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  • 2 answers

Siya Singhal 5 years ago

LHS=cosA+sinA−1cosA−sinA+1​ dividing Nr and Dr by sinA we get, =sinAcosA​+sinAsinA​−sinA1​sinAcosA​−sinAsinA​+sinA1​​ =cotA+1−cosecAcotA−1+cosecA​ =cotA+1−cosecAcotA+cosecA−(cosec2A−cot2A)​ =cotA+1−cosecA(cotA+cosecA)(1−cosecA+cotA)​ =cotA+cosecA=RHS

Balaji B 5 years ago

Multiplying the numerator and denominator with sinA : SinA [CosA – SinA +1]/ SinA [CosA + SinA –1] SinACosA–Sin^2A+SinA/ SinA [CosA +SinA –1] SinACosA+SinA –[1–Cos^2A]/ SinA[CosA+SinA–1] SinACosA+SinA–[(1–CosA)(1+CosA)] / SinA[CosA+SinA–1] SinA[CosA+1]–[(1–CosA)(1+CosA)] / SinA [CosA + SinA–1] (CosA+1)(SinA–1+CosA)/ SinA (CosA + SinA–1) (CosA+1)(SinA+CosA—1)/ SinA (CosA+SinA–1) (CosA+SinA–1) will get cancelled So , CosA+1/SinA is left Dividing (CosA) and (1) individually by (SinA), we get CotA + CosecA Which is equal to R.H.S Hence Proved
  • 2 answers

Harmandeep Kaur 5 years ago

1.Probability of orange flavored candy =0 because there is only lemon flavoured candy. So it is impossible 2.probability of lemon flavoured candy =1

Divya Soni 5 years ago

1. 0 ( bag contains only lemon flavoured candy ) 2. Let total no. of candy is 10 No. of candies which are lemon 10 10/10 = 1
  • 2 answers
Where is question

Naru Karthik 5 years ago

Send me the questions
  • 5 answers
No

Prerna Jain 5 years ago

There's no need to refer 100s of books just make ur concepts clear

Ra Dhe 5 years ago

Yes but make your concept clear

Atul Kumar 5 years ago

Try rs aggrawal or rd Sharma book

Vansh Jhawar 5 years ago

No
  • 1 answers

A K47 5 years ago

cos∅/ (1-sin∅) multiply with 1+sin∅ in both numerator and denominator, cos∅×(1+sin∅)/(1-sin∅)×(1+sin∅) = cos∅(1+sin∅)/1²-sin²∅ [ 1=sin²∅+cos²∅ therefore 1-sin²∅ = cos²∅] cos∅(1+sin∅)/cos²∅ = 1+sin∅/cos∅
  • 4 answers

Vansh Jhawar 5 years ago

Probably is 1
Because total no. of favourable outcomes/total no. Of outcomes
5/6
The probability is
  • 5 answers
Answer is 2??
Now, we use Euclid's division algorithm/lemma
31-5 and 99-5, we get 26 and 94
First we leave remainder 5
8 and 5
  • 1 answers

A K47 5 years ago

(a+d)=7 and (a+3d)=23 by subtracting equations we get d=8. putting this value in a+d=7 we get a=-1. b=15 and c=31
  • 3 answers

Prerna Jain 5 years ago

??????

Malaika Sharma 5 years ago

??????

Ravi Kumar 5 years ago

Sir I can ask doubt
  • 4 answers
If you have taken basic then practice NCERT 100 % and any other side book you wish . But you have taken standard the you should practice NCERT full as well as side book to , like, examplar.

Anurag Singh 5 years ago

Ya ncert prefer

Sayantani Sen 5 years ago

Yes

Hemang Dubey 5 years ago

If you have taken basic then practice NCERT 100 % and any other side book you wish . But you have taken standard the you should practice NCERT full as well as side book to , like, examplar.
  • 2 answers

Kavya Chanana 5 years ago

76, 20

Annanya Gupta 5 years ago

so using formula for n th term a_n=a+(n-1)da n ​ =a+(n−1)d a = first term n = no. of terms d = common difference So given a + (3-1)d + a (7-1)d = 6 2a + 8d = 6 a + 4d = 3 a = 3 - 4d (a + 2d)(a + 6d) = 8 (3 - 2d)( 3 + 2d) = 8 {substituting a = 3 - 2d} 9 - 4d² = 8 d = +1/2 and - 1/2 so when d = +1/2 then a = 3 - 2 = 1 and when d = -1/2 a = 3 + 2 = 5 so using formula for S_n=\frac{n}{2}[2a+(n-1)d]S n ​ = 2 n ​ [2a+(n−1)d] when d = +1/2 S_n=\frac{16}{2}[2*1+(16-1)d]S n ​ = 2 16 ​ [2∗1+(16−1)d] S_n=76S n ​ =76 Similarly when d = -1/2 S_n=20S n ​ =20 Hope this helps you!.....
  • 5 answers

Simmi Fagna 5 years ago

The 21st term of the A.P:16

Vansh Jhawar 5 years ago

16

Anurag Singh 5 years ago

answer is tn=16

Annanya Gupta 5 years ago

The terms are not AP. Please recheck your question.....

Adithya Dev A 5 years ago

It is not an A.P. Please verify the question.
  • 1 answers

Nitin Kumar 5 years ago

Here we have to use quadratic formula. » D=(b)^2-4ac. » D=(1)^2-4(2)(-4). » D= 1+32. » D= 33. Now using quadratic formula: » x=(- b±√D)/2a. » x=(-1±√33)/4. » x=(-1+33)/4,(-1-33)/4. » x=32/4 & -34/4. » x=8 and -17/2. ??????????
  • 2 answers

Laxmanraj Hulli 5 years ago

Write the formula to find the volume of a frustum of a cone

Lizyba 28 5 years ago

X=lb Y=bh Z=lh XYZ=l^2 b^2 h^2 Volume of cuboid=lbh l^2 b^2 h^2= XYZ
  • 1 answers

Adithya Dev A 5 years ago

Equations would be 2/x + 7/y = 1/4 and 4/x + 4/y = 1/3 where time taken for work by one man is x and time taken by one boy is y.
  • 1 answers

Adithya Dev A 5 years ago

First check if AC and BD are of equal length. Then, check if AB and BC are equal. Then, we can prove it is a square.
  • 2 answers

Annanya Gupta 5 years ago

Your question seems to be incomplete. Please verify your question which u asked....

Nandani Jaiswal 5 years ago

Please provide the details of the question ??....
  • 4 answers

Bhoomika Verma 5 years ago

Do Practice...

Vaishali 10 5 years ago

Practice practice practice....

Oviya Arumugam 5 years ago

Daily practice help you to get mark.u should be through in ncert book. Refer some guide.daily atleast spend an hour to maths subject it's enough to get good mark.

Sona Benoy 5 years ago

1. Practise practise and practice 2. Ncert should be like God 3. Sample papers..anyone in perfect 3 he sittings
  • 3 answers

Anurag Singh 5 years ago

Correct answer is 60°

Adithya Dev A 5 years ago

We would get tan thitta is 1/√3. Then, the angle would be 30°.

Rupul Mohanty 5 years ago

60°

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