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  • 1 answers

Kiran Kumari 4 years, 6 months ago

Check the question
  • 3 answers

Bhoomika Verma 4 years, 6 months ago

Plzz check your question ,your question is incomplete ...

Annanya Gupta 4 years, 6 months ago

Your question is incomplete, please check it....

Vikas Kumar 4 years, 6 months ago

3x-7y=10 के लिए y और x के रुप में व्यक्त कीजिए|
  • 1 answers

Ff_Girl Tannu 4 years, 6 months ago

H= 3.5 , R = 50/2=25 cm 25/100= 0.25 Curved Surface Area= 2πrh = (2 x 22/7 x 0.25 x 3.5 )m^2 = 5.5 m^2 Cost of painting 1 m^2 area = Rs.12.50 Cost of painting 5.5 m^2 area = Rs.5.5×12.50 = Rs.68.75
  • 1 answers

Oviya Arumugam 4 years, 6 months ago

b^2-4ac 7×7-4×1×1=45 Formulae is ( -b plus or minus root of (b^2-4ac))/2×a Substitute value in the formulae The answer will be (-7+_root of 45)/2
  • 2 answers

Anurag Singh 4 years, 6 months ago

Ya yogeshwaran bro your answer is correct

Oviya Arumugam 4 years, 6 months ago

It does not contain real roots ie apply b^2-4ac it will less than 0
  • 4 answers

Sps Shashivendra Thakur 4 years, 6 months ago

bpt

Divyanshi Choudhary 4 years, 6 months ago

BPT,converse of BPT and Pythagoras

Varsha Shingh 4 years, 6 months ago

Manve karna ki Chamak Divya Chamak Ke a Saransh

Life Is Full Of Struggle 4 years, 6 months ago

Bpt theorem
  • 2 answers

Veerpal Sandhu 4 years, 6 months ago

Equation of line parallel to 3x−4y−5=0 is given by, 3x−4y+c=0 Also distance between given line is 1 ( c1- c2)√1+m^2 ⇒c+5 √3^2 +4^2 =1 ⇒∣c+5∣=5⇒c=0,−10 Hence line parallel to 3x−4y−5=0 and unit distance from it is 3x−4y−10=0 or 3x−4y=0

Ff_Girl Tannu 4 years, 6 months ago

Equation of line parallel to 3x−4y−5=0 is given by, 3x−4y+c=0 Also distance between given line is 1 ( c1- c2)√1+m^2 ⇒c+5 √3^2 +4^2 =1 ⇒∣c+5∣=5⇒c=0,−10 Hence line parallel to 3x−4y−5=0 and unit distance from it is 3x−4y−10=0 or 3x−4y=0
  • 3 answers

Life Is Full Of Struggle 4 years, 6 months ago

2= m(3)-5......... 7=m(3).......... m=7/3

Aditi Aditi 4 years, 6 months ago

Thanks✨✨

Life Is Full Of Struggle 4 years, 6 months ago

2=m(3) -5 7=3m m=7/3
  • 5 answers

Prerna Jain 4 years, 6 months ago

Neither composite nor prime

Erin Biju 4 years, 6 months ago

It is not prime And composite

Aditi Aditi 4 years, 6 months ago

It is neither prime nor composite.?

Bahman Ankush 4 years, 6 months ago

Yes

Siddharth S Singh 4 years, 6 months ago

1 is neither prime nor composite
  • 2 answers

Sunny Singh 4 years, 6 months ago

Is there any figure

Siya Singh 4 years, 6 months ago

Write the complete question
  • 4 answers

Bhoomika Verma 4 years, 6 months ago

0

Kiran Kumari 4 years, 6 months ago

(1_SIN^2)_Cos^2 Cos^2-cos^2=0

Sunny Singh 4 years, 6 months ago

0

Hayat 06 4 years, 6 months ago

Cos²@ - cos²@ = 0
  • 1 answers

Kiran Kumari 4 years, 6 months ago

an=a+(n-1)d 62=8+(n_1)d 54=nd-d (1) Sn=n/2 (2a+(n-1)d) 210=n/2 (2×8+(n-1)d) 420=n (16+nd-d ) 420=16n+n (nd-d ) 420=16n+n (54) (from 1) 420=16n+54n 420=70n 420/70=n Hence n=6 Now put the value of n in equation 1,we get 54=nd-d 54=6d-d 54/5=d
  • 1 answers

Ranjeet Singh Rajput 4 years, 6 months ago

answr Join / Login  What would you like to ask? 11thMathsComplex Numbers and Quadratic EquationsQuadratic EquationsIf the roots of the equatio... Maths If the roots of the equations ax2+2bx+c=0 and bx2−2ac​x+b=0 are simultaneously real, then prove that b2=ac. Easy Answer Let D1​ and D2​ be the discriminants of the two equations, then  D1​≥0 and D2​≥0 ⇒4b2−4ac≥0 and 4ac−4b2≥0 ⇒b2≥ac and ac≥b2 ⇒b2=ac
  • 2 answers

Sunny Singh 4 years, 6 months ago

Thita = 90°

Gade Sarvesh 4 years, 6 months ago

2sin^2theta-cos^2theta=2 Theta=90°.
  • 3 answers

Life Is Full Of Struggle 4 years, 6 months ago

11.45 is wrong answer ?

Life Is Full Of Struggle 4 years, 6 months ago

2r+πr=36......... r(2+π)=36......... r{2+22/7}=36........ r(36/7) =36 ...... r=7 ...... Diameter = 2(7) =14cm

Kinjal Agarwal 4 years, 6 months ago

11.45
  • 1 answers

Bhoomika Verma 4 years, 6 months ago

The least number divisible by all the numbers from 1 to 10 will be the LCM of these numbers.....1=1 .......2=2×1 .....3=3×1......4=2×2......5=5×1.. ...6=2×3......7=7×1.......8=2×2×2........9=3×3.....10=2×5...........so,LCM of these numbers=1×2×2×2×3×3×5×7=2520........hence,least number divisible by all the numbers from 1 to 10 is 2520.
  • 3 answers

Gade Sarvesh 4 years, 6 months ago

x^2-4x+3 x^2-x-3x+3 x(x-1)-3(x-1) (x-1)(x-3) x-1=0 , x=1, x-3=0 , x=3. x=1,3.

Vishal Prajapat 4 years, 6 months ago

X = 3. Ans

S Shridharshini 4 years, 6 months ago

x^2-3x-1x+3=0 x(x-3)-1(x-3)=0 (x-1)(x-3)=0 x-1=0 , x-3=0 x=1 , x=3
  • 0 answers
  • 1 answers

Atharva Paliwal 4 years, 6 months ago

3=3×1.......9=3^2×1......29=29×1 (LCM=product of highest common factors) LCM=3^2×29=261....

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