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Ask QuestionPosted by Manisha Dash 5 years, 6 months ago
- 3 answers
Yogita Ingle 5 years, 6 months ago
By Euclid's division algorithm
117 = 65x1 + 52.
65 = 52x1 + 13
52 = 13x4 + 0
Therefore 13 is the HCF (65, 117).
Posted by Yash . 5 years, 6 months ago
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Posted by Lolan John 5 years, 6 months ago
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Posted by Shailaja Singh 5 years, 6 months ago
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Bishwajeet Kumar 5 years, 6 months ago
Posted by Taniya 5 years, 6 months ago
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Posted by Muskan .072 5 years, 6 months ago
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Vaishu ? 5 years, 6 months ago
Bishwajeet Kumar 5 years, 6 months ago
Posted by Account Deleted 5 years, 6 months ago
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Posted by Bhakti Gupta 5 years, 6 months ago
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Gaurav Seth 5 years, 6 months ago
To draw y = x, we will plot the points (1,1) and (0,0).
To draw y = 2x, we will plot the points (1,2) and (0,0).
To draw x + y = 6, we will plot the points (0,6) and (6,0).
Coordinates of A (0,0), B (2,4), D (3,3).
Posted by Archana Nair 5 years, 6 months ago
- 1 answers
Bishwajeet Kumar 5 years, 6 months ago
Posted by Aarzoo Chaudhary 5 years, 6 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
O be the center of circles.
AB be the chord to the larger circle and tangent to smaller circle at P.
OP be radius of smaller circle i.e., OP = 15 cm
OA & OB be radius of larger circle i.e., OA = OB = 17 cm
now,
OP ⊥ AB ( radius and tangent of a circle are ⊥ to each other)
∴ In ΔOAP by PGT,
=
+
=
+
289 = 225 +
289 - 225 =
64 =
= AP
AP = 8 cm.
Now,
In ΔOAP & ΔOPB
OA = OB = 17 cm (Radii of same circle)
OP = OP (Common Side)
∠OPA = ∠OPB = 90° ( OP⊥AB)
∴ ΔOAP ≡ ΔOPB (By R.H.S axiom)
∴ AP = PB by C.P.C.T
Now,
AB = AP + PB
AB = 2 x AP
AB = 2 x 8 cm
AB = 16 cm
∴ Length of Chord is 16 cm.
Posted by Vaibhav Soni 5 years, 6 months ago
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Vaishu ? 5 years, 6 months ago
Posted by Divyansh Goyal 5 years, 6 months ago
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Posted by Aditi Yadav 5 years, 6 months ago
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Posted by Devank Lawate 5 years, 6 months ago
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Vaishu ? 5 years, 6 months ago
Posted by Raj Dewangan 5 years, 6 months ago
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Prachi Jain 5 years, 6 months ago
Honey Jain 5 years, 6 months ago
Yogita Ingle 5 years, 6 months ago
Suppose one number is X,
And another be Y.
By first condition,
X+Y=16………….(1)
By second condition,
X-Y =18………….(2)
Adding both the equation,
X+Y=16
+X -Y=18
…………….
2x =34 (y,-y get cancelled)
X=17.
Substitute x=17 in (1),
17+y=16
Y=16–17
Y= -1
(x=17,y=-1).
Posted by Simran Rehal 5 years, 6 months ago
- 1 answers
Yogita Ingle 5 years, 6 months ago
It is a non leap year. That means the year consist of 365 days.
Now
The birthday of first friend will be on any day of the total 365 days.
So, P(1) =
Again
The birthday of the 2nd friend will be on any day of the total of 364 days as his birthday date will be on the different day than the first friend.
So, P(2) =
So, P =
P =
Posted by Sunita Sharma 5 years, 6 months ago
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Divija Bansal 5 years, 6 months ago
Posted by Saloni Gupta 5 years, 6 months ago
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Posted by K.H.Disha Kandan 5 years, 6 months ago
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Posted by K.H.Disha Kandan 5 years, 6 months ago
- 2 answers
Yogita Ingle 5 years, 6 months ago
Mr. Hardy quipped that he came in a taxi with the number '1729' which seemed a fairly ordinary number. Ramanujan said that it was not. 1729, the Hardy-Ramanujan Number, is the smallest number which can be expressed as the sum of two different cubes in two different ways.
1729 is the sum of the cubes of 10 and 9 - cube of 10 is 1000 and cube of 9 is 729; adding the two numbers results in 1729.
1729 is also the sum of the cubes of 12 and 1- cube of 12 is 1728 and cube of 1 is 1; adding the two results in 1729.
K.H.Disha Kandan 5 years, 6 months ago
Posted by Sandhya Chahar 5 years, 6 months ago
- 2 answers
Ganesh G 5 years, 6 months ago
Gaurav Seth 5 years, 6 months ago
In the given Fig, altitudes AD and CE of 
intersects each other at the point P. Show that:
(i) ∆AEP ~ ∆CDP
(ii) ∆ABD ~ ∆CBE
(iii) ∆AEP ~ ∆ADB
(iv) ∆PDC ~ ∆BEC.
AD and CE are altitudes, which intersect each other at P.
(i) In ∆AEP and ∆CDP
∠AEP = ∠CDP = 90° [given]
and ∠APE = ∠CPD
[vertically opposite angles]
Therefore, by using AA similar condition
∆AEP ~ ∆CDP.
(ii) In ∆ABD and ∆CBE
∠ADB = ∠CEB = 90° [given]
and ∠B = ∠B [common]
Therefore, by using AA similar condition
∆ABD ~ ∆CBE.
(iii) In ∆AEP and ∆ADB
∠AEP = ∠ADB = 90° [given]
and ∠PAE = ∠DAB [common]
Therefore, by using AA similar condition
∆AEP ~ ∆ADB
(iv) In ∆PDC and ∆BEC
∠PDC = ∠CEB = 90° [given]
∠PCD = ∠ECB [common]
Therefore, by using AA similar condition
∆PDC ~ ∆BEC.
Posted by Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 6 months ago
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Sawan Goja 5 years, 6 months ago
Posted by Ritika Ritika 5 years, 6 months ago
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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 6 months ago
Posted by Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 6 months ago
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Posted by Sunena Dutta 5 years, 6 months ago
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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 6 months ago
Posted by Prachi Jain 5 years, 6 months ago
- 4 answers
Yogita Ingle 5 years, 6 months ago
In △BPA, we have
DC∣∣AP [Given]
Therefore, by basic proportionality theorem, we have
BC/ CP = BD/DA ........ (I)
In △BCA, we have
DE∣∣AC
Therefore, by basic proportionality theorem, we have
BE/EC = BD/DA........ (iI)
From (i) and (ii), we get
BC/CP = BE/ EC or BE/EC = BC/CP [Hence proved]
Posted by Anushka Shivhare 5 years, 6 months ago
- 1 answers
Posted by Anchal Prakash 5 years, 6 months ago
- 2 answers
Prachi Jain 5 years, 6 months ago
Yogita Ingle 5 years, 6 months ago
- sine: Sine of an angle is defined as the ratio of the side opposite(perpendicular side) to that angle to the hypotenuse.
- cosine: Cosine of an angle is defined as the ratio of the side adjacent to that angle to the hypotenuse.
- tangent: Tangent of an angle is defined as the ratio of the side opposite to that angle to the side adjacent to that angle.
- cosecant: Cosecant is a multiplicative inverse of sine.
- secant: Secant is a multiplicative inverse of cosine.
- cotangent: Cotangent is the multiplicative inverse of the tangent.
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Prachi Jain 5 years, 6 months ago
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