CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Stomach contains gastric gland which secrets gastric juices These juices are HCL Pepsin and mucus Hcl kills the germs and make ingested food acidic so as to Pepsin can work in easily. Pepsin breaks down protein into simpler substance i.e., peptones. Mucus helps in protecting of inner wall of stomach from its own secretion of hcl

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Kasinath Digal 4 years, 7 months ago

what is the role of stomach in our digestive system

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Solve for x : root 6x+7 - (2x-7) = 0

Posted by Aditya Chopra 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Simran Kohli 4 years, 7 months ago

6x+7-2x+7=0. 4x+14=0. 4x=-14. x=-7/2

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Bipin Kumar 4 years, 7 months ago

6x+7-(2x-7)=0 Soln: 6x+7-2x+7 =0 4x+14=0 4x=-14 x=-14/4 Therefore, x=-7/2.

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find the indicated terms of the sequence whose nth terms are ( n -1 )( 2 - n )( 3 - n ) ; a1,a2,a3

Posted by Sonakshi Saha 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 7 months ago

Here we have, a_n = (n - 1)(2 - n)(3 - n)
Put n = 1
_a1= 1(1 - 1)(2 - 1)(2 - 2)(3 + 2) = 0
Put n = 2
_a2= 2(2 - 1) (2 - 2)(3 + 2) = 0
Put n = 3
_a3= 3(3 - 1)(2 - 3)(3 + 3) = 3 (2) (-1) (6) = 36

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(1/2x)+(1/3y)=2 (1/3x)+(1/2y)=13/6 Solve this equation by eliminating method

Posted by Sairam Narayan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Shubh Madheshiya 4 years, 7 months ago

Let 1/x=a,1/y=b ,1a/2+1b/3=2(1a/3)+(1b/2)=13/6 ,

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Shubh Madheshiya 4 years, 7 months ago

Let 1/x=a,1/y=b ,1a/2+1b/3=2(1a/3)+(1b/2)=13/6

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Deepesh Jha 4 years, 7 months ago

Let 1/x be a and 1/y be b. a/2 + b/3 = 2 and a/3 + b/2 = 13/6. Now take LCM. 3a/6 + 2b/6 = 2 and 2a/6 + 3b/6 = 13/6. Send the denominator to RHS. 3a + 2b = 12 and 2a + 3b = 13. Multiplying eq 1 by 2 and eq 2 by 1 . We get 6a + 4b = 24 and 6a + 9b = 39. Now you can eliminate.

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If cosec A - sin A = a^3, sec A - cos A = b^, prove that a^2b^2(a^2+b^2) = 1

Posted by Syed Rehaan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 7 months ago

We use {tex}\theta{/tex} = A

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In fig ΔABC is a right angle triangle at A. Semicircle are drawn on AB, AC and BC as diameter it is given that AB =3cm and AC=4cm find the area of the shaded region

Posted by Fox Faizal 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 7 months ago

In triangle ABC, by pythagoras theorm,we have,
{tex}B C = \sqrt { A B ^ { 2 } + A C ^ { 2 } }{/tex}
{tex}B C = \sqrt { 9 + 16 }{/tex}
{tex}B C = \sqrt { 25 }{/tex}
= 5 cm
Ar(shaded part) = Ar({tex}\triangle ABC{/tex}) + Ar(semicircle APB) + Ar.( semicircle AQC ) - Ar.(semicircle BAC)
{tex}=\left( \frac { 1 } { 2 } \times 3 \times 4 \right) + \left( \frac { 1 } { 2 } \pi \times 1.5 \times 1.5 \right) + \left( \frac { 1 } { 2 } \pi \times 2 \times 2 \right) - \left( \frac { 1 } { 2 } \pi \times 2.5 \times 2.5 \right){/tex}
{tex}= 6 + \frac { 1 } { 2 } \pi \left( 4 + \frac { 9 } { 4 } - \frac { 25 } { 4 } \right){/tex}
= 6 + 0
= 6 cm²

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In a rectangular part of dimension 50m×40m a rectangular pond is constructed so that the area of grass strip of uniform breadth surroundings, the pond would be 1184m², find the length and the breadth of the pond

Posted by Fox Faizal 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 7 months ago

It is given that the dimensions of the rectangular park is 50 m {tex}\times{/tex} 40 m.
{tex}\therefore{/tex} Area of the rectangular park = 50 {tex}\times{/tex} 40 = 2000 m²
Area of the grass surrounding the pond = 1184 m²
Now,
Area of the rectangular pond
= Area of the rectangular park − Area of the grass surrounding the rectangular pond
= 2000 − 1184
= 816 m²
Let the uniform width of the surrounding grass be y.
{tex}\therefore{/tex} Length of the rectangular pond = (50 − 2y) m
Breadth of the rectangular pond = (40 − 2y) m
Now,
Area of rectangular pond = 816 m²
{tex}\therefore{/tex} (50 − 2y) {tex}\times{/tex} (40 − 2y) = 816
{tex}\Rightarrow{/tex} 2000 − 80y − 100y + 4y² = 816
{tex}\Rightarrow{/tex} 4y² − 180y + 2000 − 816 = 0
{tex}\Rightarrow{/tex} 4y² − 180y + 1184 = 0
{tex}\Rightarrow{/tex} y² − 45y + 296 = 0
{tex}\Rightarrow{/tex} y² − 37y − 8y + 296 = 0
{tex}\Rightarrow{/tex} y(y − 37) − 8(y − 37) = 0
{tex}\Rightarrow{/tex} (y − 8)(y − 37) = 0
{tex}\Rightarrow{/tex} y − 8 = 0 or y − 37 = 0
{tex}\Rightarrow{/tex} y = 8 or y = 37
For y = 37,
Length of rectangular pond = 50 − 2 {tex}\times{/tex} 37 = −24 m, which is not possible
So, y {tex}\ne{/tex} 37
Therefore, y = 8.
When y = 8,
Length of the rectangular pond = 50 − 2 {tex}\times{/tex} 8 = 50 − 16 = 34 m
Breadth of the rectangular pond = 40 − 2 {tex}\times{/tex} 8 = 40 − 16 = 24 m.

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the height of a right circular cylinder is 6 m if three times the sum of the areas of its two circular faces is twice the area of its curved surface ,find the radius of its base

Posted by Ritu Rajput 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Tanisha Jeengar 4 years, 7 months ago

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1/2(2x+3y)+ 12/7(3x-2y)=1/2; 7/2x+3y. + 2/3x-2y =2

Posted by Mohammad Adnan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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A bag contains red and blue socks if the probability of getting a blue socks is 0.17 and find the probability of not getting a blue socks and the probability of A Red socks

Posted by Aadarsh Gupta 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Prashant . 4 years, 7 months ago

1- 0.17 =0.83

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_A_L_E_X _A 4 years, 7 months ago

0.83

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Aadarsh Gupta 4 years, 7 months ago

Answer say

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Distance between two ships is 73.2 m. From the top of tower, 100 m high, a man observes two cars on the opposite sides of the tower with the angles of depression 30c and 45c respectively. Find the distance between the cars. (Use 3 1 = .73)

Posted by Suriya Prakash 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Palak ? 1 year, 10 months ago

It answer is 72km/hr

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Posted by Madhura Dighikar 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 7 months ago

iii) The ratio of their perimeters is 6: 9

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The first and last terms of an ap are 17 ,350 respectively if common difference is 9 how many terms are there and what is their sum

Posted by Bhoomi Bhoomi 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Aakash Anand 4 years, 7 months ago

A= 17 D= 9 Añ and lest terms = 350 Añ= a + (n-1)d # 350= 17 + (n-1)9 # 350- 17 =( n-1 )9 # 333= (n-1)9 # 333/9 = n-1 # 37 = n -1 # 37 + 1 = n @ n = 38 # Sun = n/2 (a + l) = 38 /2 (17 + 350) = 19 × 367 = 6973 Ans....... ........ Aakash Anand ?

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Write down the decimal expansion of 29 upon 343

Posted by Vikash Kumar 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Aakash Anand 4 years, 7 months ago

29/343 Prime factors of 343 = 7×7×7 The denominator is not in the form of 2 and 5 so there Will be no Terminating decimal expansion.................

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Shubh Madheshiya 4 years, 7 months ago

0.845

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Harsh Harsh Boora 4 years, 7 months ago

0.0670..

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1. Find the quadratic polynomial whose zeroes are i) - 3 and 2 ii) 5 and 1 iii) 4 and -2 iv)√3 and −√3

Posted by Vishal Porwal 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Aakash Anand 4 years, 7 months ago

Let alpha = -3 and beta = 2 Sum of zeros = (-3) + 2= -1 Product of zeros = (-3) ×2= -6 Polynomial = x²- ( sum of zeros) + ( products of zeros) # x² - (-1)x + (-6) # x² + 1 - 6 ....... (P)....

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Shubh Madheshiya 4 years, 7 months ago

1. x२+ x -6 2. x२ - 6 x + 6 3 . x२ - 2x -8 4, x२ - 3

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Show that any odd positive integer in the form of 6q+1, 6q+3, or 6q+5

Posted by Mamta Kumari 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Hitkar Miglani 4 years, 7 months ago

According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers q and r which satisfies the condition a = bq + r where 0 ≤ r < b. Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder. According to Euclid’s division lemma a = bq + r a = 6q + r………………….(1) where, (0 ≤ r < 6) So r can be either 0, 1, 2, 3, 4 and 5. Case 1: If r = 1, then equation (1) becomes a = 6q + 1 The Above equation will be always as an odd integer. Case 2: If r = 3, then equation (1) becomes a = 6q + 3 The Above equation will be always as an odd integer. Case 3: If r = 5, then equation (1) becomes a = 6q + 5 The above equation will be always as an odd integer. ∴ Any odd integer is of the form 6q + 1 or 6q + 3 or 6q + 5. Hence proved.

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Prove that Root3 is irrational number

Posted by Aakash Anand 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Aakash Anand 4 years, 7 months ago

If possible let √3 is a rational number Let √3 =a/b {a and b is co- prime number} = b√3 =a [ squaring both side] [ b√3]²=[a]² = 3b²=a²................. (1) 3 is divides a² Their for 3 divides a Let a= 3c [ c is positive integer] Putting a=3c in equation (1) # 3b²= (3c) ² # 3b² = 9c² # b²= 3c² 3 is divides b² Their for 3 divides b 3 is common factor of A and B But It contradict the fact a and b are co-prime number So our assumlat is wrong Their for √ 3 is an irrational number. .......... Aakash Anand ?

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Find the coordinates of the points of Trisection of the line segment joining (4, -1) and (-2, -3).

Posted by Sandhya V 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Pawani Singla 4 years, 7 months ago

Trisection means 1:1:1. Use section formula and find out.

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Aakash Anand 4 years, 7 months ago

Let point A(4, -1) and (-2, -3)

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Rashmi Ranjan 4 years, 7 months ago

Trisection means 2:1 or 1:2 Use section formula and find out

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A solid radius in the shape of a cone mounted in a hemisphere of same base radius .if the curved surface areas of the hemuspherical part and the conical part are equal,then find the ratio of the radius and the height of the conical part

Posted by Urvashi Chouhan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Rashmi Ranjan 4 years, 7 months ago

2πrsquare =πrl l=2r We know that h =√rsqare -l square (put l=2r) then height =√3r Ratio of the radius and the height of the cone =1/√3

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Find the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

Posted by Satyam Yadav 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Rashmi Ranjan 4 years, 7 months ago

L. C. M of 8,15and21=840 110000-840=109200

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construct a circle of radius 3.5cm draw its longest chord and construct its perpendicular bisector. NOTE: draw its longest chord.

Posted by Nikita Gangwar 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Akhil Garg 4 years, 7 months ago

The longest chord of a circle is diameter

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Square root of 5

Posted by R.Shivani Ratnam.Shivani 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Shivang ___ 4 years, 7 months ago

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Aakash Anand 4 years, 7 months ago

2.2360.......

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Keerthana Varughese 4 years, 7 months ago

√5 = 2.2360…

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A solid is hemispherical at the bottom and conical above it. The surface areas of two parts are equal then the ratio of its radius and height of its conical part is ?

Posted by Tanishka Sharma 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sachin Bhati 4 years, 7 months ago

1:√3

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4÷8=?

Posted by Quareena Kashish 4 years, 7 months ago

CBSE > Class 10 > Mathematics

4 answers

Shruti Magar 4 years, 7 months ago

0.5

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Aditya Thakur 4 years, 7 months ago

0.5

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No One 4 years, 7 months ago

Half of 1 0.5 ^_^

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Aniket Agrawal 4 years, 7 months ago

1/2 = 0.5

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Use Euclid's division lemma to show that the square of any positive integers is either of the form 3m or 3m + 1 for some integer

Posted by Hiya Rajpoot 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Divyani Lahane 4 years, 7 months ago

P=3q+r 0 < r < 3 ,r= integer If r=0 ,p=3q-------(1) r=1 ,p=3q+1-------(2) r=2 ,p=3q+2--------(3) Squaring both side 9q²--------(1) 3(3q²). Let 3q² be m =3m 9q²+1²--------(2) =3(3q²)+1 let 3q² be m =3m+1 Therefore, the sum is solved

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Aakash Anand 4 years, 7 months ago

Yesss

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Tarasha Agarwal 4 years, 7 months ago

Not coming in course for boards 2020-2021

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x1,y1=-3,-1 x2,y2=2,4 find the answer using distance formula

Posted by Meet Sabhaya 4 years, 7 months ago

CBSE > Class 10 > Mathematics