Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Gupta Binita 4 years, 9 months ago
- 3 answers
Posted by Harkirat Singh 4 years, 9 months ago
- 3 answers
Palak Preet Kaur 4 years, 9 months ago
Bro . 4 years, 9 months ago
Yogita Ingle 4 years, 9 months ago
A = 30°
=
= tan60°
=
Therefore,
The value of
= $\sqrt{3}$
Posted by Tushar . 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Let the first term of an A.P. = a
And common difference = d
Given: 9th term of an A.P. is 0. Therefore,
We have to prove that
Thus,
And
From equation (2) and (3),
Hence provedc
Posted by Yo Yo Mani Singh 9 4 years, 9 months ago
- 2 answers
Yo Yo Mani Singh 9 4 years, 9 months ago
Posted by Simran . 4 years, 9 months ago
- 5 answers
Rekhadei Pujari 4 years, 9 months ago
Suruchi Devi 4 years, 9 months ago
Posted by Ankit Mali 4 years, 9 months ago
- 1 answers
Posted by Vivek Gupta 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
Ask specific question which are clear and concise.
Posted by Meera Sudharsan 4 years, 9 months ago
- 3 answers
Posted by Utsav Srivastava 4 years, 9 months ago
- 2 answers
Furry Friend 4 years, 9 months ago
Posted by Ravi Gupta 4 years, 9 months ago
- 2 answers
Posted by Thrisha Ramakrishna 4 years, 9 months ago
- 1 answers
Gopika Satheesh 4 years, 9 months ago
Posted by Renu Bala 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
asinθ + bcosθ = c
taking square both sides,
(asinθ + bcosθ)² = c²
⇒a²sin²θ + b²cos²θ + 2absinθ.cosθ = c² --------(1)
Let acosθ - bsinθ = x
Squaring both sides
(acosθ - bsinθ)² = x²
⇒a²cos²θ + b²sin²θ -2absinθ.cosθ = x² ------(2)
Add equation (1) and (2),
a²sin²θ + b²cos²θ +2abinθ.cosθ + a²cos²θ + b²sin²θ -2absinθ.cosθ = c² + x²
⇒(a² + b²)cos²θ + (a² +b²)sin²θ = c² + x²
⇒(a² + b²)[sin²θ + cos²θ ] = c² + x²
⇒(a² + b²) = c² + x² [∵ sin²x + cos²x = 1 ]
⇒(a² + b² - c²) = x²
Take square root both sides,
Hence, acosθ - bsinθ =
Posted by Priya Nadimuthu 4 years, 9 months ago
- 0 answers
Posted by Pallavi Kumari 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Q u e s t i o n :P (-2, 5) and Q (3, 2) are two points. Find the co-ordinates of the point R on PQ such that PR = 2QR.
A n s w e r:
PR:QR = 2:1
R(4 / 3, 3)
Posted by Pallavi Kumari 4 years, 9 months ago
- 2 answers
Yogita Ingle 4 years, 9 months ago
Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.
according to Euclid’s division lemma
a=bq+r
a=6q+r
where , a=0,1,2,3,4,5
then,
a=6q
or
a=6q+1
or
a=6q+2
or
a=6q+3
or
a=6q+4
or
a=6q+5
but here,
a=6q+1 & a=6q+3 & a=6q+5 are odd.
Posted by P B Pujari 4 years, 9 months ago
- 0 answers
Posted by Aaradhya Kumari 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
A prime number has exactly two factors, 1 and the number itself. So, Total numbers of a factor of a prime numbers is 2.
Posted by Parvathy Nair 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
We know that,
sec A = 1/cos A
⇒ cos A = 1/sec A
cos²A + sin²A = 1
⇒ sin²A = 1 – cos²A
⇒ sin²A = 1 – (1/sec²A) (cosA= 1/secA)
⇒ sin²A = (sec²A-1)/sec²A
⇒sinA = √((sec²A-1)/sec²A)
⇒sinA = √(sec²A-1) ÷ (secA)............................(i)
sin A = 1/cosec A
⇒ cosec A = 1/sin A
⇒cosecA= secA ÷√sec²A-1 (from eq i)
Now,
sec²A – tan²A = 1
⇒ tan²A = sec²A + 1
⇒tanA = √sec²A + 1.....................................(ii)
tan A = 1/cot A
⇒ cot A = 1/tan A
⇒cotA = 1/√sec²A + 1 (from eq ii)
Posted by Rutvika Dhodi 4 years, 9 months ago
- 2 answers
Posted by Poojitha Bv 4 years, 9 months ago
- 1 answers
Posted by Kunal Shukla 4 years, 9 months ago
- 1 answers
Posted by Ravi Choudhary 4 years, 9 months ago
- 3 answers
Suhana Pulyani 4 years, 9 months ago
Aman Kumar 4 years, 9 months ago
Posted by Shadow Vector 4 years, 9 months ago
- 1 answers
Aman Kumar 4 years, 9 months ago
Posted by Ok Siñgh 4 years, 9 months ago
- 1 answers
Aman Singh 4 years, 9 months ago
Posted by Tejal Bobde 4 years, 9 months ago
- 1 answers
Aman Kumar 4 years, 9 months ago
Posted by Saniya Khanam 4 years, 9 months ago
- 1 answers
Posted by Saniya Khanam 4 years, 9 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Shivam Sharma 4 years, 9 months ago
0Thank You