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Gaurav Seth 4 years, 8 months ago

We have given a₃ = 16

a + (3 − 1) d = 16

a + 2d = 16 (1)

a₇ − a₅ = 12

[a+ (7 − 1) d] − [a + (5 − 1) d]= 12

(a + 6d) − (a + 4d) = 12

2d = 12

d = 6

From equation (1), we obtain

a + 2 (6) = 16

a + 12 = 16

a = 4

Therefore, A.P. will be

4, 10, 16, 22, …

ANSWER

નીચે આપેલા પ્રશ્નો ના માગ્યા મુજબ ઉતાર લાખો

Posted by ... .. 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Harsh Rathor 4 years, 8 months ago

Which language is this?

Yash Sahu 4 years, 8 months ago

????

ANSWER

Express each number in a product of its prime factor

Posted by Suhaib Dar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 4 years, 8 months ago

Question 1. Express each number as a product of its prime factors:
(i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Answer:

(i) 140             = 2 x 2 x 5 x 7            =2² x 5 x 7
(ii)156             =2 x 2 x 3 x 13           =2² x 3 x 13
(iii)3825          =3 x 3 x 5 x 5 x 17    =3² x 5² x 17
(iv)5005          =5 x 7 x 11 x 13        =5 x 7 x 11 x 13
(v)7429           =17 x 19 x 23           =17 x 19 x 23

Suhaib Dar 4 years, 8 months ago

Express each number in a product of its prime factors

ANSWER

Find the value of tan15o .tan25o .tan30o tan65o .tan85o

Posted by Hemansh.P. Jain 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Sukul Kumar 4 years, 8 months ago

Sachin Kumar Tendulkar 4 years, 8 months ago

ANSWER

What is full Form of BODMAS Formula

Posted by Rounak Mishra 4 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Ayush Agrawal 4 years, 8 months ago

Bracket Order of Division Multiplication Addition Subtraction

Nandini Patil 4 years, 8 months ago

B- bracket,O- order of ,D-division ,M-multiplication,A-addition,S-substration

4Thank You

Gaurav Seth 4 years, 8 months ago

a n s w e r
As per BODMAS rule, we have to calculate the expressions given in the brackets first. The full form of BODMAS is Brackets, Orders, Division, Multiplication, Addition and Subtraction

Yogita Ingle 4 years, 8 months ago

BODMAS is an acronym and it stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction.

Asvitha Karthikeyan 4 years, 8 months ago

Bracket Of Division Multiplication Addition and Subtraction

ANSWER

As observed from the top of a 75 m. high light house form the sea level, the angle of depression of two ships are 30o and 45o . If one ship is exactly behind the other on the same side of light house, find the distance between the ships

Posted by Divyansh Gupta 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 4 years, 8 months ago

Let AB be the lighthouse of height 75 m and P, Q be the position of the two ships whose angles of depression are 45º and 30º, respectively

Gaurav Seth 4 years, 8 months ago

Q: As observed from the top of a 75m high lighthouse from the sea-level, the angles of depression of two ships are 30º and 45º.If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.

Answer

Let AB be the lighthouse of height 75 m and P, Q be the position of the two ships whose angles of depression are 45º and 30º, respectively (Fig 11.28).

ANSWER

If lateral surface area of cylinder is94.2cm2 and height is 5cm then find radius of its base

Posted by Pradip Tupke 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Mohd. Wasi .Gour. Gada . 4 years, 8 months ago

Mankrishan Chadda ?? 4 years, 8 months ago

Given, h=5cm ⇒Let radius =r (i) Curved Surface Area ⇒94.2cm2=2πrh ⇒94.2 cm2=2×3.14×r×5cm ⇒r=3cm (ii) Volume of cylinder ⇒πr2h=3.14×3×3×5 =141.2cm3 ?

ANSWER

List out all theorems from triangle ? chapter and prove it

Posted by Shiva Gowri 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

For what value(s) of ‘a’ quadratic equation 30ax^2-6x+1=0 has no real roots?

Posted by The_ Pj 4 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Simranpreet Kaur 4 years, 8 months ago

The equation has no real root i. e. B2-4AC <0 here b=-6, a=3a and c=1 (-6*-6) -4(3a)(1) <0 36-12a<0 36<12a 36/12<a 3<a

Kumar Kumar 4 years, 8 months ago

Here,coefficients of standard form of equation Ax²+Bx+C=0 are A=30a B=-6 C=1 So,Discriminant,D=B²-4AC Since,equation has no real roots i.e. D<0 i.e. B²-4AC<0 i.e. (-6)² -4 (30a)(1)<0 i.e. 36-120a <0 On transposing (-120a) i.e. 36 <0-(-120a) i.e. 36 <120a i.e. 6×6 <6×(20a) On cancelling out 6 from both sides i.e. 6<20a On dividing both sides by 20 i.e. 6/20 < a i.e. 3/10 < a i.e. a >3/10 Hence, a>3/10 for which 30ax² +6x+1=0 gas no real roots

Kumar Kumar 4 years, 8 months ago

B= ±6 as B²=36

Kumar Kumar 4 years, 8 months ago

Here,coefficients of standard form of equation Ax²+Bx+C=0 are A=30a B=6 C=1 So,Discriminant,D=B²-4AC Since,equation has no real roots i.e. D<0 i.e. B²-4AC<0 i.e. (6)² -4 (30a)(1)<0 i.e. 36-120a <0 On transposing (-120a) i.e. 36 <0-(-120a) i.e. 36 <120a i.e. 6×6 <6×(20a) On cancelling out 6 from both sides i.e. 6<20a On dividing both sides by 20 i.e. 6/20 < a i.e. 3/10 < a i.e. a >3/10 Hence, a>3/10 for which 30ax² +6x+1=0 gas no real roots

ANSWER

Kis ko math ki revision ha dang sa ??????

Posted by Diya Rajput 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Kartik Bhardwaj 4 years, 8 months ago

Dkh leyo

Aysuman Sahoo 4 years, 8 months ago

Mujhe?

Gunjan Bhardwaj 4 years, 8 months ago

Mujhe ?

17. A floor designed is made by 2-dimensional geometrical figures as shown on coordinate axes. (a' 2) A Ala 2y) (2x 0)B Pſal. b) 0 (a b)P B(2x 0) Coordinates of points are also represented. Here A'P'B' is mirror image of APB along y axis. Answer the following questions based on above diagram. (a) Determin coordinates of mid point of PP`. aь a' b (iii) (0 0) (b) The distance of point P from y-axis is. (ii) b' (c) Distance PP' is Vla-a')? +(b-b)? (in) * () (iii) b (ii) Va?+62 (iv) 0 (a-a + - (iv) Va?+u? + 2y² + 2y2 (d) The distance AA' is (1) Va? - a2 + (2y) (iii) V(2y - 2y') 2 + 42 (e) The distance between the points BB' is. (0) V272 + 2x2 (ii) V(22-0)2 + (2x' +y)? (ü) V4r+ 4x + 8xx`

ANSWER

5 pencil and 7 pens togther cost rupee 50 whreas 7 pencil and5 pens together cost rupee 46 find the cost of one pencil and that of one pen ???

Posted by Diya Rajput 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 4 years, 8 months ago

Let pencil be x and let pen be y
5x+7y=50
7x+5y=46
multiply first equation by 7
35x+49y = 350
multiply second equation by 5
35x+25y=230
solving them we get 24y=120 which gives y is 5 rupees
substituting in second equation we get x is 3 rupees

3Thank You

ANSWER

Posted by Ankush Gulami 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Krishanu Saikia 4 years, 8 months ago

IDK

ANSWER

The midpoint of the line joining the points (−10, 8)(−10, 8) and (−6,12)(−6,12) divides the line joining the points (4,−2)(4,−2) and (−2,4)(−2,4) in the ratio

Posted by Abhishek Choudhary 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Priyansh Jindal 4 years, 8 months ago

Yogita kasa aya ? explain

Yogita Ingle 4 years, 8 months ago

2:1 externally

ANSWER

Maths project on class 10 working model

Posted by Archana Bhadana 4 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Archana Bhadana 4 years, 8 months ago

Can you please tell me where I found the project .

Shiva Gowri 4 years, 8 months ago

We too have the same which states topic

Archana Bhadana 4 years, 8 months ago

Yes

Shiva Gowri 4 years, 8 months ago

Cbse project for class tenth mathematics is it

ANSWER

Q5. In ∆ABC and ∆DEF, AB/DE = BC/EF, then they will be similar when *

Posted by Smith David 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Sonu Shaw 4 years, 8 months ago

Angle ABC= Angle DEF OR AB/DE=BC/EF=AC/DF

Archana Bhadana 4 years, 8 months ago

Two triangles are similar when there corresponding angles are equal and their corresponding sides are proportional.So, angle B=angleD

ANSWER

Case study based question

Posted by Pankaj Vishwakarma 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Archana Bhadana 4 years, 8 months ago

You can find in sample paper of (basic or standard) in this app only.

ANSWER

If the polynomial f(x) = ax^3 + bx - c is divisible by the polynomial g(x) = x^2 + bx + c, then c = ?

Posted by Aachal Satwan 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 4 years, 8 months ago

If the polynomial f(x) = ax³ + bx – c is divisible by the polynomial g(x) = x² + bx + c, then find the value of ab.

a n s w e r

Since, f(x) is divisible by g(x)

ANSWER

Case study vale questions kaha se milege?

Posted by Gurmeet Kaur 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which term of the ap 3,15,27,39,........will be 120 more than its 21st term ?

Posted by Manvi . 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 4 years, 8 months ago

Given sequence is 3,15,27,39,...

The first term is a=3

The common difference is d=15−3=12

we know that the nth term of the arithmetic progression is given by a+(n−1)d

Let the mth term be 120 more than the 21st term

Therefore, 120+mthterm=21stterm

⟹120+a+(m−1)d=a+(21−1)d

⟹120+(m−1)12=(20)12

⟹12m−12=240+120

⟹12m=360+12

⟹12m=372

⟹m= 372/12 =31

Aachal Satwan 4 years, 8 months ago

a = 3, d=12 a21 = a + (n-1)d = 3 + (21-1)12 = 243 243 + 120 = 363 an = 363 a + (n-1)d = 363 3 + (n-1)12 = 363 12n = 363 - 3 + 12 n = 372 / 12 ∴n = 31st term

ANSWER

Proof of AAA similarity criteria

Posted by Saba Yasmeen Kamdod 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 4 years, 8 months ago

AAA similarity theorem or criterion:
If the corresponding angles of two triangles are equal, then their corresponding sides are proportional and the triangles are similar

In ΔABC and ΔPQR, ∠A = ∠P , ∠B = ∠Q , and ∠C = ∠R then  AB PQ =  BC QR =  ACPRand ΔABC ∼ ΔPQR.

Given: In ΔABC and ΔPQR, ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R.

To prove:   AB PQ =  BC QR =  ACPR

Construction : Draw LM such that    PL AB = PM AC .

Proof: In ΔABC and ΔPLM,

AB = PL and AC = PM (By Contruction)

∠BAC = ∠LPM (Given)

∴ ΔABC ≅ ΔPLM (SAS congruence rule)

∠B = ∠L (Corresponding angles of congruent triangles)

Hence ∠B = ∠Q (Given)

∴ ∠L = ∠Q

LQ is a transversal to LM and QR.

Hence  ∠L = ∠Q (Proved)

∴ LM ∥ QR

  PL LQ =  PM MR

  LQ PL =  MR PM   (Taking reciprocals)

  LQ PL + 1 =  MR PM + 1 (Adding 1 to both sides)

  LQ+PL PL =  MR+PM PM

  PQ PL =  PR PM

  PQ AB =  PR AC   (AB = PL and AC =PM)

  AB PQ =  AC PR (Taking Reciprocals) ............... (1)

  AB PQ =  BC QR

  AB PQ =  AC PR =   BC QR

∴ ΔABC ~ ΔPQR

ANSWER

The LCM of two numbers is 1200.Which of the following cannot be their HCF? A)600 B)500 C)400 D)200

Posted by Sneha Desai 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 4 years, 8 months ago

Because the HCF of two numbers is also the factor of their multiples, therefore 200, 400 and 600 divide 1200 but 500 does not.

ANSWER

The angle of elevation of a ladder learning against a wall

Posted by Harsh Kumar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Rounak Mishra 4 years, 8 months ago

The angle of elevation of a ladder leaning against a wall is 60º and the foot of the ladder is 4.6 m away from the wall. Angle = 60º and distance between wall and ladder= 4.6 m. = 9.2 m. Angle is 60 degree, on angle will be 90 degree, so 3rd angle is 30 degree.