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    • Posted by Simmi Fagna 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anurag Singh 5 years ago

    Answer is 88/21 or 4.1907

    0Thank You

    ANSWER

    • Posted by Akshat Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Vidhi Srivastav 5 years ago

    No!!!! 0 can be written in p/q form and it is a positive no.

    1Thank You

    Abhishek Kumar 5 years ago

    32. Prove that: sinθ(1+tanθ) + cosθ(1+cotθ)= secθ+cosecθ

    5Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anurag Singh 5 years ago

    4th vertex of parallelogram is (0,-1)

    1Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Dishi Shah 5 years ago

    4

    0Thank You

    Anurag Singh 5 years ago

    Simmi fagna your answer is wrong check your answer

    0Thank You

    Anurag Singh 5 years ago

    HCF OF( 96 AND 404) =4

    0Thank You

    Simmi Fagna 5 years ago

    404=2×2×101=2²×101¹

    0Thank You

    Simmi Fagna 5 years ago

    96=2×2×2×2×2×3=2²×3¹

    0Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anurag Singh 5 years ago

    Alpha =2 and bita =3/2

    0Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Srishtika Murugan 5 years ago

    I have used the following identity: a²-b²=(a+b)(a-b) 1+cot²∆=cosec²∆

    0Thank You

    Srishtika Murugan 5 years ago

    Consider ∆ to be theta. Cosec²∆-cot²∆=1 (cosec∆+cot∆)(cosec∆-cot∆)=1 (Cosec∆+cot∆)1/3=1 cosec∆+cot∆=3

    0Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Dishi Shah 5 years ago

    25 cm

    0Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anurag Singh 5 years ago

    Bro questions sahi sa likho kya CB. QR CA kya hai parallelogram hai ya aur kuch hai

    0Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Nitin Kumar 5 years ago

    1/36

    0Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Shubham Sharma 5 years ago

    9×1=9 9×2=18 9×3=27 9×4=36 9×5=45 9×6=54 9×7=63 9×8=72 9×9=81 9×10=90

    1Thank You

    ANSWER

    • Posted by Shubham Sharma 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Annu Singh 5 years ago

    45°

    0Thank You

    ANSWER

    • Posted by Pushvinder Singh 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Saiyam Jain 5 years ago

    No point interested

    0Thank You

    ANSWER

    • Posted by Ankit Singh 5 years ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Tanishq Singh 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Atul Mehra 5 years ago

    It is terminationg

    2Thank You

    ANSWER

    • Posted by Saloni Dubey 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Anurag Singh 5 years ago

    Write full question here.

    0Thank You

    Akshat Sharma 5 years ago

    What to find here?

    1Thank You

    Tanvi @1201 5 years ago

    What to find here???

    2Thank You

    ANSWER

    • Posted by Abhishek Brar 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Simmi Fagna 5 years ago

    798789×98778987=789035775925743

    0Thank You

    Akshat Sharma 5 years ago

    ?

    0Thank You

    Tanvi @1201 5 years ago

    789,035,775,925,743

    3Thank You

    ANSWER

    • Posted by Riya Saxena 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Sahil Singh 5 years ago

    using distance formula to find the sides of square EF=√{3-(-2)}^2+(0-0)^2 EF=√(5)^2+0 EF=√25 EF=5 we know that sides of a square are equal then th distance of sides EF=5 FG=5 GH=5 HE=5 PERIMETER= sum of all sides 5+5+5+5=20ans

    1Thank You

    Tanishq Singh 5 years ago

    Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

    1Thank You

    Sumit Chauhan 5 years ago

    First we find distance between EF, FH, HI and IE respectively after than add the distance all

    2Thank You

    ANSWER

    • Posted by Yajnesh Kulal 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Simmi Fagna 5 years ago

    (a2-b3)=(a²‐b²)ka formula

    0Thank You

    ANSWER

    • Posted by Priya Priya 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Ishan Khandelwal 5 years ago

    The distance between these points is 5√3m

    1Thank You

    ANSWER

    • Posted by Anjali Khatekar 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Simranpreet Kaur 5 years ago

    Both A and D

    0Thank You

    Ishan Khandelwal 5 years ago

    A is correct

    0Thank You

    Rashmi Maurya 5 years ago

    D one is correct

    0Thank You

    ANSWER

    • Posted by Devarsh Pandey 10A 5 years ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Marisetty Aashish 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Jay Singh 5 years ago

    Let root5+root3be a rational number which can be written in the form of p upon q and q is not equal to 0 root5+root3=p\q root3=p\q-root5 root3=p-root5\q So that p-root5 is rational number Where root3 is irrational number So our contradict assumptions is wrong Thus' root 5+root 3 is irrational number Proved

    0Thank You

    ANSWER

    • Posted by Simmi Fagna 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Divya Soni 5 years ago

    A mathematical proof is an inferential argument for a mathematical statement, showing that the stated assumptions logically guarantee the conclusion.

    4Thank You

    ANSWER

    • Posted by Priyanshi Yadav 5 years ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Tanvi @1201 5 years ago

    Sec=4 by root 7

    1Thank You

    Tanishq Singh 5 years ago

    Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

    0Thank You

    It'S Krishna 5 years ago

    Diya soni you copied my answer

    0Thank You

    Divya Soni 5 years ago

    Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

    1Thank You

    It'S Krishna 5 years ago

    Sin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7

    1Thank You

    ANSWER

    • Posted by Tanish Tiwadi 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Sahil Singh 5 years ago

    if the question is a^2+b^2= (a^2+b^2)-2ab

    0Thank You

    Pavi Pandey 5 years ago

    A square + b square??what do u want to ask??

    1Thank You

    Simmi Fagna 5 years ago

    What is this ?

    1Thank You

    ANSWER

    • Posted by Rajdeep Singh 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Rimi Singh 5 years ago

    Ans is 1

    1Thank You

    ANSWER

    • Posted by Surinder Kumar 5 years ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Surinder Kumar 5 years ago

    Class interval 0-20,20-40,40-60,60-80,80-100,100-120.and frequency is 5,f1,10,f2,7,8.

    0Thank You

    Surinder Kumar 5 years ago

    Table is also given

    1Thank You

    ANSWER

    • Posted by Koyal Shetty 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Anurag Singh 5 years ago

    Simmi fagna complete your answer questions ask shaded region find

    0Thank You

    Simmi Fagna 5 years ago

    Given, Side of square ABCD=10cm Area of square ABCD =(Side)² =(10)² =100cm² Given,semicircle is drawn with Side of square as diameter, So,Diameter of semicircle =Side of square =10cm Radius of semicircle =Side/2=10/2=5

    0Thank You

    Himanshu Verma 5 years ago

    Where is the picture?

    0Thank You

    ANSWER

    • Posted by Prema Jenila Gemmela 5 years ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Anurag Singh 5 years ago

    Answer is 0.68

    0Thank You

    Divya Soni 5 years ago

    17×2×2/5×5×2×2=68 10×10=100 68/100=0.68 ans

    0Thank You

    Hemang Dubey 5 years ago

    17×2×2/5×5×2×2=68/10×10 =68/100=0.68 ANS

    2Thank You

    ANSWER

    • Posted by Akampan Gill 5 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Samar Pratap 4 years, 11 months ago

    is aap ke malik ki aa chod denge

    2Thank You

    ANSWER

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