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  • 1 answers

Sia ? 4 years, 4 months ago

In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.
  • 1 answers

Gaurav Seth 4 years, 8 months ago

The value of B is 0°

Step-by-step explanation:

given sin 2B = 2 sin B

we have to find the value of B

then

hence , The value of B is 0°

  • 1 answers

Yogita Ingle 4 years, 8 months ago

V=375 cm³,l=20 cm,b=7.5 cm h=?

V = lbh

20 (7.5) h = 375

150 h = 375

h = 375/150 = 2.5 cm

 

  • 1 answers

Sonukishore Kamat 4 years, 8 months ago

10th class CBSE standard wala ka case study based question jo hai bahut hi difficult hai mere liye Kaise solve hota hai batao
  • 1 answers

Abhijeet Anand 4 years, 8 months ago

0+0 = 1
  • 1 answers

Aryan Tiwari 4 years, 8 months ago

Sab exercise aayega
  • 2 answers

Aryan Tiwari 4 years, 8 months ago

When we factorize 4x2-4x+x-1 4x(x-1)+(x-1) to give two zeroes because it is quadratic polynomial

Iron Man 4 years, 8 months ago

As when we factorise it 4x2-4x+x-1 4x(x-1)+1(x-1) x=1,-1/4.
Ba
  • 0 answers
  • 3 answers

Sujata Gurung 4 years, 8 months ago

Thank you ?

Yogita Ingle 4 years, 8 months ago

2√3x2 ˗ 5x + √3 
 ⇒ 2√3x2 ˗ 2x ˗ 3x+ √3   
⇒ 2x (√3x ˗ 1) ˗ √3 (√3x ˗ 1) = 0 
 ⇒ (√3x ˗ 1) or (2x − √3) = 0   
⇒ (√3x ˗ 1) = 0 or (2x − √3) = 0   
⇒ x = 1/ √3 or x = √3/ 2   
⇒ x = 1/ √3 × √3 /√3 = √3/ 3 or x = √3/ 2 

Sujata Gurung 4 years, 8 months ago

2√3x2+5x+√3
  • 3 answers

Sonukishore Kamat 4 years, 8 months ago

Time table me Kya h agar man se kabhi 5 ghanta pdhai Kar Liya to topper bhi rone lagega

Vivek Kumar 4 years, 8 months ago

Same bro

Moksha Maheta 4 years, 8 months ago

Do one thing just clear your notes and on sunfay revise it at all that's it and you can follow it
  • 3 answers

Hemant Kaswan 4 years, 8 months ago

Chal

Parinita Mahawar 4 years, 8 months ago

Cosec = Hypotenuse /Perpendicular It's just the opposite of sin

Sanjeev Kumar 4 years, 8 months ago

Photo bhejna hai
  • 2 answers

Aryan Tiwari 4 years, 8 months ago

Y=3

Yogita Ingle 4 years, 8 months ago

.If x= 2

 x+ y = 5 

2 + y = 5

y = 5 - 2

y = 3

9+2
  • 5 answers

Mohit Kataria 4 years, 8 months ago

11

Shiv Devi Jaiswal 4 years, 8 months ago

11

Krazy Girl 4 years, 8 months ago

11

Nikhil Khatri 4 years, 8 months ago

11

Aditya Sachdeva 4 years, 8 months ago

11
  • 1 answers

Gaurav Seth 4 years, 8 months ago

p(x) = x²-5x-6
-b/a = 5
c/a = -6

p(6) = 0

Let the other zero be "a"

sum of zeros = 6 + a = -b/a 

6 + a = 5

a = 5 - 6
   = -1

The other zero is -1

  • 0 answers
  • 1 answers

Shubham Mishra 4 years, 8 months ago

2
  • 2 answers

Yogita Ingle 4 years, 8 months ago

AB= √(9-9)²+(6-0)² = 6
BC= √(-9-9)²+(6-6)² = 18
CD = √(-9+9)²+(0-6)² = 6
DA = √(-9-9)²+(0-0)² = 18
so,it's opposite sides are equal,hence it is rectangle.

Neha Parveen 4 years, 8 months ago

Tell me
  • 1 answers

Yogita Ingle 4 years, 8 months ago

Let the point be A(5,−6), B(−1,−4) and P(0,y)

Point P is on y−axis,hence its x co-ordinate is 0.So, it is of the form P(0,y)

Now, we have to find ratio.

Let the ratio be k:1

Hence m1​=k,m2​=1,x1​=5,y1​=−6,x2​=−1,y2​=−4,x=0,y=0

Using sections formula x= (m1​x2​+m2​x1​​)/m1​+m2​

⇒0=−k+5​/k+1

∴k=5

Again y=(m1​y2​+m2​y1​​)/m1​+m2​

=−4k−6​/ k+1 = (−20−6​)/ 6 for k=5

=−13​/3

Hence the coordiantes of point is P(0,−13​/3)

  • 1 answers

Golver Stoot 4 years, 8 months ago

At present x=6 and y=3 now if x=70 then find y Solution:- let the X and x x=6 and after exceeding X=70 so, exceeding no.= X-x (70-6)= 64 Since, x exceed by 64 So, Y= y+64=(3+64)= 67
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  • 3 answers

Mohd. Wasi .Gour. Gada . 4 years, 8 months ago

Explain the figure

Sonukishore Kamat 4 years, 8 months ago

Explain By figure

Yogita Ingle 4 years, 8 months ago

The polynomial with degree greater than 2 can also intersect the x - axis at two points. Hence, it need not be a quadratic polynomial. 

  • 1 answers

Yogita Ingle 4 years, 8 months ago

Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15 
A + B = 90 or A = 90 - B 

CosA = Cos(90-B) 
7/15 = SinB 
CosecB = 1/SinB = 1/ 7/15 = 15/7 

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