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  • 1 answers

Sujal Jiratee 10 months, 3 weeks ago

E
  • 2 answers

Pratiksha Limbu 10 months, 3 weeks ago

222228

Apurva Sharma 10 months, 3 weeks ago

222228
  • 3 answers

Navya Bedi 10 months, 3 weeks ago

LCM(280,x)=14HCF(280,x)------1 LCM+HCF=600 LCM=600-HCF--------2 From 1 and 2 600-HCF=14HCF 600=15HCF HCF=40 LCM=14×40 LCM=560 Now, LCM×HCF=280×x 560×40=280x x=80 Hope this helps

Ahana Khanna 10 months, 3 weeks ago

600-280=320 So the other no. Is 320

Joban Preet 10 months, 3 weeks ago

?
  • 1 answers

Pratiksha Limbu 10 months, 3 weeks ago

4.5
  • 1 answers

Aneek Bera 10 months, 3 weeks ago

Squaring both side we get sin²+cos²+2sincos=4 Sincos=3/2 A.T.C (Sin⁴+cos⁴)²-2sin⁴cos⁴ =[(sin²+cos²)²-2sin²cos²]²-3⁴ =(1-9)²-81 =64-81 =-17
  • 2 answers

Rupshree Singh 10 months, 4 weeks ago

By squaring both side SinA.CosA=1

Ishika Chouhan 10 months, 4 weeks ago

Square both side (SinA cosA)²= (√3)² Sin²A + cos²A + 2sinA.cosA = 3 We know that - Sin²A + Cos²A =1 So, 1+ 2sinA.cosA =3 2sinA.cosA = 3-1 2sinA.cosA =2 SinA.CosA = 2/2 SinA.CosA=1
  • 5 answers

Rupshree Singh 10 months, 4 weeks ago

ap4= 7+ 3 d ap4=-1+3d In apz ap4-ap4= ay-a+3d ay-8+3d -1+3d-(-8-3d) -1+34+8-30 = 7

Avani Cho 10 months, 4 weeks ago

7

Ashish Gupta 10 months, 4 weeks ago

7

Yash Singh 10 months, 4 weeks ago

7 is correct answer

Yash Singh 10 months, 4 weeks ago

2 ans
  • 1 answers

Ak Vijeesh Vijeesh 10 months, 4 weeks ago

X-y-y =9
  • 1 answers

Student Pro 11 months ago

3x/2-5y/3=-2----1 x/3+y/2=13/6---2 take the Icm of 6 in 1 and2 therefore, 9x-10y=-12----3 from this x=-12+10y/9---5 and 2x+3y=13-----4 putting 5 in 4 therefore, y=3 and from 5 x=2 {byputting thevalue of y in it}
  • 1 answers

Pratham Maurya 11 months ago

Given distance=360 km. Let the speed of the train be x km/hr. Speed when increased by 5 km/hr =(x+5) km/hr 360x−360(x+5)=1 [360x+1800−360x]x(x+5)=1 x2+5x−1800=0 x2+45x−40x−1800=0 x(x+45)−40(x+45)=0 (x−40)(x+45)=0 x=40,−45 The speed of the train is 40 km/hr.
  • 1 answers

Student Pro 11 months ago

3sin30=1/2*3=3/2 4cos^2 45=4(1/2)^2=4*1/2=4/2 cot^2 30=√3^2=3 cos^2 30 = √3/2^2=3/4 Sin2 60^= (√3/2)2=3/4 3(1/2)+4/2-3/3/4+3/4 [ by cutting 3 by 3cand 4by 4] 3/2+4/2-3[ now take the lcm of -3 multiply it by 2] = 3+4-6/2=7-6/2= 1/2 ans is 1/2
  • 2 answers

Student Pro 11 months ago

Product of zeroes=c/a__1 So  compare ax^2-6x-6with ax^2+bx+c=0 a=a,b=-6,c=-6 So c/a=-6/a=4[ given ] =-6=4a =-6/4= a =-3/2=a Ans

Neha Singh 11 months ago

A=30/16
  • 2 answers

Kanchan Yadàv 10 months, 3 weeks ago

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Suman is celebrating her birthday
  • 2 answers

Rupshree Singh 11 months ago

Length of minute hand = 5cm = 8 Time period = 6:05 am to 6:40 am. = 35 minutes 1 min = 6° 35min = 35x6 = 210°= Ө Area of the sector = θ/360 ×πr² 210/360×22/7×5×5 = 275/6 cm².

Soham Tanksale 11 months ago

J
  • 2 answers

Sankalp Dinesh 11 months ago

Means???

Kaunen Ansari 11 months ago

1 answer
  • 2 answers

Ashish Gupta 10 months, 4 weeks ago

-20

Namrata Babani 11 months ago

-62-(11-1)-3 -62-10*-3 -62+30 -32
  • 3 answers

Khushi Maan 11 months ago

Isme upar to sinA common lena hoga or niche cosA lena h ,, then upar ya niche ek jagah pr sin²A + cos²A = 1. Ye identity put Krna h ....

S Manikandan 11 months ago

Give me answer

S Manikandan 11 months ago

Write a rational number between root 2 and root 3
  • 2 answers

Praveen Prajapati 11 months ago

According to question First eq........ Is X+Y =27 And Second eq... Is XY=182 Then you solve eq by factorisation is Value X and Y is 13,14 or 14,13 Your question is solved

Khushi Maan 11 months ago

10x + y = 27 and 10xy = 182

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