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Ask QuestionPosted by Rryhgffcd Srffdftgfr 5 years, 6 months ago
- 3 answers
Yogita Ingle 5 years, 6 months ago
3rd term of the AP: a+2d = 5 …(1)
7th term: a+6d = 9 …(2)
Subtract (1) from (2)
4d = 4, or
d = 1 and so a = 3.
The AP is 3,4,5,6,….
Gunjan Singh 5 years, 6 months ago
Posted by Prachi Soni 5 years, 6 months ago
- 3 answers
Posted by Manasvi Pathak 5 years, 6 months ago
- 1 answers
Yogita Ingle 5 years, 6 months ago
Kx−2y=3 and 3x+y=5 are intersecting lines
⇒ form intersecting lines a1x+b1y+c1=0
and a2x+b2y+c2=0
⇒a1/a2 ≠ b1/b2
⇒ k/3 ≠ −2/1
∴k ≠ −b
∴ the value of k is not equal to−6
Posted by Dhanshree Mane 5 years, 6 months ago
- 1 answers
Tarun Bisen 5 years, 6 months ago
Posted by God World 5 years, 6 months ago
- 1 answers
Tarun Bisen 5 years, 6 months ago
Posted by Paramveer Singh 5 years, 6 months ago
- 1 answers
Yogita Ingle 5 years, 6 months ago
Given : Expression
Cross multiply,
Apply middle term split,
Therefore, The solution of the expression is x=-2 and x=1.
Posted by Shalini Yadav 5 years, 6 months ago
- 2 answers
Posted by Chutia Raj 5 years, 6 months ago
- 2 answers
Posted by Rohit Joshi 5 years, 6 months ago
- 1 answers
Gaurav Seth 5 years, 6 months ago
Given that triangle ABC and ΔPQR in which AD and PM are medians drawn on sides BC and QR respectively.
It is given that AB/PQ = AC/PR = AD/PM
We have to prove that ΔABC ~ ΔPQR
Construction: Produce AD to E such that AD = DE and PM to F such that PM = MF
From the figure,
In ΔABD and ΔCDE,
AD = DE [by construction]
∠ADB = ∠CDE [vertically opposite angles]
BD = DC [Since AD is a median]
So, by SAS congruent condition
ΔABC ≅ ΔPQR
AB = CE [by CPCT]
Similarly, we can prove
ΔPQM ≅ ΔRMF
PQ = RF [by CPCT]
Now, given that
AB/PQ = AC/PR = AD/PM
CE/RF = AC/PR = 2AD/2PM
CE/RF = AC/PR = AE/PF [Since AE = AD + DE and AD = DE, Same for PF]
By using SSS Congruent condition
ΔACE ≅ ΔPRF
=> ∠1 = ∠2 ......1
Similarly, ∠3 = ∠4 ......2
Adding equations 1 and 2, we get
∠1 + ∠3 = ∠2 + ∠4
=> ∠A = ∠P
Now, in ΔABC and ΔPQR
AB/PQ = AC/PR
and ∠A = ∠P
By SAS similar condtion,
ΔABC ~ ΔPQR
Posted by Utsav Srivastava 5 years, 6 months ago
- 1 answers
Posted by Saif Ali 5 years, 6 months ago
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Posted by Nishant Pandey 5 years, 6 months ago
- 5 answers
Posted by Shubham Prasad 5 years, 6 months ago
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Posted by Ramachandrappa Ankushakhani 5 years, 6 months ago
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Honey Jain 5 years, 6 months ago
Posted by Sonam Kumari Paswan 5 years, 6 months ago
- 5 answers
Anil Tharkar 5 years, 6 months ago
Posted by ༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 6 months ago
- 3 answers
Posted by ༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 6 months ago
- 5 answers
Posted by ༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 6 months ago
- 5 answers
Posted by Anurag Gupta 5 years, 6 months ago
- 3 answers
Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 6 months ago
༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 6 months ago
Posted by Kuldeep Kumar 5 years, 6 months ago
- 1 answers
༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 6 months ago
Posted by Gouri Krishna K U 5 years, 6 months ago
- 2 answers
༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 6 months ago
Gaurav Seth 5 years, 6 months ago
ar(abcd)=ar(DBC)+ar(dab)
ar(DBC)
1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))
1/2(1(1-2)+(4(2-0)+1(0-1))
1/2(-1+8-1)
1/2(6)
3 squnits
ar (dab)
1/2 (1(-1-2)+-2(2-0)+1(0-(-1))
1/2 (-3-4+1)
1/2 (-7+1)
1/2 (-6)
3 squnits
ar (abcd) =3 + 3= 6 squnits
Posted by Karan Prajapati 5 years, 6 months ago
- 3 answers
Gourav Gupta 5 years, 6 months ago
Sanskriti Mathur 5 years, 6 months ago
Posted by Gunjan Singh 5 years, 6 months ago
- 1 answers
Gaurav Seth 5 years, 6 months ago
Let say Side of of cube is 4a
Then Surface area of cube S = 6(4a)² = 96a²
Volume of cube = (4a)³ = 64a³
Cube cut in 64 cubes
Hence volume of one small cube = 64a³/64 = a³
Side of small cube = a
Surface area of small cube = 6a²
Surface area of 64 small cubes = 64 * 6a² = 384a²
increase in surface area = 384a² - 96a² = 288a²
% increase in surface area = (288a²/96a²) * 100
= 300%
by 300% total surface area increase
Posted by Vinit Kumar 5 years, 6 months ago
- 3 answers
Gaurav Seth 5 years, 6 months ago
NCERT Solutions for Class 10 Maths Exercise 4.1 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
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?Suhani Arora? 5 years, 6 months ago
Posted by Devika Sharma 5 years, 6 months ago
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Posted by Md Taufique 5 years, 6 months ago
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Posted by Ankita Lenka 5 years, 6 months ago
- 5 answers
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Prachi Jain 5 years, 6 months ago
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