ago

The answer is very simple my child. First of all read the question twice and is your own brainbecause I am a very busy person GOOD LUCK BOY/GIRL . YOU HAVE MY LEGENDARY BLESSINGS. ?THANK YOU?
  • 1 answers

Gaurav Seth 5 years, 3 months ago

from circumcentre distance of every vertex is same

let circumcentre point C

so AC=BC=CO

AC^2=BC^2=CO^2

by distance formula

AC^2 = BC^2

[(x-a)^2+(y-0)^2] = [(x-0)^2+(y-b)^2]

by solving

x^2+a^2 -2ax+ y^2 = x^2 +y^2+ b^2-2yb

2(by-ax)= b^2 -a^2 ---- (1)

NOW AC^2=OC^2

(x-0)^2 + (y-b)^2 = x^2 + y^2

by solving this equation y=b/2

put the value of y in (1) and we will get x=a/2

So answer is (a/2,b/2)

  • 0 answers
  • 4 answers

Dev Sangwan 5 years, 3 months ago

I think Answer will be 'not defined'

Tripti Tiwari 5 years, 3 months ago

39 /+0 (13+13) =39/+0 (26) =39 /+0*26 =39/0 =0ans

Rd Gamers 5 years, 3 months ago

0 is the correct answer

Yogita Ingle 5 years, 3 months ago

39/+0(13+13)

= 39/+0(26)

= 39/0

= 0

  • 3 answers

Dhanush N 5 years, 3 months ago

(4x+9x)² We use (a+b)²=a²+b²+2ab =4x²+9x²+2*4x*9x =16x²+81x²+72 =97x²+72x² =169x²

Rd Gamers 5 years, 3 months ago

169x2

Yogita Ingle 5 years, 3 months ago

(4x+9x)²

= (13x)2

= 169x2

  • 1 answers

Yogita Ingle 5 years, 3 months ago

141x+93 y =189 .........(i)

93 x + 141 y=45.........(ii)

Add (i) and (ii), we get

141x+93 y =189 

93 x + 141 y=45
_______________
234x + 234 y= 234

x + y=1........ (iii)

Subtract (i) and (ii), we get

141x+93 y =189 

93 x + 141 y=45
_______________
48 x - 48  y=144
  x -  y = 3........ (iv)

Adding (iii) and (iv), we get

    x + y=1
+ x - y = 3

____________

2x = 4
x = 2
Put x = 2 in (iii)
2 + y = 1
y = 1 - 2  = -1

  • 3 answers

Dev Sangwan 5 years, 3 months ago

9/11 Numerator is 9

Anupama ?? 5 years, 3 months ago

81/100

Sri Anish 5 years, 3 months ago

81/100
  • 2 answers

Gaurav Seth 5 years, 3 months ago

For every quadratic equation, there can be one or more than one solution. These are called the roots of the quadratic equation.

For a quadratic equation ax2+bx+c = 0,

the sum of its roots = –b/a and the product of its roots = c/a.

Jagrat Narvariya 5 years, 3 months ago

Chapter 15
  • 4 answers

Nabila Ansari 5 years, 3 months ago

X^2 -3x-2

Aditya Tiwari 5 years, 3 months ago

x*2-3x-2

?????? ?????? 5 years, 3 months ago

x²-3x-2

Anupama ?? 5 years, 3 months ago

x*2 - 3x+2
  • 4 answers

Sri Anish 5 years, 3 months ago

X²-5X=14 X²-5X-14=0 X²-7X+2X-14=0 X(X-7)+2(X-7)=0 (X-7)(X+2)=0 (X-7)=0 (X+2)=0 X=7 and X=-2

Anirudh Jaat From Haryana 5 years, 3 months ago

it is done by this this x2-5x-14=0 x2+2x-7x-14=0. x(x+2)-7(x+2)=0 (x+2) (x-7) =0 if x+2=0. x=-2 Not Valid x-7=0 x=7

Aditya Tiwari 5 years, 3 months ago

7,-2

Anupama ?? 5 years, 3 months ago

x*2-5x-14=0 =x*2-7x -2x-14=0=x(x-7)-2(x-7)=0 =(x-7)(x-2)so x=7,2
  • 1 answers

Gaurav Seth 5 years, 3 months ago

Q u e s t i o n : Find the area of a triangle ABC with A(1, - 4) and mid-points of sides through A being (2, - 1) and (0, - 1)

 

A n s w e r :

Let E be the mid point of AB

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  • 2 answers

Dev Sangwan 5 years, 3 months ago

You have to solve both the brackets Separately By (a²+b²+2ab) & (a²+b²-2ab) =3+25+10root3+25+3-10root3 =3+25+3+25 =56 56 is a terminating no so it is a rational no

Prashant Mori 5 years, 3 months ago

4
  • 2 answers

Dev Sangwan 5 years, 3 months ago

How???

Avatar ? 5 years, 3 months ago

111
  • 3 answers

Dhanush N 5 years, 3 months ago

a=5,d=5,an=1000 We have to use the formula an=a+(n-1)d 1000=5+(n-1)5 1000-5=(n-1)5 995=(n-1)5 995/5=n-1 199=n-1 199+1=n n=200

Gaurav Seth 5 years, 3 months ago

Step - by - step explanation :

a =5, d =5, tn =995

995 = 5 + (n-1) × 5

995 = 5 + 5n - 5

995 = 5 n

n = 995 ÷ 5 = 199

Avatar ? 5 years, 3 months ago

200

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