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  • 1 answers

Gaurav Seth 5 years ago

A N S W E R

Given two numbers are 101 and 151

101, 151 doesn't any common prime

So, LCM is 101 × 151=15 , 251 

HCL of 101 & 151 is 1.

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  • 2 answers

Vansh Patidar 5 years ago

Take that number a and b so a = 60 b = ? LCM = 240 HCF = 12 according to mathematics law LCM × HCF = a × b Take that number a and b so a = 60 b = ? LCM = 240 HCF = 12 according to mathematics law LCM × HCF = a × b LCM × HCF/a = b 240 × 12 /60 = b 48 = b so the onother number is = b = 48 LCM × HCF/a = b 240 × 12 /60 = b 48 = b so the onother number is = b = 48

Gaurav Seth 5 years ago

Take that number a and b so
a = 60
b = ?
LCM = 240
HCF = 12

according to mathematics law

LCM × HCF = a × b

LCM × HCF/a = b

240 × 12 /60 = b

48 = b

so the onother number is = b = 48

  • 1 answers

Yogita Ingle 5 years ago

Let us assume that √5 is a rational number.

Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0
⇒√5=p/q

On squaring both the sides we get,
⇒5=p²/q²
⇒5q²=p² —————–(i)

p²/5= q²

So 5 divides p
p is a multiple of 5
⇒p=5m
⇒p²=25m² ————-(ii)
From equations (i) and (ii), we get,
5q²=25m²
⇒q²=5m²
⇒q² is a multiple of 5
⇒q is a multiple of 5
Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√5 is an irrational number

  • 1 answers

A K47 5 years ago

i)7x-2y/xy =5 =7x/xy - 2y/xy =5 =7/y - 2/x =5 ii)8x+7y/xy =15 =8x/xy+7y/xy=15 =8/y+7/x=15 Let 1/x=p and 1/y=q then by substituting these values we get, 7q-2p=5 and 8q+7p=15 By eliminating, q=1 and p=1; We know that 1/x=p and 1/y =q then by putting values of q and p we get x=1 and y =1.
  • 1 answers

Yogita Ingle 5 years ago

Euclid's division lemma :

Let a and b be any two positive

integers .Then there exists two

unique whole numbers q and r

such that

a = bq + r ,

0 ≤ r < b

Now , 900 and 270 , start with the larger integer , that is 900. Apply the
Division lemma , we get
900 = 270 × 3 + 90
270 = 90 × 3 + 0
The remainder has now become zero . Now our procedure stops.
Since the divisor at this stage is 90.
Therefore ,
HCF ( 900 , 270 ) = 90
 

  • 2 answers

Love Preet 5 years ago

Available on the app...

Daniya Khan 5 years ago

What mathematics chapter 3,4,5,6,7
  • 2 answers

Daniya Khan 5 years ago

Ya I also have same problem

Prianshu Kumar 5 years ago

Yes
  • 2 answers
If two triangles are similar to each other, then the ratio of the areas of these triangles will be equal to the square of the ratio of the corresponding sides of these triangles. It is given that the sides are in the ratio 4:9. Hence, the correct answer is 16 : 81.

Gaurav Seth 5 years ago

If two triangles are similar to each other, then the ratio of the areas of these triangles will be equal to the square of the ratio of the corresponding sides of these triangles.

It is given that the sides are in the ratio 4:9.

Therefore, ratio between areas of these triangles = (4 / 9)= 1681

Hence, the correct answer is 16 : 81.

  • 3 answers
Let 6x2 - 7x- 3 be p(x) =0 so,6x2 - 7x-3 =0  6x2 - (9-2) x -3  6x2 - 9x + 2x -3 (6x2 - 9x)(2x-3) 3x(2x-3) +1 (2x-3) (3x +1) (2x -3) = 0 ⇒ 3x +1 = 0     ⇒ 2x -3 = 0 ⇒ x =3/2 ⇒ x = - 1/3                             sum of zeroes = -1/3 + 3/2  =7/6   = -b/a product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a

Archita Gupta 5 years ago

6x²- 7x-3 6x²+2x-9x-3 2x(3x+1)-3(3x+1) (2x-3) (3x+1) 2x-3=0 2x=3 X=3/2 3x+1=0 3x= -1 x=-1/3 Sum of zeroes =- coefficient x/coefficient of x² 3/2+(-1)/3=-(-7)/6 9-2/6 =7/6 7/6=7/6 Produce of zeroes = constant term / coefficient of x² 3/2×(-1)/3=(-3)/6 -3/6=-3/6

Gaurav Seth 5 years ago

Let 6x2 - 7x- 3 be p(x) =0

so,6x- 7x-3 =0

 6x2 - (9-2) x -3

 6x- 9x + 2x -3

(6x- 9x)(2x-3)

3x(2x-3) +1 (2x-3)

(3x +1) (2x -3) = 0

⇒ 3x +1 = 0    

⇒ 2x -3 = 0

⇒ x =3/2

⇒ x = - 1/3                            

sum of zeroes = -1/3 + 3/2  =7/6   = -b/a

product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a 

  • 2 answers

Shivdeep Singh 5 years ago

Let a=2 b=2 a=b a×a=ab a^a-b^b = ab-b^b (a+b)(a-b)=b(a-b) a+b =b(a-b)/(a-b) 2+2= 2
If A,B and C are interior angles of a triangle ABC,then show that sin (B+C/2)=cos A/2
  • 1 answers

Gautam Sinha 5 years ago

4x- 24
  • 2 answers
Find the cubic of polynomial given number as zeroes

Yogita Ingle 5 years ago

If x = 3

then 3x + (k-3)x+9=0​

3(3) +( k - 3)3 + 9 =0

9 + 3k - 9 + 9 =0

3k = -9

k =-9/3 = -3

 

  • 3 answers

Prince Kumar 5 years ago

Question is wrong either incomplete

Abin Shah 5 years ago

84

Shiv Jee Gupta 5 years ago

Hi
  • 1 answers
Sum of zeroes=9/8 Because,a³+b³=(a+b){(a+b)²-3ab}
  • 1 answers

Vaishu ? 5 years ago

The midpoint theorem states that the line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side.
  • 5 answers

Sushant Sharma 5 years ago

We have x+y=3 ----------(i) and. 3x+2y=4 --_------(ii) From eq-(i). we'll get y=3-x -----(iii) Now put the value in eq-(ii) We ll get ,,,,, ::. :: 3x+2(3-x)=4 3x+6-2x=4 3x-2x=4-6 x=-2 Hurray ?????We solve it
x = -2

Paul Mongku 5 years ago

By method of elimination Let, x+y=3......(1) 3x+2y=4.....(2) Multiply (1) by 3 we get, 3x+3y=9......(3) Now, subtract (2)from(3) 3x+3y= 9 - 3x+2y= 4 - - ______________ Y=5.....(4) Again substitute (4) in (1) we get, x+5=3 x =3-5 x = -2 ....ans

Yogita Ingle 5 years ago

 x+y=3 -------- (i)

 3x+2y=4 ......... (ii)

Multiply (i) by 2 and subtract from (ii)

3x + 2y = 4

2x + 2y = 6

____________

x = -2

Arham Hussain 5 years ago

-2
  • 2 answers

Vaishu ? 5 years ago

Infact their are many numbers

Vaishu ? 5 years ago

7.6 is the number which is never between 0&1.
  • 1 answers

Vaishu ? 5 years ago

•sin θ = Opposite Side/Hypotenuse •cos θ = Adjacent Side/Hypotenuse •tan θ = Opposite Side/Adjacent Side •sec θ = Hypotenuse/Adjacent Side •cosec θ = Hypotenuse/Opposite Side •cot θ = Adjacent Side/Opposite Side •cosec θ = 1/sin θ •sec θ = 1/cos θ •cot θ = 1/tan θ •sin θ = 1/cosec θ •cos θ = 1/sec θ •tan θ = 1/cot θ
  • 2 answers
Gando

Vaishu ? 5 years ago

1) Probability =( No. of the favourable outcomes)÷ (number of all possible outcomes). 2) Probability of event,P(E) + Probability of an event not happening, P(Ē) = 1
  • 1 answers

Gaurav Seth 5 years ago

et the assume mean A = 42

Classes Mid value(x1) d1 = x1 - 42 u1=x1-425 f1 f1u1
25 - 29 27 -15 -3 14 -42
30 - 34 32 -10 -2 22 -44
35 - 39 37 -5 -1 16 -16
40 - 44 42 0 0 6 0
45 - 49 47 5 1 5 5
50 - 54 52 10 2 3 6
55 - 59 57 15 3 4 12
        N = 70 ∑f1u1=-79

We have

A = 42, h = 5

Mean =A+h×∑f1u1N

=42+5×-7970

=42+-39570

=42-39570

= 42 - 5.643

= 36.357

 

 

 

 

 

  • 5 answers

Nishant Bhati 5 years ago

3

Nitish Yadav 5 years ago

Answer ha 3

Piyush Raj 5 years ago

3

Yogita Ingle 5 years ago

2 ÷ 2 +  2

= 1 + 2

= 3

Itachi Uchiha ? 5 years ago

2÷2+2=3.

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