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Determine the AP. whose 3rd term is 5 and 7th term is 9

Posted by Rryhgffcd Srffdftgfr 5 years, 1 month ago

3 answers

Prachi Jain 5 years, 1 month ago

3rd term of the AP: a+2d = 5 …(1) 7th term: a+6d = 9 …(2) Subtract (1) from (2) 4d = 4, or d = 1 and so a = 3. The AP is 3,4,5,6,….

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Yogita Ingle 5 years, 1 month ago

3rd term of the AP: a+2d = 5 …(1)

7th term: a+6d = 9 …(2)

Subtract (1) from (2)

4d = 4, or

d = 1 and so a = 3.

The AP is 3,4,5,6,….

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Gunjan Singh 5 years, 1 month ago

Here a3= a+2d =5___(1) a7= a+6d =9___(2) Subtracting 2 from 1 a+2d-a-6d = 5-9 => -4d = -4 d= 1 Now a+2d = 5 a = 5-2d Putting the value of (d) a= 5- 2(1) a = 3 The required AP is 3,4,5,6,7......

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Give example of two irrationals whose sum is rational

Posted by Prachi Soni 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Ritika Ritika 5 years, 1 month ago

(3+√2) and (3-√2)

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Prachi Jain 5 years, 1 month ago

Root3+4 and root4-3

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Saurav Sharma 5 years, 1 month ago

Root3 +4 and root 4-3

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ANSWER

For what value of k do the equations k x - 2y=3and 3x+y=5 represent two lines intersecting at a unique point

Posted by Manasvi Pathak 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

Kx−2y=3 and 3x+y=5 are intersecting lines

⇒ form intersecting lines a₁x+b₁y+c₁=0

and a₂x+b₂y+c₂=0

⇒a₁/a₂≠ b₁/b₂

⇒ k/3 ≠ −2/1

∴k ≠ −b

∴ the value of k is not equal to−6

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ANSWER

Solve the elimination method X + y equal to 14 x minus y equal to 4

Posted by Dhanshree Mane 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Tarun Bisen 5 years, 1 month ago

Here's your answer.... x+y=14 Let this equation be equation 1 x-y=4 Let this equation be equation 2. Solve equation 1 and 2 You can either add or subtract the equations. Let us subtract the equation... x+y=14 x-y=4 _______ 2y=10 y=10/2 Y=5 Substitute y=5 in equation 1 x+y=14 x+5=14 x=14-5 x=9 So, x=9 and y =5

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Similar triangle theorem

Posted by God World 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Tarun Bisen 5 years, 1 month ago

Theorem: If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. This proves that the ratio of the area of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.

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Solve the equation: 4 x ‒ 3 = 5 2?+3 , x ≠ 0, 3 2

Posted by Paramveer Singh 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

Given : Expression

Cross multiply,

Apply middle term split,

Therefore, The solution of the expression is x=-2 and x=1.

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Which term of the AP 3 8 13 18 is 88

Posted by Shalini Yadav 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Sagar Dhadke 5 years, 1 month ago

I love you

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Kumar Uday Charan 5 years, 1 month ago

18th term

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A candidate scored 40 marks in a test if

Posted by Chutia Raj 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Eva Kandoth 5 years, 1 month ago

Bruhh atleast write the question complete

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Paramveer Singh 5 years, 1 month ago

Bro plz.. write full que

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Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that ABC PQR

Posted by Rohit Joshi 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

Given that triangle ABC and ΔPQR in which AD and PM are medians drawn on sides BC and QR respectively.

It is given that AB/PQ = AC/PR = AD/PM

We have to prove that ΔABC ~ ΔPQR

Construction: Produce AD to E such that AD = DE and PM to F such that PM = MF

From the figure,

In ΔABD and ΔCDE,

AD = DE [by construction]

∠ADB = ∠CDE [vertically opposite angles]

BD = DC [Since AD is a median]

So, by SAS congruent condition

ΔABC ≅ ΔPQR

AB = CE [by CPCT]

Similarly, we can prove

ΔPQM ≅ ΔRMF

PQ = RF [by CPCT]

Now, given that

AB/PQ = AC/PR = AD/PM

CE/RF = AC/PR = 2AD/2PM

CE/RF = AC/PR = AE/PF [Since AE = AD + DE and AD = DE, Same for PF]

By using SSS Congruent condition

ΔACE ≅ ΔPRF

=> ∠1 = ∠2 ......1

Similarly, ∠3 = ∠4 ......2

Adding equations 1 and 2, we get

∠1 + ∠3 = ∠2 + ∠4

=> ∠A = ∠P

Now, in ΔABC and ΔPQR

AB/PQ = AC/PR

and ∠A = ∠P

By SAS similar condtion,

ΔABC ~ ΔPQR

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Maths exercise -8. 4 question 5 solutin

Posted by Utsav Srivastava 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Rohit Joshi 5 years, 1 month ago

To check CBSE guide in math ncert solutions

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ANSWER

If the point p (2,1)lies on the line segment joining points A (4,2)and B (8,4)then,

Posted by Saif Ali 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Tarun Lovestatus 5 years, 1 month ago

Triangle

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Find each of the products 3x(-1)

Posted by Nishant Pandey 5 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Taniya 5 years, 1 month ago

-3x

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Tarun Lovestatus 5 years, 1 month ago

_3x

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Honey Jain 5 years, 1 month ago

-3x

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Priyanshi Jadeja 5 years, 1 month ago

-3x

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Anmol Varshney 5 years, 1 month ago

-3x

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ANSWER

5+5=

Posted by Shubham Prasad 5 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Priyanshi Jadeja 5 years, 1 month ago

5+5=10 I hope it will help you!??

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Barkha Mandloi 5 years, 1 month ago

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Sminu Saji 5 years, 1 month ago

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Anmol Varshney 5 years, 1 month ago

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Honey Jain 5 years, 1 month ago

1Thank You

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2x+3y=9 4x+6y=18 solve in substantial method

Posted by Ramachandrappa Ankushakhani 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Priyanshu Sharma 5 years, 1 month ago

It's ncert just do it by yourself

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Tarun Lovestatus 5 years, 1 month ago

Unique siruliont

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Honey Jain 5 years, 1 month ago

2x=9-3y x=9-3y/2 Now put value of x in 2 equation 4 (9-3y/2)+6y=18 (18-6y)+6y=18 0 This equation is unique solution

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A spiral is made up of successive semicircle with center alternately at A and B starting with centre at A of raddi 0.5 CM, 1.0 CM, 1.5 CM, 2.0 CM.... As shown in fig 5.4 . What is the total length of such a spiral made up of thirteen consecutive semicircle ( take π=22/7

Posted by Sagar Adhikari 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

N.Vishal Rao 5 years, 1 month ago

It is an A.P.

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N.Vishal Rao 5 years, 1 month ago

143..I think

1Thank You

ANSWER

please help me kon kon syllabus ka chapters delete Hua 2020 ma

Posted by Sonam Kumari Paswan 5 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Priyanshi Jadeja 5 years, 1 month ago

See at cbse website... I hope it will help you!??

1Thank You

Robins Kumar 5 years, 1 month ago

See at cbse website

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Anil Tharkar 5 years, 1 month ago

UNIT I-NUMBER SYSTEMS Chapter Topics REAL NUMBERS Euclid’s division lemma POLYNOMIALS Statement and simple problems on division algorithm for polynomials with real coefficients. PAIR OF LINEAR EQUATIONS IN TWO VARIABLES cross multiplication method QUADRATIC EQUATIONS Situational problems based on equations reducible to quadratic equations ARITHMETIC PROGRESSIONS Application in solving daily life problems based on sum to n terms COORDINATE GEOMETRY Area of a triangle TRIANGLES Proof of the following theorems are deleted · The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. · In a triangle, if the square on one side is equal to sumof the squares on the other two sides, the angle opposite to the first side is a right angle. CIRCLES No Deletion CONSTRUCTIONS Construction of a triangle similar to a given triangle. UNIT V- TRIGONOMETRY Chapter Topics INTRODUCTION TO TRIGONOMETRY Motivate the ratios whichever are defined at 0o and 90o TRIGONOMETRIC IDENTITIES Trigonometric ratios of complementary angles HEIGHTS AND DISTANCES No deletion AREAS RELATED TO CIRCLES Problems on central angle of 120° SURFACE AREAS AND VOLUMES Frustum of a cone UNIT VI-STATISTICS & PROBABILITY Chapter Topics STATISTICS · Step deviation Method for finding the mean Cumulative Frequency graph PROBABILITY No deletion

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Ravi Yadav 5 years, 1 month ago

Google par dekh lo

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

you can search it on google..........

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ANSWER

Find the value of tan-1(1)+cos-1(-1/2)+sin-1(-1/2)

Posted by ༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Honey Jain 5 years, 1 month ago

3×22/7/4

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Shreya Rajshree 5 years, 1 month ago

3π/4 is the answer Hope will help

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

3π/4

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ANSWER

9sec2A-tan2A=?

Posted by ༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Anil Tharkar 5 years, 1 month ago

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

I think 9 is the answer

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

lol ?ok I will try it again

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༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

Ans is wrong

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

47.255817 A2

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ANSWER

2minus8

Posted by ༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

Hnji?

0Thank You

༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

Free fire khelte ho

1Thank You

༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

You play Ffy

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

-6

1Thank You

༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

-6

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ANSWER

The larger of two supplementary angles exceed the smaller by 18 find the angles

Posted by Anurag Gupta 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

Let the angle be x other angle (it's supplement) =( 180-x) x+18= (180-x) 2x = 162 x = 162/2 = 81 other angle(its supplement) = 180- x =180-81 = 99

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

lol ???????

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༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

See in your Book............,,,,,,,.,.,.,.,.,.,

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Example no.2 ch 8 introduction to trigonometry in this question I can't understand the solution

Posted by Kuldeep Kumar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

Aak from your elder's to explane the example Ok?????????????

1Thank You

ANSWER

If A(-2,-1),B(x,0),C(4,y)and D(1,2) are the vertices of a parallelogram taken in order.find x and y and diagonals

Posted by Gouri Krishna K U 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

ar(abcd)=ar(DBC)+ar(dab) ar(DBC) 1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)) 1/2(1(1-2)+(4(2-0)+1(0-1)) 1/2(-1+8-1) 1/2(6) 3 squnits ar (dab) 1/2 (1(-1-2)+-2(2-0)+1(0-(-1)) 1/2 (-3-4+1) 1/2 (-7+1) 1/2 (-6) 3 squnits ar (abcd) =3 + 3= 6 squnits Ok ???????????????????????????????

1Thank You

Gaurav Seth 5 years, 1 month ago

ar(abcd)=ar(DBC)+ar(dab)

ar(DBC)
1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))
1/2(1(1-2)+(4(2-0)+1(0-1))
1/2(-1+8-1)
1/2(6)
3 squnits

ar (dab)
1/2 (1(-1-2)+-2(2-0)+1(0-(-1))
1/2 (-3-4+1)
1/2 (-7+1)
1/2 (-6)
3 squnits

ar (abcd) =3 + 3= 6 squnits

1Thank You

ANSWER

Find the zeros of polynomial x2-9x-8

Posted by Karan Prajapati 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

༄ᶦᶰᵈ᭄༒ツⓋⓘⓝⓔⓔⓣ Ｋｕｍａｒ༒ 5 years, 1 month ago

Yes their is an mistake in this Q

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Gourav Gupta 5 years, 1 month ago

The zeros of the polynomial is (9+√113)/2 , (9- √113)/2

1Thank You

Sanskriti Mathur 5 years, 1 month ago

Their is some problem in this question. Check the signs of this question

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ANSWER

If a solid cube of total surface area ‘S’ is cut into 64 identical cubes, by what value would the total surface area increase?

Posted by Gunjan Singh 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

Let say Side of of cube is 4a

Then Surface area of cube S = 6(4a)² = 96a²

Volume of cube = (4a)³ = 64a³

Cube cut in 64 cubes

Hence volume of one small cube = 64a³/64 = a³

Side of small cube = a

Surface area of small cube = 6a²

Surface area of 64 small cubes = 64 * 6a² = 384a²

increase in surface area = 384a² - 96a² = 288a²

% increase in surface area = (288a²/96a²) * 100

= 300%

by 300% total surface area increase

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ANSWER

Chapter 4 exercise 4.1

Posted by Vinit Kumar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Gaurav Seth 5 years, 1 month ago

NCERT Solutions for Class 10 Maths Exercise 4.1 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

Click on the link

https://mycbseguide.com/blog/ncert-solutions-class-10-maths-exercise-4-1/

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?Suhani Arora? 5 years, 1 month ago

Go to mathematics ch.4 ex. 4.1 and u will find ur answer

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Vinit Kumar 5 years, 1 month ago

Number kiya hai

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ANSWER

Ex.2.4 4

Posted by Devika Sharma 5 years, 1 month ago