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  • 3 answers

Shivam Sharma 4 years, 9 months ago

2x²-x+1/8=0 Multiplying the eq. by 8 16x²-8x+1=0 16x²-4x-4x+1=0 4x(4x-1) -1(4x-1) =0 X=1/4, 1/4

Gupta Binita 4 years, 9 months ago

thank u

Yogita Ingle 4 years, 9 months ago

Hence the solution is 

  • 3 answers

Palak Preet Kaur 4 years, 9 months ago

A = 30° = = tan60° = Therefore, The value of = $\sqrt{3}$

Bro . 4 years, 9 months ago

2tan30°/ (1 + tan²30°) (2/√3)/(1+ 1/3) (2/√3)/ (4/3) (2/√3) × (3/4) 3/2√3 After rationalisation, √3/2

Yogita Ingle 4 years, 9 months ago

A = 30°

tan60°

= 

Therefore,

The value of

 = $\sqrt{3}$

  • 1 answers

Gaurav Seth 4 years, 9 months ago

Let the first term of an A.P. = a

And common difference = d

Given: 9th term of an A.P. is 0. Therefore,

We have to prove that 

Thus,

And

From equation (2) and (3),

Hence provedc

  • 2 answers

Manpreet Yadav 4 years, 9 months ago

a=-3 d=4 A10=33

Yo Yo Mani Singh 9 4 years, 9 months ago

sum of the first five terms of an AP is 25 and the sum of its next five terms is -75. Find the 10th term of its AP
  • 5 answers

Neha Kumari 4 years, 9 months ago

CosecA = 4\3

Rekhadei Pujari 4 years, 9 months ago

Given, sin A=3/4. We know, Cosec A =1/sin A Then, cosec A=1/3/4 =4/3

Bro . 4 years, 9 months ago

sinA = 3/4. cosecA = 1/sinA. cosecA = 4/3

Suruchi Devi 4 years, 9 months ago

Sin A=3/4 Since, cosec A=1/sin A Therefore, cosec A=1/3/4 => cosec A =4/3

Manpreet Yadav 4 years, 9 months ago

4/3
  • 1 answers

Ankit Mali 4 years, 9 months ago

Search it on Google ?
  • 2 answers

Vivek Gupta 4 years, 8 months ago

Ok

Gaurav Seth 4 years, 9 months ago

Don't post personal information, mobile numbers and other details.
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  • 3 answers

Rekhadei Pujari 4 years, 9 months ago

U can search in google

Laxmi S.P? 4 years, 9 months ago

Type class 10 cbse solved sample papers

Laxmi S.P? 4 years, 9 months ago

In Google
  • 2 answers

Laxmi S.P? 4 years, 9 months ago

Yàaa

Furry Friend 4 years, 9 months ago

Yes, you need to be thorough with the concepts by then. And last 2 months you can utilise your time in revision
  • 2 answers

Manpreet Yadav 4 years, 9 months ago

14

Yogesh Meena 4 years, 9 months ago

14
  • 1 answers

Gopika Satheesh 4 years, 9 months ago

1.  In ΔLMN, ∟L = 50°and ∟N= 60°. If ΔLMN is similar to ΔPQR, then find ∟Q. (AI CBSE 2009) 2.  If areas of two similar triangles are in the ratio 25:64, write the ratio of their corresponding sides. (AI CBSE 2009) 3.  D, E and F are mid points of sides BC, AC and AB respectively of triangle ABC. Find ar(ΔDEF)/ar(ΔABC). ( AI CBSE 2008) 4.  If one diagonal of a trapezium divides the other diagonal in the ratio 1:2. Prove that one of the parallel sides is double the other. (CBSE 2010) 5.  ABC is a right triangle, right angled at A, and D is the mid-point of AB. Prove that BC2 = CD2 + 3BD2. (AI CBSE 2009 C) 6.  If the diagonals of a quadrilateral divide each other proportionally, prove that it is a trapezium. (CBSE 2008) 7.  Triangle ABC is right angled at B and D is the mid-point of BC. Prove that:- AC2 = 4AD2 . 3AB2.(AI CBSE 2008 C) 8.  E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABC is similar to ΔCFB. (AI CBSE 2008)
  • 1 answers

Gaurav Seth 4 years, 9 months ago

asinθ + bcosθ = c
taking square both sides,
(asinθ + bcosθ)² = c²
⇒a²sin²θ + b²cos²θ + 2absinθ.cosθ = c² --------(1)

Let acosθ - bsinθ = x
Squaring both sides
(acosθ - bsinθ)² = x²
⇒a²cos²θ + b²sin²θ -2absinθ.cosθ = x² ------(2)

Add equation (1) and (2),
a²sin²θ + b²cos²θ +2abinθ.cosθ + a²cos²θ + b²sin²θ -2absinθ.cosθ = c² + x²
⇒(a² + b²)cos²θ + (a² +b²)sin²θ = c² + x²
⇒(a² + b²)[sin²θ + cos²θ ] = c² + x²
⇒(a² + b²) = c² + x² [∵ sin²x + cos²x = 1 ]
⇒(a² + b² - c²) = x²
Take square root both sides,

Hence, acosθ - bsinθ = 

  • 0 answers
  • 1 answers

Gaurav Seth 4 years, 9 months ago

Q u e s t i o n :P (-2, 5) and Q (3, 2) are two points. Find the co-ordinates of the point R on PQ such that PR = 2QR.
A n s w e r:

PR:QR = 2:1

R(4 / 3, 3)

  • 2 answers

Pallavi Kumari 4 years, 9 months ago

Thank you

Yogita Ingle 4 years, 9 months ago

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid’s division lemma
a=bq+r

a=6q+r

where , a=0,1,2,3,4,5
then,
a=6q
or
a=6q+1
or
a=6q+2
or
a=6q+3
or
a=6q+4
or
a=6q+5

but here,
a=6q+1 & a=6q+3 & a=6q+5 are odd.

  • 1 answers

Yogita Ingle 4 years, 9 months ago

A prime number has exactly two factors, 1 and the number itself. So, Total numbers of a factor of a prime numbers is 2.

  • 1 answers

Yogita Ingle 4 years, 9 months ago

We know that,
sec A = 1/cos A
⇒ cos A = 1/sec A
cos²A + sin²A = 1
⇒  sin²A = 1 – cos²A
⇒  sin²A = 1 – (1/sec²A)                          (cosA= 1/secA)
⇒  sin²A = (sec²A-1)/sec²A

⇒sinA = √((sec²A-1)/sec²A)

sinA = √(sec²A-1) ÷ (secA)............................(i)

sin A = 1/cosec A
⇒ cosec A = 1/sin A

cosecA= secA ÷√sec²A-1                 (from eq i)
Now,
sec²A – tan²A = 1
⇒ tan²A = sec²A + 1

tanA = √sec²A + 1.....................................(ii)

tan A = 1/cot A
⇒ cot A = 1/tan A

cotA  = 1/√sec²A + 1                  (from eq ii)

  • 2 answers

Ayush Patel 4 years, 9 months ago

It has no root

Ritik Yadav 4 years, 9 months ago

x=-root2 and x=3root2
  • 1 answers

Mayank Chaudhary 4 years, 9 months ago

So what next??
  • 3 answers

Darshan Patel 4 years, 9 months ago

In Ch 3 cross multiplication method was deleted

Suhana Pulyani 4 years, 9 months ago

Topics are reduced Step deviation Cross multiplication Cubic polynomials

Aman Kumar 4 years, 9 months ago

No any chapter is reduced only the sub topics of some chapters is reduced..
  • 1 answers

Aman Kumar 4 years, 9 months ago

Ar.= πr2=301.84sqcm r2=301.84×7÷22=96.04 r=√96.04=9.8cm r=9.8 circumference=2πr=2×22÷7×9.8=44×1.4=61.6 cm
  • 1 answers

Aman Singh 4 years, 9 months ago

I assume you mean “IF a die is tossed three times, what is the probability of no fives?” Die #1 can do so with probability 5 / 6 (meaning, no fives). Ditto for #2, #3. Hence, the required probability is (5/6)*(5/6)*(5/6) = 125/216, which is almost 58%.
  • 1 answers

Aman Kumar 4 years, 9 months ago

No nothing like this has been provided untill you subscribe to primium। But u can find it in sample papers

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