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Ask QuestionPosted by Aditya Noob 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
Let the cost price of one chair be Rs. x and that of one table be Rs. y. Profit on chair = 25%.
∴ Selling price of one chair
Profit on a table = 10%
∴ Selling price of one table =
According to the given condition, we have
If profit on a chair is 10% and on a table is 25%, then total selling price is Rs. 1535.
Subtracting equation (ii) from equation (i), we get
3x - 3y = -300 ⇒ x - y = -100
Adding equation (ii) and (i), we get
47x + 47y = 61100 ⇒ x + y = 1300
Thus, we have following equations
x - y = -100 ...(iii)
x + y = 1300 ...(iv)
From (iii), we have
x - y = - i 00
⇒ x = y - 100 ...(v)
Substituting the value of x in (iv), we get
x + y = 1300
⇒ y - 100 + y - 1300
2y - 100 = 1300
⇒ 2y - 1400 ⇒ y = 700
Substituting the value of y in (v), we get
x = y - 100
⇒ x = 700 - 100 = 600
Hence, cost price of one chair = Rs. 600 and cost price of one table = Rs. 700
Posted by Gunja Gupta 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
It is given that ΔABC ∼ ΔFEG.
∴ ∠A = ∠F, ∠B = ∠E, and ∠ACB = ∠FGE
∠ACB = ∠FGE
∴ ∠ACD = ∠FGH (Angle bisector)
And, ∠DCB = ∠HGE (Angle bisector)
In ΔACD and ΔFGH,
∠A = ∠F (Proved above)
∠ACD = ∠FGH (Proved above)
∴ ΔACD ∼ ΔFGH (By AA similarity criterion)
=>(CD)/(GH) = (AC)/(FG)
Posted by Anurag Kumar 4 years, 8 months ago
- 2 answers
Mayank Rauthan 4 years, 9 months ago
Gaurav Seth 4 years, 9 months ago
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Aditya Noob 4 years, 9 months ago
3Thank You