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Ask QuestionPosted by Mehakpreet Kaur Brar 4 years, 10 months ago
- 1 answers
Posted by Navjot Singh 4 years, 10 months ago
- 2 answers
Vansh Patidar 4 years, 10 months ago
Gaurav Seth 4 years, 10 months ago
Take that number a and b so
a = 60
b = ?
LCM = 240
HCF = 12
according to mathematics law
LCM × HCF = a × b
LCM × HCF/a = b
240 × 12 /60 = b
48 = b
so the onother number is = b = 48
Posted by Anushka Singh 4 years, 10 months ago
- 1 answers
Yogita Ingle 4 years, 10 months ago
Let us assume that √5 is a rational number.
Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0
⇒√5=p/q
On squaring both the sides we get,
⇒5=p²/q²
⇒5q²=p² —————–(i)
p²/5= q²
So 5 divides p
p is a multiple of 5
⇒p=5m
⇒p²=25m² ————-(ii)
From equations (i) and (ii), we get,
5q²=25m²
⇒q²=5m²
⇒q² is a multiple of 5
⇒q is a multiple of 5
Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number
√5 is an irrational number
Posted by उत्सव राज 4 years, 10 months ago
- 1 answers
A K47 4 years, 10 months ago
Posted by Akash Deep 4 years, 10 months ago
- 0 answers
Posted by Veraiah Kesam 4 years, 10 months ago
- 1 answers
Yogita Ingle 4 years, 10 months ago
Euclid's division lemma :
Let a and b be any two positive
integers .Then there exists two
unique whole numbers q and r
such that
a = bq + r ,
0 ≤ r < b
Now , 900 and 270 , start with the larger integer , that is 900. Apply the
Division lemma , we get
900 = 270 × 3 + 90
270 = 90 × 3 + 0
The remainder has now become zero . Now our procedure stops.
Since the divisor at this stage is 90.
Therefore ,
HCF ( 900 , 270 ) = 90
Posted by Jayank Mishra 4 years, 10 months ago
- 2 answers
Posted by Nandini Soni 4 years, 10 months ago
- 2 answers
Posted by Aman Kumar 4 years, 10 months ago
- 2 answers
King Adithya H M... 4 years, 10 months ago
Gaurav Seth 4 years, 10 months ago
If two triangles are similar to each other, then the ratio of the areas of these triangles will be equal to the square of the ratio of the corresponding sides of these triangles.
It is given that the sides are in the ratio 4:9.
Therefore, ratio between areas of these triangles = (4 / 9)2 = 1681
Hence, the correct answer is 16 : 81.
Posted by Janvi Rajput 4 years, 10 months ago
- 3 answers
King Adithya H M... 4 years, 10 months ago
Archita Gupta 4 years, 10 months ago
Gaurav Seth 4 years, 10 months ago
Let 6x2 - 7x- 3 be p(x) =0
so,6x2 - 7x-3 =0
6x2 - (9-2) x -3
6x2 - 9x + 2x -3
(6x2 - 9x)(2x-3)
3x(2x-3) +1 (2x-3)
(3x +1) (2x -3) = 0
⇒ 3x +1 = 0
⇒ 2x -3 = 0
⇒ x =3/2
⇒ x = - 1/3
sum of zeroes = -1/3 + 3/2 =7/6 = -b/a
product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a
Posted by Dheeraj Kumar 4 years, 10 months ago
- 2 answers
Shivdeep Singh 4 years, 10 months ago
Sonu Kumar Rajbhar 4 years, 10 months ago
Posted by Manish Angural 4 years, 10 months ago
- 1 answers
Posted by Md Danish Siddiqui 4 years, 10 months ago
- 2 answers
Mebanangtei Kshiar 4 years, 10 months ago
Yogita Ingle 4 years, 10 months ago
If x = 3
then 3x + (k-3)x+9=0
3(3) +( k - 3)3 + 9 =0
9 + 3k - 9 + 9 =0
3k = -9
k =-9/3 = -3
Posted by Akhya Sahay 4 years, 10 months ago
- 4 answers
Posted by Khushi Upadhyay 4 years, 10 months ago
- 3 answers
Posted by Arham Hussain 4 years, 10 months ago
- 1 answers
Himanshu Pathak Pathak 4 years, 10 months ago
Posted by Nisha Raman 4 years, 10 months ago
- 1 answers
Posted by Yogesh Kumar 4 years, 10 months ago
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Vaishu ? 4 years, 10 months ago
Posted by Arham Hussain 4 years, 10 months ago
- 5 answers
Sushant Sharma 4 years, 10 months ago
Paul Mongku 4 years, 10 months ago
Yogita Ingle 4 years, 10 months ago
x+y=3 -------- (i)
3x+2y=4 ......... (ii)
Multiply (i) by 2 and subtract from (ii)
3x + 2y = 4
2x + 2y = 6
____________
x = -2
Posted by Jesh . 4 years, 10 months ago
- 2 answers
Posted by Bhupendra Dhapkari 4 years, 10 months ago
- 1 answers
Vaishu ? 4 years, 10 months ago
Posted by Chirag Prajapati 4 years, 10 months ago
- 2 answers
Vaishu ? 4 years, 10 months ago
Posted by Sunil Gurjar 4 years, 10 months ago
- 1 answers
Gaurav Seth 4 years, 10 months ago
et the assume mean A = 42
Classes | Mid value(x1) | d1 = x1 - 42 | u1=x1-425 | f1 | f1u1 |
25 - 29 | 27 | -15 | -3 | 14 | -42 |
30 - 34 | 32 | -10 | -2 | 22 | -44 |
35 - 39 | 37 | -5 | -1 | 16 | -16 |
40 - 44 | 42 | 0 | 0 | 6 | 0 |
45 - 49 | 47 | 5 | 1 | 5 | 5 |
50 - 54 | 52 | 10 | 2 | 3 | 6 |
55 - 59 | 57 | 15 | 3 | 4 | 12 |
N = 70 | ∑f1u1=-79 |
We have
A = 42, h = 5
Mean =A+h×∑f1u1N
=42+5×-7970
=42+-39570
=42-39570
= 42 - 5.643
= 36.357
Posted by Md Sahddab Khan 4 years, 10 months ago
- 5 answers
Posted by Vikas Kumar 4 years, 10 months ago
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Posted by Divya Upadhyay 4 years, 10 months ago
- 1 answers
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Gaurav Seth 4 years, 10 months ago
A N S W E R
Given two numbers are 101 and 151
101, 151 doesn't any common prime
So, LCM is 101 × 151=15 , 251
HCL of 101 & 151 is 1.
<section> </section>1Thank You