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  • 2 answers

Vidhi Srivastav 4 years, 5 months ago

No!!!! 0 can be written in p/q form and it is a positive no.

Abhishek Kumar 4 years, 5 months ago

32. Prove that: sinθ(1+tanθ) + cosθ(1+cotθ)= secθ+cosecθ
  • 5 answers

Dishi Shah 4 years, 5 months ago

4

Anurag Singh 4 years, 5 months ago

Simmi fagna your answer is wrong check your answer

Anurag Singh 4 years, 5 months ago

HCF OF( 96 AND 404) =4

Simmi Fagna 4 years, 5 months ago

404=2×2×101=2²×101¹

Simmi Fagna 4 years, 5 months ago

96=2×2×2×2×2×3=2²×3¹
  • 1 answers

Anurag Singh 4 years, 5 months ago

Alpha =2 and bita =3/2
  • 2 answers

Srishtika Murugan 4 years, 5 months ago

I have used the following identity: a²-b²=(a+b)(a-b) 1+cot²∆=cosec²∆

Srishtika Murugan 4 years, 5 months ago

Consider ∆ to be theta. Cosec²∆-cot²∆=1 (cosec∆+cot∆)(cosec∆-cot∆)=1 (Cosec∆+cot∆)1/3=1 cosec∆+cot∆=3
  • 1 answers

Anurag Singh 4 years, 5 months ago

Bro questions sahi sa likho kya CB. QR CA kya hai parallelogram hai ya aur kuch hai
  • 1 answers

Shubham Sharma 4 years, 5 months ago

9×1=9 9×2=18 9×3=27 9×4=36 9×5=45 9×6=54 9×7=63 9×8=72 9×9=81 9×10=90
  • 1 answers

Annu Singh 4 years, 5 months ago

45°
  • 1 answers

Saiyam Jain 4 years, 5 months ago

No point interested
  • 1 answers

Atul Mehra 4 years, 5 months ago

It is terminationg
  • 3 answers

Anurag Singh 4 years, 5 months ago

Write full question here.

Akshat Sharma 4 years, 5 months ago

What to find here?

Tanvi @1201 4 years, 6 months ago

What to find here???
  • 3 answers

Simmi Fagna 4 years, 5 months ago

798789×98778987=789035775925743

Akshat Sharma 4 years, 5 months ago

?

Tanvi @1201 4 years, 6 months ago

789,035,775,925,743
  • 3 answers

Sahil Singh 4 years, 5 months ago

using distance formula to find the sides of square EF=√{3-(-2)}^2+(0-0)^2 EF=√(5)^2+0 EF=√25 EF=5 we know that sides of a square are equal then th distance of sides EF=5 FG=5 GH=5 HE=5 PERIMETER= sum of all sides 5+5+5+5=20ans

Tanishq Singh 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

Sumit Chauhan 4 years, 6 months ago

First we find distance between EF, FH, HI and IE respectively after than add the distance all
  • 1 answers

Simmi Fagna 4 years, 5 months ago

(a2-b3)=(a²‐b²)ka formula
  • 0 answers
  • 1 answers

Jay Singh 4 years, 6 months ago

Let root5+root3be a rational number which can be written in the form of p upon q and q is not equal to 0 root5+root3=p\q root3=p\q-root5 root3=p-root5\q So that p-root5 is rational number Where root3 is irrational number So our contradict assumptions is wrong Thus' root 5+root 3 is irrational number Proved
  • 1 answers

Divya Soni 4 years, 6 months ago

A mathematical proof is an inferential argument for a mathematical statement, showing that the stated assumptions logically guarantee the conclusion.
  • 5 answers

Tanvi @1201 4 years, 6 months ago

Sec=4 by root 7

Tanishq Singh 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

It'S Krishna 4 years, 6 months ago

Diya soni you copied my answer

Divya Soni 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

It'S Krishna 4 years, 6 months ago

Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7
  • 3 answers

Sahil Singh 4 years, 6 months ago

if the question is a^2+b^2= (a^2+b^2)-2ab

Pavi Pandey 4 years, 6 months ago

A square + b square??what do u want to ask??

Simmi Fagna 4 years, 6 months ago

What is this ?
  • 1 answers

Rimi Singh 4 years, 6 months ago

Ans is 1
  • 2 answers

Surinder Kumar 4 years, 6 months ago

Class interval 0-20,20-40,40-60,60-80,80-100,100-120.and frequency is 5,f1,10,f2,7,8.

Surinder Kumar 4 years, 6 months ago

Table is also given
  • 3 answers

Anurag Singh 4 years, 5 months ago

Simmi fagna complete your answer questions ask shaded region find

Simmi Fagna 4 years, 5 months ago

Given, Side of square ABCD=10cm Area of square ABCD =(Side)² =(10)² =100cm² Given,semicircle is drawn with Side of square as diameter, So,Diameter of semicircle =Side of square =10cm Radius of semicircle =Side/2=10/2=5

Himanshu Verma 4 years, 6 months ago

Where is the picture?
  • 3 answers

Anurag Singh 4 years, 5 months ago

Answer is 0.68

Divya Soni 4 years, 6 months ago

17×2×2/5×5×2×2=68 10×10=100 68/100=0.68 ans

Hemang Dubey 4 years, 6 months ago

17×2×2/5×5×2×2=68/10×10 =68/100=0.68 ANS

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