Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Riya 10Th Green 4 years, 9 months ago
- 1 answers
Posted by Vishwa Michael 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
Tangents drawn from am external point to a circle
are equal in length
so from the diagram we get
AH= AE; DH = DG; CG=CF
4−x=x y=2y−3
2x=4 y=3
x=2
As x=2 DH = 5 − AH = 5−(4−x) =3
as DH=DG DG=3
So Length of CD=CG+GD
=3+3=6
Posted by Mathanbalaji Anavarathan 4 years, 9 months ago
- 4 answers
Yogita Ingle 4 years, 9 months ago
A probability event can be defined as a set of outcomes of an experiment. In other words, an event in probability is the subset of the respective sample space.
Archana Nair 4 years, 9 months ago
Posted by Cg〲Heena Gaming 4 years, 9 months ago
- 1 answers
Posted by Hcyvh Vguv 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
A n s w e r
The prime factors are: 5 x 7 x 11 x 13
or also written as { 5, 7, 11, 13 }
Written in exponential form: 51 x 71 x 111 x 131
Posted by Lovy Yadav 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
There are a variety of subconcepts which are related to answering questions based on boat and streams. Given below are the four terms which are important for a candidate to know to understand the concept of streams.
- Stream – The moving water in a river is called stream.
- Upstream – If the boat is flowing in the opposite direction to the stream, it is called upstream. In this case, the net speed of the boat is called the upstream speed
- Downstream – If the boat is flowing along the direction of the stream, it is called downstream. In this case, the net speed of the boat is called downstream speed
- Still Water – Under this circumstance the water is considered to be stationary and the speed of the water is zero
Meghna Thapar 4 years, 9 months ago
The terms upstream and downstream oil and gas production refer to an oil or gas company's location in the supply chain. Upstream oil and gas production is conducted by companies who identify, extract, or produce raw materials. Downstream oil and gas production companies are closer to the end user or consumer.
When a boat travels in the same direction as the current, we say that it is traveling downstream. Thus if b is the speed of the boat in still water, and c is the speed of the current, then its total speed is. Downstream speed = b + c. When a boat travels against the current, it travels upstream.
Posted by Sridhar R 4 years, 9 months ago
- 4 answers
Gopika Satheesh 4 years, 9 months ago
Posted by Gopika Satheesh 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
Proof:
The diagram for this sum is attached below
Let AB be the tower and BC be the flagstaff. Let OA = x metre, AB = ‘y’ metre and BC = ‘h’ metre.
In right ∆OAB,
On cross-multiplication we get,
→ (1)
In right ∆OAC
→ (2)
Equating equation 1 and 2 we get,
Thus the height of the tower is h tan alpha/tan beta - tan alpha is proved
Posted by Durgesh Kumar 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
x2 +3x - (m+2)(m+5) = 0
⇒ x2 + (m+5)x - (m+2)x - (m+2)(m+5) = 0
⇒ x (x + m+5) - (m+2)(x+m+5) = 0
⇒ (x+m+5)(x-m-2) = 0
⇒ x = - m-5. and m+2
Roots are (-m-5) and (m+2)
Posted by Khushi Sanini45 4 years, 9 months ago
- 1 answers
Posted by Samyak Jain 4 years, 9 months ago
- 1 answers
Posted by Mohammed Abubakar 4 years, 9 months ago
- 2 answers
Posted by Mahak Sinha 4 years, 9 months ago
- 2 answers
Dhirendra Pratap Singh 4 years, 9 months ago
Posted by Himanshu Kabra 4 years, 9 months ago
- 3 answers
King?Adithya H. M.. 4 years, 9 months ago
Gaurav Seth 4 years, 9 months ago
The quadratic polynomial of the .
To find:
“Quadratic polynomial” whose zeros are
Solution:
A quadratic polynomial is a polynomial of degree 2. A univariate quadratic polynomial has the form . An equation involving a ‘quadratic polynomial’ is called a quadratic equation.
Posted by Akshay Guttula 4 years, 9 months ago
- 2 answers
Yogita Ingle 4 years, 8 months ago
Using the Pythagoras answer the following questions:
1) What is the length of the broken part?
A) 15 m
B) 20 m
C) 25 m
D) 30 m
2) What was the height of the full tree?
A) 40 m
B) 50 m
C) 35 m
D) 30 m
3) In the formed right-angle triangle what is the length of the hypotenuse?
A) 15 m
B) 20 m
C) 25 m
D) 30m
4) What is the area of the formed right angle triangle?
A) 100 m2
B) 200 m2
C) 60 m2
D) 150 m2
5 )What is the perimeter of the formed triangle?
A) 60 m
B) 50 m
C) 45 m
D) 100 m
Answer
1)C
2)A
3)C
4)D
5)A
Posted by Yogender Mavi 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Solution:
(i) Taking A as origin, coordinates of the vertices P, Q and R are,
From figure: P = (4, 6), Q = (3, 2), R (6, 5)
Here AD is the x-axis and AB is the y-axis.
(ii) Taking C as origin,
Coordinates of vertices P, Q and R are ( 12, 2) , (13, 6) and (10, 3) respectively.
Here CB is the x-axis and CD is the y-axis.
Find the area of triangles:
Area of triangle PQR in case of origin A:
Using formula: Area of a triangle =
= ½ [4(2 – 5) + 3 (5 – 6) + 6 (6 – 2)]
= ½ ( – 12 – 3 + 24 )
= 9/2 sq unit
(ii) Area of triangle PQR in case of origin C:
Area of a triangle =
= ½ [ 12(6 – 3) + 13 ( 3 – 2) + 10( 2 – 6)]
= ½ ( 36 + 13 – 40)
= 9/2 sq unit
This implies, Area of triangle PQR at origin A = Area of triangle PQR at origin C
Area is same in both case because triangle remains the same no matter which point is considered as origin.
Posted by Jiya Munjal 4 years, 9 months ago
- 2 answers
Posted by Harsha Shreya 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Given:
=
We have to find, the value of is:
Solution:
∴
Using the algebraic identity:
(a + b)(a - b) =
Using the trigonometric identity:
+
= 1
⇒ = 1 -
and
= 1 -
Using the trigonometric identity:
=
=
Put =
, we get
=
=
∴ =
Thus, the value of is "equal to
".
Posted by Swagata Lakshmi Mallik 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
IN THE GIVEN QUESTION, SIDES OF RECTANGLE AB=10 cm
AND AD=5 cm.
THE LARGEST SEMI CIRCLE INSCRIBED IN THIS RECTANGLE WILL BE WITH DIAMETER 10 cm
THEREFORE , ITS RADIUS WILL BE 5 cm.
ITS AREA WILL BE =π
⇒
⇒22*25/7
⇒AREA OF SEMICIRCLE=550/7 consider this as equation (1)
NOW,ΔAPB IS AN ISOSCELES TRIANGLE WITH SIDES AP=AB,
THEREFORE LET AP=AB= X(say)
THEN IN TRIANGLE APB ,
WE GET ∠PAB=∠PBA (ANGLES OPPOSITE TO EQUAL SIDES)=45°(ANGLE SUM PROPERTY IF A TRIANGLE)
BY SIN 45° IN TRIANGLE WE GET,
PB/AB=
⇒
⇒X=10 cm.
therefore AREA OF ΔAPB=1/2*b*h
⇒1/2*x*x
⇒1/2*10*10
⇒AREA OF ΔAPB=50 ...consider this as equation (2)
NOW, AREA OF SHADED REGION = AREA OF SEMICIRCLE-AREA OF TRIANGLE
⇒AREA OF SHADED REGION =550/7-50
⇒550/7-350/7
⇒200/7
⇒28.571528
THEREFORE THE AREA OF SHADED REGION IS 28.571528
Posted by Vivekpreet Singh 4 years, 9 months ago
- 2 answers
ಹರ್ಷನಂದ ಹರ್ಷನಂದ 4 years, 9 months ago
Posted by Uma Yadav 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Area = 6.16 m^2
x r^2 = 6.16
r^2 = 616 / 100 x 7 / 22
r^2 = 196 / 100
r = 14 / 10
r = 1.4 m
Circumference = 2 x x r
= 2 x 22/7 x 1.4
= 8.8 m
Distance = 572 m
Number of revolutions = Distance / Circumference
made by the wheel = 572 / 8.8
= 65
Therefore, the wheel makes 65 revolutions to cover 572 meter.
Posted by अमन तिवारी 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
Therefore we can write the formula as follows:
By squaring on both sides we get:
Therefore, the value of p is +4 or -4
Posted by Namika Mishra 4 years, 5 months ago
- 0 answers
Posted by Palak Saini 4 years, 9 months ago
- 4 answers
Posted by Gupta Binita 4 years, 9 months ago
- 3 answers
Yogita Ingle 4 years, 9 months ago
We know that the general form of quadratic equation is ax2+bx+c=0.
The given equation is (x+2)3=2x(x2−1) can be simplified as follows:
(x+2)3 = 2x(x2−1)
⇒x3+23+(3×x×2)( x+2)=2x3−2x (∵(a+b)3=a3+b3+3ab(a+b))
⇒x3+8+6x(x+2)=2x3−2x
⇒x3+8+6x2+12x=2x3−2x
⇒x3+8+6x2+12x−2x3+2x=0
⇒−x3+6x2+14x+8=0
Since the variable x in the equation −x3+6x2+14x+8=0 has degree 3, therefore, it is not of the form ax2+bx+c=0.
Hence, the equation (x+2)3=2x(x2−1) is not a quadratic equation.
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Gaurav Seth 4 years, 9 months ago
1. Sides of triangles are given below. Determine which of them are right triangles? In case of a right triangle, write the length of its hypotenuse.
(i) 7 cm, 24 cm, 25 cm
(ii) 3 cm, 8 cm, 6 cm
(iii) 50 cm, 80 cm, 100 cm
(iv) 13 cm, 12 cm, 5 cm
Solution:
(i) Given, sides of the triangle are 7 cm, 24 cm, and 25 cm.
Squaring the lengths of the sides of the, we will get 49, 576, and 625.
49 + 576 = 625
(7)2 + (24)2 = (25)2
Therefore, the above equation satisfies, Pythagoras theorem. Hence, it is right angled triangle.
Length of Hypotenuse = 25 cm
(ii) Given, sides of the triangle are 3 cm, 8 cm, and 6 cm.
Squaring the lengths of these sides, we will get 9, 64, and 36.
Clearly, 9 + 36 ≠ 64
Or, 32 + 62 ≠ 82
Therefore, the sum of the squares of the lengths of two sides is not equal to the square of the length of the hypotenuse.
Hence, the given triangle does not satisfies Pythagoras theorem.
(iii) Given, sides of triangle’s are 50 cm, 80 cm, and 100 cm.
Squaring the lengths of these sides, we will get 2500, 6400, and 10000.
However, 2500 + 6400 ≠ 10000
Or, 502 + 802 ≠ 1002
As you can see, the sum of the squares of the lengths of two sides is not equal to the square of the length of the third side.
Therefore, the given triangle does not satisfies Pythagoras theorem.
Hence, it is not a right triangle.
(iv) Given, sides are 13 cm, 12 cm, and 5 cm.
Squaring the lengths of these sides, we will get 169, 144, and 25.
Thus, 144 +25 = 169
Or, 122 + 52 = 132
The sides of the given triangle are satisfying Pythagoras theorem.
Therefore, it is a right triangle.
Hence, length of the hypotenuse of this triangle is 13 cm.
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