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  • 1 answers

Gaurav Seth 5 years ago

On comparing the ratios a1/a2 , b1/b2  and c1/c2, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:
Use this table for the solution

S.N.

Compare the Ratio

Graphic representation

Algebraic interpretation

Linear equations

1

 

Intersection lines at one point

Exactly one solution or
unique solution

Consistent

2

 

Coincident line

Infinity solution or many solutions

 Dependent and consistent

3

Parallel lines

No solution

Inconsistent

Solution: (i)

5x – 4y + 8         = 0

7x + 6y – 9         = 0
Compare the equation with

We get
a1 = 5,            b1       = -4,               and c1 = 8
a2 =7               b2       =6                    and c2 = -9

Hence

So both are Intersecting lines at one point
(ii)9x + 3y + 12            = 0
18x + 6y + 24           = 0
Compare the equation with

We get
a1 = 9,           b1       = 3,                 and c1 = 12
a2 =18          b2        =6,                   and c2 = 24

Hence

So both lines are coincident

(iii)6x – 3y + 10       = 0
2x – y + 9            = 0
Compare the equation with

We get
a1 = 6,            b1       =- 3,               and c1 = 10
a2 =2              b2        =-1,                 and c2 = 9 

Hence

So both lines are parallel

  • 3 answers

Sakshi Jagtap 3 years, 5 months ago

ANSWER:- 17/625 = 17/5⁴.... So, 17/625 is terminating

Akash K 5 years ago

How to express in decimal form without actual division

Yogita Ingle 5 years ago

1) A rational number is terminating if and only if the denominator of the rational number is of the form 2ᵃ or 5ᵇ or 2ᵃ.5ᵇ

2) In the given fraction 17/625

  • 17/625 can be written as 17/(5×5×5×5)
  • 17/5⁴

As the denominator has 5⁴ so the term is terminating.

  • 1 answers

Yogita Ingle 5 years ago

Let us assume √2 is rational number.
a rational number can be written into he form of p/q
√2=p/q
p=√2q
Squaring on both sides
p²=2q²__________(1)
.·.2 divides p² then 2 also divides p
.·.p is an even number
Let p=2a (definition of even number,'a' is positive integer)
Put p=2a in eq (1)
p²=2q²
(2a)²=2q²
4a²=2q²
q²=2a²
.·.2 divides q² then 2 also divides q
Both p and q have 2 as common factor.
But this contradicts the fact that p and q are co primes or integers.
Our supposition is false
.·.√2 is an irrational number.

  • 1 answers

Khushi Singh 5 years ago

AP: ,2,4,6.... To n term a=2,d=2,n=n,sn=n(n+1) Sn=n÷2[2a+(n-1)d] n(n+1)=n÷2[2×2+2n-2] n(2n+2)=n(2n+2) Both sides are same. So, his answer is 0
  • 1 answers

Gaurav Seth 5 years ago

To find the sum of squares, we use the formula of (n+1)³ as shown in the picture.

In the proof, I have used one result directly:

1 + 2 + 3 + ... + n = n(n+1)/2

Proof:
Given series is an A.P. with
First term = 1
Last term = n
Number of terms = n

Sum = n/2 [First term + Last Term]
So, Sum = n/2 [1 + n]
So, Sum = n(n+1)/2

That is, 1 + 2 + 3 + ... + n = n(n+1)/2
 

  • 1 answers

Yogita Ingle 5 years ago

There are four basic rules of logarithms as given below:-

  1. Logb (mn)= logb m + logb n. In this rule, the multiplication of two logarithmic values is equal to the addition of their individual logarithms.

          For example- log( 2y ) = log(2) + log(y)

  1. Logb (m/n)= logb m – logb This is called as division rule. Here the division of two logarithmic values is equal to the difference of each logarithm.

         For example, log( 2/ y ) = log(2) -log(y)

  1. Logb (mn) = n logb m

         This is the exponential rule of logarithms. The logarithm of m with a rational exponent is equal to the exponent times its logarithm.

  1.  Logm = logm/ loga b    
  • 5 answers

Atul Kumar 5 years ago

CHAPTER TOPICS REMOVED ?UNIT I-NUMBER SYSTEMS 〰️ ?REAL NUMBERS ➡️? Euclid’s division lemma ?UNIT II-ALGEBRA 〰️ ?POLYNOMIALS ➡️?Statement and simple problems on division algorithm for polynomials with real coefficients. ?PAIR OF LINEAR EQUATIONS IN TWO VARIABLES ➡️ ?cross multiplication method ?QUADRATIC EQUATIONS ➡️ ?Situational problems based on equations reducible to quadratic equations ?ARITHMETIC PROGRESSIONS ➡️ ?Application in solving daily life problems based on sum to n terms ?UNIT III-COORDINATE GEOMETRY 〰️ ?COORDINATE GEOMETRY ➡️ ? Area of a triangle. ?UNIT IV-GEOMETRY 〰️ ?TRIANGLES➡️Proof of the following theorems are deleted ?The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. ?In a triangle, if the square on one side is equal to sum of the squares on the other two sides, the angle opposite to the first side is a right angle. ?CIRCLES ➡️No deletion ?CONSTRUCTIONS ➡️Construction of a triangle similar to a given triangle. ?UNIT V- TRIGONOMETRY 〰️ ?INTRODUCTION TO TRIGONOMETRY ➡️ ?motivate the ratios whichever are defined at 0o and 90o TRIGONOMETRIC IDENTITIES➡️ ?Trigonometric ratios of complementary angles. ?HEIGHTS AND DISTANCES➡️No deletion ?UNIT VI-MENSURATION 〰️ ?AREAS RELATED TO CIRCLES ➡️ Problems on central angle of 120° ?SURFACE AREAS AND VOLUMES ➡️ Frustum of a cone. ?UNIT VI-STATISTICS & PROBABILITY 〰️ ?STATISTICS ➡️?Step deviation Method for finding the mean ?Cumulative Frequency graph ?PROBABILITY➡️ No deletion
For know about your syllabus so, visit now on you tube channel math by pankaj priyanshu

Sakshi Jagtap 5 years ago

CHAPTER TOPICS REMOVED ?UNIT I-NUMBER SYSTEMS 〰️ ?REAL NUMBERS ➡️? Euclid’s division lemma ?UNIT II-ALGEBRA 〰️ ?POLYNOMIALS ➡️?Statement and simple problems on division algorithm for polynomials with real coefficients. ?PAIR OF LINEAR EQUATIONS IN TWO VARIABLES ➡️ ?cross multiplication method ?QUADRATIC EQUATIONS ➡️ ?Situational problems based on equations reducible to quadratic equations ?ARITHMETIC PROGRESSIONS ➡️ ?Application in solving daily life problems based on sum to n terms ?UNIT III-COORDINATE GEOMETRY 〰️ ?COORDINATE GEOMETRY ➡️ ? Area of a triangle. ?UNIT IV-GEOMETRY 〰️ ?TRIANGLES➡️Proof of the following theorems are deleted ?The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. ?In a triangle, if the square on one side is equal to sum of the squares on the other two sides, the angle opposite to the first side is a right angle. ?CIRCLES ➡️No deletion ?CONSTRUCTIONS ➡️Construction of a triangle similar to a given triangle. ?UNIT V- TRIGONOMETRY 〰️ ?INTRODUCTION TO TRIGONOMETRY ➡️ ?motivate the ratios whichever are defined at 0o and 90o TRIGONOMETRIC IDENTITIES➡️ ?Trigonometric ratios of complementary angles. ?HEIGHTS AND DISTANCES➡️No deletion ?UNIT VI-MENSURATION 〰️ ?AREAS RELATED TO CIRCLES ➡️ Problems on central angle of 120° ?SURFACE AREAS AND VOLUMES ➡️ Frustum of a cone. ?UNIT VI-STATISTICS & PROBABILITY 〰️ ?STATISTICS ➡️?Step deviation Method for finding the mean ?Cumulative Frequency graph ?PROBABILITY➡️ No deletion

Kashish . 5 years ago

DECUCTED PORTION MATHEMATICS Code - 041 CLASS X CHAPTER TOPICS REMOVED UNIT I-NUMBER SYSTEMS REAL NUMBERS  Euclid’s division lemma UNIT II-ALGEBRA POLYNOMIALS  Statement and simple problems on division algorithm for polynomials with real coefficients. PAIR OF LINEAR EQUATIONS IN TWO VARIABLES  cross multiplication method QUADRATIC EQUATIONS Situational problems based on equations reducible to quadratic equations ARITHMETIC PROGRESSIONS Application in solving daily life problems based on sum to n terms UNIT III-COORDINATE GEOMETRY COORDINATE GEOMETRY  Area of a triangle. UNIT IV-GEOMETRY TRIANGLES Proof of the following theorems are deleted The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.  In a triangle, if the square on one side is equal to sum of the squares on the other two sides, the angle opposite to the first side is a right angle. CIRCLES No deletion CONSTRUCTIONS  Construction of a triangle similar to a given triangle. UNIT V- TRIGONOMETRY INTRODUCTION TO TRIGONOMETRY  motivate the ratios whichever are defined at 0o and 90o TRIGONOMETRIC IDENTITIES Trigonometric ratios of complementary angles. HEIGHTS AND DISTANCES No deletion UNIT VI-MENSURATION AREAS RELATED TO CIRCLES  Problems on central angle of 120° SURFACE AREAS AND VOLUMES  Frustum of a cone. UNIT VI-STATISTICS & PROBABILITY STATISTICS  Step deviation Method for finding the mean  Cumulative Frequency graph PROBABILITY No deletion

Sahil Singh 5 years ago

Pta nhi yrr
  • 2 answers

Shobha Kumari 5 years ago

Given,eqn =x+y=a+b................ (1) And =ax-by=a2-b2........... (2) From (1)*b+(2) =bx+by=ab+b2 =ax-by =a2-b2 =ax+bx=a2+ab =X(a+b)=a(a+b) =X=a Now,on putting x=a in eqn 1 =x+y=a+b =a+y=a+b =y=a Hence,x=a and y =b

Muskan Sharma 5 years ago

Given:- equation x+y= a+b and ax - by= a² - b² Solution:- Let x+y =a+b......(1) and ax - by = a² - b² .......(2) Substitute x from (1) in equation (2) a( a+b-y)- by = a²-b² a²+ab-ay-by =a²-b² ab-ay-by=b² ab-y(a+b)=-b² y(a+b)=ab+b² y(a+b)=b(a+b) y=b Substitute y in equation (1)... x+y= a+b x=a+b-b x=a x=a and y=b .
  • 1 answers

Gaurav Seth 5 years ago

Let r m be the radius and l m be the slant height of the cone, then
r = 2 m, and l = 2.8 m
Let r1 m be the radius and h m be the height of the cylinder, then
Now, r1 – 2 m and h = 2.1 m
Area of the canvas used
= CSA of cone + CSA of cylinder
= πrl + 2 πr1h
= πrl + 2πrh [r = r1]
= π r (l + 2h) m

and Cost of canvas of the tent
= Rs. (500 x 44)
= Rs. 22,000.

  • 1 answers

Gaurav Seth 5 years ago

Let 7-2√3 as rational number.

Then,7-2√3=a/b,where a and b are coprime.

Therefore,-2√3=a/b-7

√3=a/-2b -7

Here,a/-2b -7 is a rational number .

We know that √3 is an irrational number.

Hence,our assumption is not correct.

Therefore,7-2√3 is an irrational number.

  • 1 answers

Sakshi Jagtap 5 years ago

Yes absolutely, bcuz both the equations r same........ k(x²+3x+2)=0......... x²+3x+2=0/k........ x²+3x+2=0......... hope this helps uhh ?
  • 2 answers

Sakshi Jagtap 5 years ago

Ur short solution :- LHS = 2 tan 30÷1+tan²30......... Putting tan 30°= 1/√3............ => 2(1/√3) ÷ 1+ (1/√3)².............. => 2/√3÷1+(1/3)............. => 2/√3÷4/3............ => 2/√3 * 3/4........... => √3/2 = Sin 60°.......... LHS = RHS ........ HENCE PROVED.

Sakshi Jagtap 5 years ago

ANSWER!- LHS= 2 tan 30÷1+tan² 30...... Putting tan 30°=1/√3..... => 2(1/√3)÷ 1+(1/√3)²...... => 2/√3÷1+(1/3)...... => 2/√3÷ 4/3 ( since taking LCM of 1+(1/3)..... => 2/√3* 3/4 ( while doing multiplication of both the reciprocal will happen of 4/3)...... Therefore, √3 n 3 will b cancelled and 3 becomes √3, 2 n 4 will b cancelled and 2 will remain...... => √3/2....... :. √3/2 = Sin 60°...... LHS = RHS....... HENCE PROVED...... I think i did my best to explain this solution better?.....yaa its seems to b lengthy bcuz i have solved plus explained also......
  • 2 answers

Paru ? 5 years ago

Hey! Thank you ?✌?. Ya its helpful for me.

Sakshi Jagtap 5 years ago

The product of all common prime  factor is the HCF...... ⇒a=x*x*y*y...... ⇒b=x*y*y...... common Factors are x*y*y....... Thus ,HCF(a,b)=xy² ....... Hope this helps uhh ?...
  • 1 answers

Sakshi Jagtap 5 years ago

Let salary of A = 2k,..... B = 3k,..... C = 5k.... =>A's new salary = 115/100 of 2k = 115/100 x 2k = 23k/13....... =>B's new salary = 110/100 of 3k = 110/100 x 3k = 33k/10...... =>C's new salary = 120/100 of 5k = 120/100 x 5k = 6k..... Hence,new ratio = 23k/13 : 33k/10 : 6k = 23 : 33 : 60....... HOPE THIS HELPS UHH?
  • 1 answers

Sakshi Jagtap 5 years ago

Madeeha we can't share or post images over here.....u can prefer to google
  • 2 answers

Sandeep A W 5 years ago

Sin²60=(√3/2)²=3/4. Tan²45=(1)²=1. Cos²30=(√3/2)²=3/4. Cot²90=(0)²=0. Sin²60-Tan²45+Cos²30-Cot²90=3/4-1+3/4-0. =3/4-1+3/4. =3-4+3/4. =6-4/4. =2/4. =1/2.

Palak ? 4 years, 8 months ago

,?
  • 1 answers

Gautam Sinha 5 years ago

Sin2theta ×1/sin2theta= 1
  • 3 answers

Muskan Sharma 5 years ago

Answer:-1/2xsq

Sakshi Jagtap 5 years ago

Answer:- 1/2x²

Palak ? 5 years ago

Hey, punam its answer is 1/2x sq. Please I hv a request search preksha rana channel on YouTube and if u liked her videos please subscribe the channel and like it,,....if possible do share it with ur frnds and family members
  • 4 answers
2x²-x-6x+3=x(2x-1)-3(2x-1)(x-3) =>x=3 or ½

Mansi Mansi 5 years ago

2x^2-x-6x+3=x(2x-1)-3(2x-1) => (2x-1)(x-3)=> x=3 or x=1/2

Itachi Uchiha ? 5 years ago

meet.google.com/vkd-rwgd-dbx .....join it
2x²-x-6x+3 => x(2x-1)-3(2x-1) => (x-3)(2x-1) => x=3 or 1/2
  • 2 answers

Itachi Uchiha ? 5 years ago

Sandhya k if you don't understand hindi then how can your name Sandhya..bcz this is a indian cultural name .....are u think I m a mad bt no I try to gave my better to the students to achieve their goals........bt plzz don't mind it....

Itachi Uchiha ? 5 years ago

Sandhya now join this next meeting
  • 3 answers
sñ =1+2+3+4......+ñ sñ=ñ/2[2(1)+[ñ-1)1]=ñ(ñ+1)/2

Itachi Uchiha ? 5 years ago

meet.google.com/vkd-rwgd-dbx join this link

Muskan Sharma 5 years ago

Sn= 1+2+3+4+5+........+n Sn =n/2(2(1)+(n-1) 1) = n(n+1)/2
  • 3 answers
2/1-2çóß²A

Itachi Uchiha ? 5 years ago

Join this meet.google.com/vkd-rwgd-dbx

Yogita Ingle 5 years ago

1) (a+b)²+(a-b)² = 2(+)

2) (a-b)(a+b) = -b²

and

By Trigonometric identity:

sin²A+cos²A = 1 */

*/

/* By Trigonometric identity:

cos²A = 1-sin²A*/

Therefore,

  • 3 answers

Itachi Uchiha ? 5 years ago

Join this meet.google.com/vkd-rwgd-dbx

Gaurav Seth 5 years ago

HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.

Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.

The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.

Deleted syllabus of CBSE Class 10 Mathematics

 

Sakshi Jagtap 5 years ago

no, 6.4 is not Ommited.
  • 2 answers

Itachi Uchiha ? 5 years ago

https://meet.google.com/omc-jpgf-hkk

Numa Khan 5 years ago

https://meet.google.com/jxh-udvj-vuf

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