No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 2 answers

Rohan Kumar 5 years ago

105, 112, 119, ..., 994 This is an AP with first term (a) = 105 and common difference (d) = 7 Let an be the last term. an = a + (n - 1)d 994 = 105 + (n - 1)(7) 7(n - 1) = 889 n - 1 = 127 n = 128 Thus, there are 128 three-digit natural numbers that are divisible by

Yogita Ingle 5 years ago

Three digit numbers divisible by 7 are

<div>

105, 112, 119, ..., 994

This is an AP with first term (a) = 105 and common difference (d) = 7

Let an be the last term.

an = a + (n - 1)d

994 = 105 + (n - 1)(7)

7(n - 1) = 889

n - 1 = 127

n = 128

Thus, there are 128 three-digit natural numbers that are divisible by 7.

</div>
  • 1 answers

Yogita Ingle 5 years ago

Factors the number,

LCM is the least common multiple,

Therefore, LCM of 30240 and 29700 using prime factorisation method is 1663200.

  • 1 answers

Yogita Ingle 5 years ago

Let
P(4, m) = (x, y)
A(2, 3) = (x1, y1)
B(6, -3) = (x2, y2)
By using section formula in this points, we get.
Let the ratio in which P divide the line segment A and B be = k:1
Therefore,
x = kx2 + x1(1)/k + 1
=> 4 = 6k + 2 /k + 1
=> 4k + 4 = 6k + 2
=> 2k = 2
=.> k = 1
So, the ratio = 1:1
Now,
y = k(y2) + 1(y1) / k + 1
=> m = -3 + 3 /1 + 1
=> m = 0/2
=> m = 0.  

  • 2 answers
*Given a function of the form f(x)=ax2+bx+c, one can find the zeroes of the function (that is, where f(x)=0) by using the quadratic formula: x=−b±√b2−4ac2a. If the discriminant b2−4ac is less than zero, these roots will be complex or imaginary, and if the discriminant is greater than or equal to 0. these roots will be real. The use of ± informs us that there are two solutions here; one where we are subtracting √b2−4ac, and one where we are adding it.* For a step by step example, assume the function f(x)=x2−7x+10. Here a=1,b=−7,c=10. If we set f(x)=0, then the values of x for which f(x)=0, that is to say the roots of f(x), would be determined by the quadratic formula: x=−(−7)±√(−7)2−4(1)(10)2(1)=7±√49−402=7±√92=7±32. Thus, our roots will be at x=7+32 and x=7−32 or x=5 and x=2. On the graph of the function, we would see that the parabola crosses the x-axis at x=2 and x=5.

Kanishka Singh 5 years ago

First split the middle term and get factors of the given polynomial. Next to it put the factors equal to the value of zero. Then you will get the zeroes of the polynomial. You can also verify your answer using verification method.
  • 1 answers

Yogita Ingle 5 years ago

Mode= 3 Median - 2 mean

=> 28 = 3 median - 2*27

=> 16= 3 median - 54

=> 3 median= 70

=> median= 70/3= 23.33

so, Median of distribution is 23.33

  • 3 answers

Anand Nishad 5 years ago

Hello

Itachi Uchiha ? 5 years ago

The symbol used to denote irrational number is Q

Itachi Uchiha ? 5 years ago

Hii Sandhya..........
  • 2 answers
The place of 7 is 1,00,000 I.e., 6@,85,325 & place of 8 is 10,000 I.e., 67,@5,325. The difference is: 1,00,000-10,000=90,000.

Paru ? 5 years ago

The place of 7 is 1,00,000 I.e., 6@,85,325 & place of 8 is 10,000 I.e., 67,@5,325. The difference is: 1,00,000-10,000=90,000. Hope this is your answer ?.
  • 2 answers
You are right paru...

Paru ? 5 years ago

Hey Rishabh Type your answer in answer option. Don't type it in question option. If you don't know where to type your answer then see, first you have to press 'answer' option (you will get it below in every questions). Then you will get 'type your answer' option (that too you will get below). Then type your answer & send it. Hope you got it ?.
  • 2 answers

Nishant Bhati 5 years ago

X²+(a+b)-2ab

Paru ? 5 years ago

(X+a)(X+b)=X^2+(a+b)X+(ab)
  • 1 answers

Sumant Kumar 5 years ago

8×14/7×2)/(18/6×3)=8×2×2)/(3×3)=32/9=14/3
  • 2 answers

Gautam Sinha 5 years ago

2×1/√3/1-(1/√3) ² solve krna ok

Gautam Sinha 5 years ago

Ans √3
  • 1 answers

Itachi Uchiha ? 5 years ago

If u have already completed ur NCERT BOOK...and u want revise any chapter then firstly solve all the example, exercise questions , and solve sample paper, previous year paper of that chapter after this I hope u are ready for testing these chapter.....
  • 1 answers

Divya Divya 5 years ago

Exercise 4.1 question 4
  • 1 answers

Xyz Student 5 years ago

Solution: Let number be added is x -4/7 + x = 5/9 x= 5/9 + 4/7 = (35+36) upon 63 i.e. = 35+36/63 =71/63 Hence, required number is 71/63
  • 0 answers
  • 3 answers

Aaron E 5 years ago

Don't worry you can start from next year ?

Sahil Kumar 5 years ago

Abhi tak Sanskrit Aur english kee second book bhi nhi dekhi ,

Itachi Uchiha ? 5 years ago

Mene to abhi start hi ni kiya??????
  • 1 answers

Gaurav Seth 5 years ago

Let the original speed y km/ hr and total time taken be x h

Distance = xy  

[ Distance = time × speed]

(y + ½) (x - 1) = xy

xy -  y +  x/2 - ½ = xy

x/2 - y = ½ ………………(1)

[Distance covered in each case is same]

(y -1) (x + 3) = xy

xy + 3y -x -3 = xy

-x + 3y = 3……………..(2)

Multiply equation 1 by 3 ,

3x/2 - 3y = 3/2…………(3)

On adding eq 2 and 3,

-x + 3y = 3

3x/2 - 3y = 3/2

---------------------

-x +3x/2 = 3/2 +3

(-2x + 3x)/2 = (3+6)/2

x/2  = 9/2

x = 9  

On Putting x = 9 in eq 2

-x + 3y = 3

-9 + 3y = 3

3y = 3 +9

3y = 12

y = 12/3  

y = 4  

Distance covered by man = xy = 9 × 4 = 36 km

Original speed of walking = y = 4 km/h

Hence, the Distance covered by man is 36 km & Original speed of walking is 4 km/h.

  • 5 answers

Itachi Uchiha ? 5 years ago

No I waste my time to this question from 2 days .. ????

Itachi Uchiha ? 5 years ago

??✌️????✌️?????????

Itachi Uchiha ? 5 years ago

Btaiye ki kahan rule break hua h or mera tarika pasand aaya ho to thnks ka button jaroor press Krna....

Ayush Kumar 5 years ago

I know how you solved it, you have solved it by mistake

Itachi Uchiha ? 5 years ago

0=0 (as we all know).. If write it as 20-20 =25-25 (I didn't see any problem in this statement) Then, If we write 20-20 as (4×5)-(4×5) there is no problem.... similarly we write 25-25 as (5×5)-(5×5). ....then if we take 4 in L.H.S as a common digit. And take 5-5 in bracket..... similarly we take 5 in R.H.S as a common digit...and take 5-5 in bracket.... And in both the sides L.H.S AND R.H.S. we have to see that (5-5) in common then we cut it .. Now we have to see 4=5and we also write it as 2+2=5. ?????????????????? MENE KR DIYA JAISA MENE KAHA THA KI MENE RULE TODA H MATHS KA TO PLZZ BTAYIA KO MENE RULE KAHAM TODA H IS PURE QUESTION MEI ...??☺️?? ???????MENE KR DIYA ????

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App