Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Rajat Arora 4 years, 8 months ago
- 2 answers
Gaurav Seth 4 years, 8 months ago
In ΔABC, Let ∠ABC be θ
Sin θ = (a2 - b2) / (a2 + b2)
⇒ AB = (a2 - b2)
⇒ AC = (a2 + b2)
⇒ BC = √[(a2 + b2)2 - (a2 - b2)2] [According to Pythagoras theorem]
⇒ BC = √(4a2b2)
⇒ BC = 2ab
Cos θ = 2ab / (a2 + b2)
Tan θ = (a2 - b2) / 2ab.
Cosec θ, Sec θ and Cot θ are the reciprocals of Sin θ, Cos θ, Tan θ respectively.
Posted by Mohamed Ashiq 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
The great Nature has intended us to earn our bread in the sweat of our brow. Every one, therefore, who idles away a single minute becomes to that extent a burden upon his neighbours, and to do so is to commit a breach of the very first lesson of ahimsa. Ahimsa is nothing if not a well-balance, exquisite consideration for one's neighbour, and an idle man is wanting in that elementary consideration. (YI, 11-4-1929, p. 144-15)
Posted by Uttam Meena Jaipur 4 years, 8 months ago
- 1 answers
Posted by Manan Pareek 4 years, 8 months ago
- 1 answers
Gaurav Seth 4 years, 8 months ago
AB is a tower. D and Care two points on the same side of a tower, BD = a and BC = b.
∠ADB and ∠ACB are the complementary angles.
If ∠ADB = x, then ∠ACB = 90 – x
In ∆ADB,
………… (1)
In ∆ABC,
…………....(2)
Multiplying (1) and (2),
(AB)2 = ab
AB = √ab
Height of tower = AB = √ab
Hence proved.
Posted by Tripti Priya 4 years, 8 months ago
- 2 answers
Pragati Pagare 4 years, 8 months ago
Posted by Ritesh Singh 4 years, 8 months ago
- 5 answers
Posted by Bala Manohar 1 year, 1 month ago
- 0 answers
Posted by Dhairya Pratap Singh 4 years, 8 months ago
- 2 answers
Posted by Aman Raj 4 years, 8 months ago
- 0 answers
Posted by Ninyanjali Patel 4 years, 8 months ago
- 1 answers
Varun Agarwal 4 years, 8 months ago
Posted by Aashna Singh 4 years, 8 months ago
- 1 answers
Gautam Sinha 4 years, 8 months ago
Posted by Roshan Dhamala 4 years, 8 months ago
- 3 answers
Archi Jain 4 years, 8 months ago
Aashna Singh 4 years, 8 months ago
Posted by Khirabdhi Sahu 4 years, 8 months ago
- 2 answers
Gaurav Seth 4 years, 8 months ago
1)C
2)A
3)C
4)D
5)A
Answer:
Use the pythagoras theorem.
Step-by-step explanation:
Check the figure.
The length of the standing part of the tree = 15 m
Length of the base = 20 m
To find: Hypotenuse or the longest side.
Using Pythagoras theorem,
Where, ab = 15 m
bc = 20
225 + 400 =
625 =
= ac
∴ ac = 25
Posted by @/<$#!T Just Own 4 years, 8 months ago
- 0 answers
Posted by Hogwarts ... 4 years, 8 months ago
- 0 answers
Posted by Akshay Nayak 4 years, 9 months ago
- 2 answers
Jatin Sharma 4 years, 9 months ago
Gaurav Seth 4 years, 9 months ago
Let the first number be x and the second number is 27 - x.
Therefore, their product = x (27 - x)
It is given that the product of these numbers is 182.
Therefore, x(27 - x) = 182
⇒ x2 – 27x + 182 = 0
⇒ x2 – 13x - 14x + 182 = 0
⇒ x(x - 13) -14(x - 13) = 0
⇒ (x - 13)(x -14) = 0
Either x = -13 = 0 or x - 14 = 0
⇒ x = 13 or x = 14
If first number = 13, then
Other number = 27 - 13 = 14
If first number = 14, then
Other number = 27 - 14 = 13
Therefore, the numbers are 13 and 14.
Posted by Prajwal More 4 years, 9 months ago
- 2 answers
Yogita Ingle 4 years, 9 months ago
7x² - 12x + 18
Find the sum of the roots:
Sum of the roots = α + β
α + β = - b/a
α + β = - (-12 ) / 7 = 12/7
Find the product of the roots:
Product of the roots = αβ
αβ = c/a
αβ = 18/7
Find the ratio:
α + β : αβ = 12/7 : 18/7
Multiply by 7:
α + β : αβ = 12 : 18
Divide by 6:
α + β : αβ = 2 : 3
Posted by Taylor N 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
2x2 -7 x+3=0
2x2 -6x - 1x +3=0
2x ( x - 3) - 1( x- 3) = 0
(x - 3)(2x - 1) = 0
x - 3 = 0 or 2x - 1 = 0
x = 3 or x = 1/2
Posted by Bhoomika R 4 years, 9 months ago
- 2 answers
Neha Kumari 4 years, 9 months ago
Aanya Jain 4 years, 9 months ago
Posted by Tanmay Meshram 4 years, 9 months ago
- 2 answers
Aanya Jain 4 years, 9 months ago
Posted by Manav Kumar 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
Given :
Let ‘d’ be the diameter of a circle and ‘a’ be the side of a triangle.
Diameter of a circle = side of equilateral triangle
d = a
Radius of a circle, r = d/2
Area of circle,A1 = πr²
Area of an equilateral ∆, A2 = √3/4 a²
Ratio of the Area of circle and Area of an equilateral ∆ :
A1 : A2 = πr² : √3/4× a²
A1 / A2 = πr² / √3/4 ×a²
A1 / A2 = π(d/2)² / √3/4× a²
A1 / A2 = π(a/2)² / √3/4 × a²
[d = a]
A1 / A2 = π(a²/4) / √3/4 × a²
A1 / A2 = πa²/4 × 4 /√3a²
A1 / A2 = π/√3
A1 : A2 = π : √3
Hence, the Ratio of the Areas of circle and equilateral ∆ is π : √3
Posted by Drashti Ambiya 4 years, 9 months ago
- 2 answers
Mayank Rauthan 4 years, 9 months ago
Yogita Ingle 4 years, 9 months ago
Basic Proportionality Theorem states that, if a line is parallel to a side of a triangle which intersects the other sides into two distinct points,then the line divides those sides of the triangle in proportion.
Let ABC be the triangle.
The line l parallel to BC intersect AB at D and AC at E.
To prove AD/DB =AE/EC
Join BE,CD
Draw EF⊥AB, DG⊥CA
Since EF⊥AB,
EF is the height of triangles ADE and DBE
Area of △ADE=1/2 × base × height=1/2AD×EF
Area of △DBE= 1/2 ×DB×EF
areaofΔDBEareaofΔADE=1/2×AD×EF/ 1/2×DB×EF=AD/DB ........(1)
Similarly,
areaofΔDCEareaofΔADE= 1/2 ×AE×DG/ 1/2 ×EC×DG =AE/EC ......(2)
But ΔDBE and ΔDCE are the same base DE and between the same parallel straight line BC and DE.
Area of ΔDBE= area of ΔDCE ....(3)
From (1), (2) and (3), we have
AD/DB =AE/EC
Hence proved.
Posted by Krithika Umesh 4 years, 8 months ago
- 5 answers
Yogita Ingle 4 years, 1 month ago
Suresh is having a garden near Delhi. In the garden, there are different types of trees and flower plants. One day due to heavy rain and storm one of the trees got broken as shown in the figure.The height of the unbroken part is 15 m and the broken part of the tree has fallen at 20 m away from the base of the tree.
Using the Pythagoras answer the following questions:
1) What is the length of the broken part?
A) 15 m
B) 20 m
C) 25 m
D) 30 m
2) What was the height of the full tree?
A) 40 m
B) 50 m
C) 35 m
D) 30 m
3) In the formed right-angle triangle what is the length of the hypotenuse?
A) 15 m
B) 20 m
C) 25 m
D) 30m
4) What is the area of the formed right angle triangle?
A) 100 m2
B) 200 m2
C) 60 m2
D) 150 m2
5 )What is the perimeter of the formed triangle?
A) 60 m
B) 50 m
C) 45 m
D) 100 m
Answer:
1)C
2)A
3)C
4)D
5)A
Posted by Shatrudhan Ray 4 years, 9 months ago
- 0 answers
Posted by Anuj Ahire 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Let the Tower be AC = 100m
Distance between cars is BD
BD=BC+CD
Let the BC be 'x' and CD be 'y'
In Traingle ACD
Cot45°= Base/Perpendicular
Cot45°=y/100
1=y/100
y=100m
In Traingle ACB
Cot30°=x/100
1.732=x/100
1.732×100=x
x=173.2m
Distance between cars = BC+CD
=x+y
=173.2+100
=273.2m
Or
Posted by Priya Kumari 4 years, 9 months ago
- 3 answers
Ashutosh Ranjan 4 years, 9 months ago
Gaurav Seth 4 years, 9 months ago
Putting x = (-1/2) in 3x2 + 2kx - 3 = 0,
or
Given : If is a solution of the quadratic equation
.
To find : The value of k ?
Solution :
To get the value of k substitute the value of x in the equation,
Equation
Put ,
Therefore, The value of k is or
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Rajat Arora 4 years, 8 months ago
0Thank You