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  • 1 answers

?Suhani Arora? 5 years, 1 month ago

Good evenimg
  • 3 answers

Priyanshi Jadeja 5 years, 1 month ago

Problems will definitely there because maths is a subject where you will face difficulties ; if you will work on it with keen interest than gradually you will not face difficulty.As per my advice you should 1st solve all doubts of ncert with the optional ones than you should solve sums from practice books i.e. RD Sharma,Navneet etc.... than don't forget to solve last 5 years paper. You can also practice with Gala. I hope it will help you! ??

Kritika Pathak 5 years, 1 month ago

(Prothom Boss) RS Aggarwal is better than ncert because it gives all questions of ncert

Prothom Bose 5 years, 1 month ago

Maths is not a subject which can be mastered in a day or two.It requires lots of practise.If you realy want to score good in maths than firstly go through all questions in ncert also examples given book(excluding the optional one).Once you are done with ncert and have enough time than solve refresher.But most importantly dont forget to solve the previous years question paper and also go through the latest pattern of exam paper which will be provided by CBSE on ots sites.
  • 3 answers

Liv 5 years, 1 month ago

What's the question?
Which question are you talking about?

Zeel Paghdal 5 years, 1 month ago

What's your question???
  • 1 answers

Shubham Saxena ???? 5 years, 1 month ago

But write your question properly ( with whole question ) .
  • 1 answers
It depends on number which number are there in question
  • 1 answers

Pranav Bhasin 5 years, 1 month ago

√3x^2 -4x -4√3 =√3x^2 -6x +2x -4√3 =√3x(x-2√3) +2(x-2√3) =(√3x + 2) (x - 2√3)
  • 2 answers

Gourav Gupta 5 years, 1 month ago

Step 1: 2x+3y=9 ..............(eqn 1) 4x-6y=18 ............(eqn 2) divide equation 2 by 2 on both sides, we get: 2x - 3y = 9 2x = 9 + 3y x = (9+ 3y)/2 ..........(eqn 3) step 2: now put the value of x (from equation 3) in equation 1, we get: 2((9+ 3y)/2) + 3y = 9 (9 + 3y) +3y = 9 9 + 6y =9 6y = 9-9 6y = 0 y = 0 .........................(eqn 4) step 3: Now put the value of y = 0 (from equation 4) in equation 3, we get x = (9+ 3(0))/2 x = 9/2 x = 4.5 .......................(eqn 5) so the answer is x = 4.5 and y = 0. step 4: Verification: to verify the answer we can put these values of x and y in any one of the equation 1 or equation 2. put x = 4.5 and y = 0 in equation 1, we get 2x+3y=9 2(4.5) + 3(0) = 9 9 + 0 = 9 9 = 9 L.H.S. = R.H.S.

Gaurav Seth 5 years, 1 month ago

Step 1:

           2x+3y=9 ..............(eqn 1)

           4x-6y=18  ............(eqn 2)

divide equation 2 by 2 on both sides, we get:

           2x - 3y = 9

           2x = 9 + 3y

             x = (9+ 3y)/2   ..........(eqn 3)

 

step 2:

now put the value of x (from equation 3) in equation 1, we get:

            2((9+ 3y)/2) + 3y = 9

             (9 + 3y) +3y = 9

              9 + 6y =9

              6y = 9-9

              6y = 0

                y = 0   .........................(eqn 4)

 

step 3:

Now put the value of y = 0 (from equation 4) in equation 3, we get

           x = (9+ 3(0))/2

           x = 9/2

           x = 4.5  .......................(eqn 5)

so the answer is  x = 4.5 and y = 0.

 

step 4:

Verification:

to verify the answer we can put these values of x and y in any one of the equation 1 or equation 2.

put  x = 4.5 and y = 0  in equation 1, we get

             2x+3y=9

             2(4.5) + 3(0) = 9

              9 + 0 = 9

                9 = 9

            L.H.S. = R.H.S.

It means our answer is right.

  • 1 answers
See in your Book.......
  • 1 answers

Yogita Ingle 5 years, 1 month ago

Let, O is the centre of the given circle.

A tangent PR has been drawn touching the circle at point P.

Draw QP ⊥ RP at point P, such that point Q lies on the circle.

∠OPR = 90° (radius ⊥ tangent)

Also, ∠QPR = 90° (Given)

∴ ∠OPR = ∠QPR

Now, the above case is possible only when centre O lies on the line QP.

Hence, perpendicular at the point of contact to the tangent to a circle passes through the centre of the circle.

  • 2 answers

Yogita Ingle 5 years, 1 month ago

Let us assume to the contrary that √3 is a rational number.

It can be expressed in the form of p/q

where p and q are co-primes and q≠ 0.

⇒ √3 = p/q

⇒ 3 = p2/q2 (Squaring on both the sides)

⇒ 3q2 = p2………………………………..(1)

It means that 3 divides pand also 3 divides p because each factor should appear two times for the square to exist.

So we have p = 3r

where r is some integer.

⇒ p2 = 9r2………………………………..(2)

from equation (1) and (2)

⇒ 3q2 = 9r2

⇒ q2 = 3r2

Where q2 is multiply of 3 and also q is multiple of 3.

Then p, q have a common factor of 3. This runs contrary to their being co-primes. Consequently, p / q is not a rational number. This demonstrates that √3 is an irrational number.

Vishal Jat Jaat 5 years, 1 month ago

Hajjsv
  • 3 answers

Priyaranjan Kumar 5 years, 2 months ago

11 square is 121

Kavya Mehra 5 years, 2 months ago

By CBSE according to new syllabus

Kavya Mehra 5 years, 2 months ago

This portion is deleted
  • 1 answers

Sawan Goja 5 years, 1 month ago

What was it.!?
  • 1 answers

Netra Kallibaddi 5 years, 2 months ago

3 units
  • 1 answers

Shristi Upadhyay 5 years, 2 months ago

x=1 Now put the value of x in given polynomial we got, a×1×1-3(a-1)×1-1=0 a-3a+3-1=0 -2a+2=0 -2(a-1)=0 (a-1)=0 a=1 So we got the value of a is 1
  • 2 answers

Yogita Ingle 5 years, 2 months ago

The zeroes 2 and -2. 

∴ Sum of the zeroes = 2 +(-2) = 0

∴ Product of the zeroes = 2 × (-2) = -4 

The required polynomial is x2 - (sum of the zeroes) x + Product of the zeroes 

⇒ x2 - (0) x + (-4)

x2 - 4 

Shristi Upadhyay 5 years, 2 months ago

Here given zeroes of polynomial (2,-2) That means, alpha is 2 and Beta is -2 Now alpha+beta=2+(-2)=0 and alpha×beta=2×-2=-4 Then put these value in x2-(alpha+beta)x+alpha×beta x2-0x+(-4) X2+4 it is a polynomial
  • 5 answers

Pooja Rao 5 years, 1 month ago

120

Tapan Kumar Sahu 5 years, 1 month ago

The smallest number is 3

Tapan Kumar Sahu 5 years, 1 month ago

3

Priyaranjan Kumar 5 years, 2 months ago

The smallest no. Is 3

Ayan Gupta 5 years, 2 months ago

120
  • 1 answers

Yogita Ingle 5 years, 2 months ago

Let us assume that 5 -√3 is rational. Then it can be written in the form

5 - √3 = p/q

or 5 - p/q = √ 3

It implies √3 is a rational number [Since 5 - p/q are rationals

But this contradicts the fact that √3 is irrational. Hence our supposition was wrong. Therefore 5 -√ 3 is irrational.

  • 2 answers

Prem Sagar T.K 5 years, 2 months ago

x=1 Y=2

Mayank Chaudhary 5 years, 2 months ago

2+2=X+y+1 4=X+y+1 4-1= X+y 3=X+y x= y-3. ----eq(1) x+y=3 y-3+y=3 2y=3+3 2y=6 y=3 So, putting the value of y in eq(1) x =0
  • 4 answers

Prem Sagar T.K 5 years, 2 months ago

x=0

Boobala Guru 5 years, 2 months ago

Yes x=0

Nidhi Jain 5 years, 2 months ago

Here x=0

Kritika Kansal 5 years, 2 months ago

2x + 4x = 0 6x = 0 X = 0/6 X = 0
  • 2 answers

Shubham Saxena ???? 5 years, 2 months ago

(x - 2 ) (x + 2 ) = ( x - 3 ) ( 2x + 3 ),,,, [x² + 2x - 2x - 4 = 2x² + 3x - 6x - 9 = 0] ,,,, [x² + 2x - 2x - 4 - 2x² - 3x + 6x + 9 = 0 ],,,, [ x² + 9x + 5 = 0 ,, Hence it is a quadratic equation . Thank you

Boobala Guru 5 years, 2 months ago

(X-2) (x+2)=x^2+(-2+2)x+-2×2=x^2-4 yes it is a quadratic it has a degree of 2
  • 1 answers

Yahiya Khan 5 years, 2 months ago

Follow me on Instagram @yahiya_khan786 I will explain properly on that platform

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