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  • 1 answers

Ayush Kumar 4 years, 10 months ago

Cot^2 theta + 1 = cosec^2 theta (3/x)^2 + 1 = (3x)^2 9/x^2 + 1= 9x^2 9/x^2 - 9x^2 = -1 9(1/x^2 - x^2) = -1 3(1/x^2 - x^2) = -1/3 Therefore, 3(x^2 - 1/x^2) = 1/3
  • 0 answers
  • 5 answers

Itachi Uchiha ? 4 years, 10 months ago

Thnku (^£^) ......

: (ᵔᴥᵔ) ???? (ᵔᴥᵔ) 4 years, 10 months ago

Ohhh gr8?

Nasir Ul Haq 4 years, 10 months ago

.................

Itachi Uchiha ? 4 years, 10 months ago

But no I will prove it at 2:30 pm get ready..........

Itachi Uchiha ? 4 years, 10 months ago

Someone said it is done by mistake ???.....
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  • 1 answers

Kavita Yadav 4 years, 10 months ago

To convert the given trigonometric ratios in terms of cot functions, use trigonometric formulas We know that, cosec2A – cot2A = 1 cosec2A = 1 + cot2A Since cosec function is the inverse of sin function, it is written as 1/sin2A = 1 + cot2A Now, rearrange the terms, it becomes sin2A = 1/(1+cot2A) Now, take square roots on both sides, we get sin A = ±1/(√(1+cot2A) The above equation defines the sin function in terms of cot function Now, to express sec function in terms of cot function, use this formula sin2A = 1/ (1+cot2A) Now, represent the sin function as cos function 1 – cos2A = 1/ (1+cot2A) Rearrange the terms, cos2A = 1 – 1/(1+cot2A) ⇒cos2A = (1-1+cot2A)/(1+cot2A) Since sec function is the inverse of cos function, ⇒ 1/sec2A = cot2A/(1+cot2A) Take the reciprocal and square roots on both sides, we get ⇒ sec A = ±√ (1+cot2A)/cotA Now, to express tan function in terms of cot function tan A = sin A/cos A and cot A = cos A/sin A Since cot function is the inverse of tan function, it is rewritten as tan A = 1/cot A
  • 1 answers

Ayushi Rai 4 years, 10 months ago

17
  • 1 answers

G.Mohammed Fayaz✨ Fz Fayaz 4 years, 6 months ago

Yes
  • 1 answers

Subhalaxmi P 4 years, 10 months ago

Middle term factorization
  • 2 answers

Vidya Mudaraddi 4 years, 10 months ago

2x²+3x+2=0 2x²+4x-1x+2=0 2x(x+2)-1(x+2)=0 (X+2) (2x-1)=0 X=-2 & x=1/2

Subhalaxmi P 4 years, 10 months ago

X^2+x+2x+2 x(x+1)+2(x+1) (x+1)(x+2) x = -1,-2
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  • 3 answers

Dhawanpreet Kaur 4 years, 10 months ago

Cos A =4/5 so, b/h=4/5 , b =4, h=5 and then tan A =3/4 ,cot A =4/3

A . 4 years, 10 months ago

TanA=3/4 and cotA=4/3

Yogita Ingle 4 years, 10 months ago

cos A = 4/5

sin A =√1 - cos2 A = √1 - (4/5)2 = √1 - 16/25 =√(25-16)/25 = √9/25 = 3/5

tan A = sinA/cos A = 3/4

ans cot A = cos A /sinA = 4/3

  • 4 answers

Dhawanpreet Kaur 4 years, 10 months ago

P upon H U should learn the table P B P H H B And now see carefully Up to down each line first is P upon H is SIN Q where q is theta B upon H is cos Q and P upon B is tan q

Vaishnavi Gupta 4 years, 10 months ago

P/h

Varista Gupta 4 years, 10 months ago

Perpendicular/hypothesis

Vaishnavi Singh 4 years, 10 months ago

p/h
  • 2 answers

Vaishnavi Gupta 4 years, 10 months ago

Chapter?????

Prince Yadav 4 years, 10 months ago

Chapter ???????
  • 2 answers

Vaishnavi Gupta 4 years, 10 months ago

Ji chapter btane ka kasht kree

Prince Yadav 4 years, 10 months ago

Chapter ?????
  • 2 answers

Sakshi Jagtap 4 years, 10 months ago

ohh nice Atul....from where uhh have taken this?

Atul Kumar 4 years, 10 months ago

CHAPTER TOPICS REMOVED ?UNIT I-NUMBER SYSTEMS 〰️ ?REAL NUMBERS ➡️? Euclid’s division lemma ?UNIT II-ALGEBRA 〰️ ?POLYNOMIALS ➡️?Statement and simple problems on division algorithm for polynomials with real coefficients. ?PAIR OF LINEAR EQUATIONS IN TWO VARIABLES ➡️ ?cross multiplication method ?QUADRATIC EQUATIONS ➡️ ?Situational problems based on equations reducible to quadratic equations ?ARITHMETIC PROGRESSIONS ➡️ ?Application in solving daily life problems based on sum to n terms ?UNIT III-COORDINATE GEOMETRY 〰️ ?COORDINATE GEOMETRY ➡️ ? Area of a triangle. ?UNIT IV-GEOMETRY 〰️ ?TRIANGLES➡️Proof of the following theorems are deleted ?The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. ?In a triangle, if the square on one side is equal to sum of the squares on the other two sides, the angle opposite to the first side is a right angle. ?CIRCLES ➡️No deletion ?CONSTRUCTIONS ➡️Construction of a triangle similar to a given triangle. ?UNIT V- TRIGONOMETRY 〰️ ?INTRODUCTION TO TRIGONOMETRY ➡️ ?motivate the ratios whichever are defined at 0o and 90o TRIGONOMETRIC IDENTITIES➡️ ?Trigonometric ratios of complementary angles. ?HEIGHTS AND DISTANCES➡️No deletion ?UNIT VI-MENSURATION 〰️ ?AREAS RELATED TO CIRCLES ➡️ Problems on central angle of 120° ?SURFACE AREAS AND VOLUMES ➡️ Frustum of a cone. ?UNIT VI-STATISTICS & PROBABILITY 〰️ ?STATISTICS ➡️?Step deviation Method for finding the mean ?Cumulative Frequency graph ?PROBABILITY➡️ No deletion
  • 2 answers

Aman Singh 4 years, 3 months ago

Thanks

Anjali Bisht 4 years, 10 months ago

Question:- (7-2√3) Solution:- Let us assume that (7-2√3) is a rational number. Therefore we can write in the form of p/q. Where p and q are co- prime numbers. 7-2√3=p/q 7-p/q=2√3 7q-p/q=2√3 7q-p/2q=√3 √3=7q-p/2q Since, we know that √3 is an irrational number . Hence our assumption is wrong 7q-p/q or 7-2√3 is an irrational number.. Hence Proved..... I hope now your doubt is clear??
  • 1 answers

Varun Soni 4 years, 10 months ago

https://images.app.goo.gl/eJK1UnZKtYo2NaEA6
  • 4 answers

Xyz Student 4 years, 10 months ago

Solution: Given AB=6 cm, BC=4 m, QR=28 m. To find:PQ. In ∆ABC and ∆PQR. Angle B= Angle Q= 90°[ Vertical]. Angle ACB= Angle PRQ [same angle on both, from sum]. By AA Criterion ∆ABC ∆PQR Corresponding sides of similar triangles are in proportion AB/PQ = BC/QR = 6/PQ = 4/28. PQ = (28*6)/4 = 42 cm. Height of tower = 42m

?Isha .B 4 years, 10 months ago

Please...Explain... The Method...

Atul Kumar 4 years, 10 months ago

42meter

Akhya Sahay 4 years, 10 months ago

42 m
  • 2 answers

Varun Soni 4 years, 10 months ago

Trigonometry formula Sin=Oppo/hypo Cos=adj/hypo Tan=Oppo/adj Cosec=hypo/Oppo Sec=Hypo/adj Cot=Adj/Oppo Sin=1/cosec Cos=1/sec Tan= sin/cos Cot= cos

Akhilesh Achant 4 years, 10 months ago

Trigonometry formula Sin=Oppo/hypo Cos=adj/hypo Tan=Oppo/adj Cosec=hypo/Oppo Sec=Hypo/adj Cot=Adj/Oppo Sin=1/cosec Cos=1/sec Tan= sin/cos Cot= cos/sin
  • 1 answers

Esha Kendhe 4 years, 10 months ago

a consecutive number is the one which follows one another without gaps Example 1,2,3...
  • 5 answers

Munmun Naresh 4 years, 10 months ago

2πrh

Nisha???????? Bharti 4 years, 10 months ago

2πrh

Raj Singh 4 years, 10 months ago

2 π r h + 2 π r 2 2 \pi rh + 2 \pi r^{2} 2πrh+2πr2.

?Mansi ? 4 years, 10 months ago

the CSA of a cylinder will be: 2*π*R*H

Yogita Ingle 4 years, 10 months ago

Curved Surface Area- The curved surface area is defined as the area of only curved surface, leaving the circular top and base.

Formula for calculating the Curved Surface Area (C.S.A.)-

Consider a cylinder having a height ‘h’ and base radius ‘r’.

The curved surface area of a cylinder is given as-

C.S.A.= 

  • 5 answers

?Mansi ? 4 years, 10 months ago

3:5

Mohit Gupta 4 years, 10 months ago

And the value of X is 9.??

Mohit Gupta 4 years, 10 months ago

Hey! That is not the answer by mistake I typed it so answer is 3:5

Mohit Gupta 4 years, 10 months ago

Ratio is 7:2

Daksh Khandelwal 4 years, 10 months ago

Chapter 7 exercise 7.2
  • 1 answers

Gaurav Seth 4 years, 10 months ago

Height is the measurement of an object in the vertical direction and distance is the measurement of an object from a particular point in the horizontal direction. If we imagine a line connecting the point of observation to the topmost point of the object then the horizontal line, vertical line and the imaginary line will form a triangle.

Observe the figure. Consider the observer to be at point C. The height of the object is shown by line AB. The distance of the object from the observer is given by line BC. The object may or may not be perpendicular to the ground. Line AC represents the Line of Sight when the observer is observing the topmost point of the object. Angle α represents the angle of elevation and Angle β represents the angle of depression.

Using trigonometry, if we are provided with any of the two quantities that may be a side or an angle, we can calculate all the rest of the quantities. By the law of alternate angles, the angle of elevation and angle of depression are consequently equal in magnitude (α = β). Tan α is equal to the ratio of the height and distance.

You can be provided with any two of the following information:

  • The distance of the object from the observer
  • The height of the object
  • Angle at which the observer views the topmost point of the object (angle of elevation)
  • The angle at which the observer views the object when the observer is on top of a tower/building (angle of depression)
  • 1 answers

Pulkit Kumawat 4 years, 10 months ago

Question
  • 3 answers

Yogita Ingle 4 years, 10 months ago

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid’s division lemma
a=bq+r

a=6q+r

where , a=0,1,2,3,4,5
then,
a=6q
or
a=6q+1
or
a=6q+2
or
a=6q+3
or
a=6q+4
or
a=6q+5

but here,
a=6q+1 & a=6q+3 & a=6q+5 are odd.

Bhaduram Hembra 4 years, 10 months ago

What is meant by the idea of satyagraha ?

Bhaduram Hembra 4 years, 10 months ago

What is gegraphy
  • 2 answers

Sakshi Jagtap 4 years, 10 months ago

??hlo......If that person is upset? at u there will be a particular reason behind her/his upsetness, it might be bcuz of some mistake happened from uhh or something else. U both will be friends ?or besties ? or ❤️luv birds, so u both will be doing some fun or cute gossips or cute fighting's in past. So u should repeat that gossips with ur dash or tell that person about ur past fighting's..... absolutely then that person will laugh?. Actually i have a real experience about this thing, my boyfriend was a bit upset at me then i noticed for some days n then i refreshed the old fun n memories between us then he started to laughing n give me a hot hug. I wish ?that this works on uhh. All the best?......IF I WAS KNOWING THE REASON BEHIND HIS OR HER UPSETNESS, I MIGHT HAVE HELPED UHH MORE NICELY.

Shikha Gupta 4 years, 10 months ago

Can you please explain from which study side u have asked this question

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