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  • 3 answers

Deepali Vishnoi 1 year, 8 months ago

The distance between the points (0,2/5)and (-2/5,0)is

Shuhbham Mahakud 1 year, 8 months ago

Sn = n/2 [2a + (n-1)d] Substituting values :- 0 = n/2 [2(50) + (n-1)(-4)] 0 = n/2 [100 - 4n + 4] 0 = n/2 [104 - 4n] 0 = n/2 × 4 [ 26 - n ] 0 = 2n [ 26 - n ] 0 = 26 - n - 26 = - n 26 = n. This should be the answer according to me.

Its Vicky 1 year, 8 months ago

Sn = n/2 [2a + (n-1)d] Substituting values :- 0 = n/2 [2(50) + (n-1)(-4)] 0 = n/2 [100 - 4n + 4] 0 = n/2 [104 - 4n] 0 = n/2 × 4 [ 26 - n ] 0 = 2n [ 26 - n ] 0 = 26 - n - 26 = - n 26 = n. This should be the answer according to me.
  • 3 answers

Akanksha Kumari 1 year, 8 months ago

(x-1) (x-2) (x-7)

Stanzin Lhadon 1 year, 8 months ago

(x-2)(x-7)(x-1)

Aditya Sinha 1 year, 8 months ago

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  • 3 answers

Sarthak Malviya 1 year, 8 months ago

LCM will be (x-2)(x-2)(x-7)

Sarthak Malviya 1 year, 8 months ago

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Ritika Chauhan 1 year, 8 months ago

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  • 1 answers

Raunak Singh 1 year, 8 months ago

Intersecting at point (a,b)
  • 2 answers

S. Youthish Kumar 1 year, 8 months ago

8

Raunak Singh 1 year, 8 months ago

8 cm of diameter can be fitted with a height of 8 cm
  • 2 answers

Sarthak Malviya 1 year, 8 months ago

A=-2or2 and b=2or-2 then answer is -16 or 16

S. Youthish Kumar 1 year, 8 months ago

0
  • 2 answers

Ritika Chauhan 1 year, 8 months ago

Solution - Sin30° = 1/2 , tan 45° = 1 , sec 30° = 2/√3 , cot45° = 1 = 1/2 + 1 ÷ √3/2 + 1 = 1+2 / 2 ÷ √3 + 2 / 2 = 3 / 2 × 2 / √3 + 2 = 3 / √3 + 2 = √3 × √3 / √3 + 2 = √3 / 2 = Sin 60° answer I hope this is helpful to you...~

Kavya Rajvanshi 1 year, 8 months ago

1/2+1÷ 2/√3+1 = 1+2/3 ÷ 2+√3/2√3 = 3√3(2-√3)/2 is a answer
  • 3 answers

Sai Pansare 1 year, 8 months ago

Let the ratio in which the line segment joining A(- 3, 10) and B(6, - 8) be divided by point C(- 1, 6) be k : 1. By Section formula, C(x, y) = [(mx₂ + nx₁) / m + n, (my₂ + ny₁) / m + n] m = k, n = 1 Therefore, - 1 = (6k - 3) / (k + 1) - k - 1 = 6k - 3 7k = 2 k = 2 / 7 Hence, the point C divides line segment AB in the ratio 2 : 7.

Raunak Singh 1 year, 8 months ago

2:7

Parimal Katpatal 1 year, 8 months ago

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  • 2 answers

Shuhbham Mahakud 1 year, 8 months ago

TO PROVE:-(1+tan²A)/(1+cot²A) = sec²A-1 =>(1+tan²A)/(1+1/tan²A){ we know that cot²A = 1/tan²A } =>(1+ tan²A)/ {(tan²A + 1)/tan²A} =>{(tan²A)(1+ tan²A)}/ (tan²A+ 1) => tan²A => sec²A-1 { from the identity sec²A-tan²A = 1}

Shagun Sehra 1 year, 8 months ago

TO PROVE:-(1+tan²A)/(1+cot²A) = sec²A-1 =>(1+tan²A)/(1+1/tan²A){ we know that cot²A = 1/tan²A } =>(1+ tan²A)/ {(tan²A + 1)/tan²A} =>{(tan²A)(1+ tan²A)}/ (tan²A+ 1) => tan²A => sec²A-1 { from the identity sec²A-tan²A = 1}
  • 0 answers
  • 1 answers

Utkarsh Shrivastava 1 year, 8 months ago

Because it has non terminating ana non repeating decimal expansion
  • 1 answers

Shagun Sehra 1 year, 8 months ago

x = m + n y = m - n
  • 2 answers

Kuldeep Mallick 1 year, 8 months ago

0.4

Fjak Nka 1 year, 8 months ago

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  • 1 answers

Raunak Singh 1 year, 8 months ago

x= 10 or x= 21/2
  • 2 answers

Manoj Kumar 1 year, 6 months ago

(Tan theta)^2 - (sin theta)^2

Yug Purohit 1 year, 8 months ago

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  • 1 answers

Vedansh Tiwari 1 year, 8 months ago

sin(A+B) = 1 sin(A+B) = sin90 A+B = 90 [equation 1] cos(A-B) = 1 cos(A-B) = cos 0 A-B = 0 [equation 2] add equation (1) and (2) we get 2A=90 A=45o put the value of A in equation (2) A-B=0 45-B=0 B=45o A=B=45o
  • 1 answers

Alfiya💫💫💫 . 1 year, 8 months ago

D =b²-4ac.. =6²-4x1x10 =36-40 -4 D<0 hence it has no real root..
  • 2 answers

Lucky Sharma 1 year, 8 months ago

Answer is 2 sin x + 1 sinx = 2sin2x + 1 = 2 sin x (sinx - 1)²= 0 ⇒ sin x = = 1 cosec x = 1 in 19 x + cosec20 x = 1+1=2

Lucky Sharma 1 year, 8 months ago

1
  • 4 answers

Palak Siwach 1 year, 8 months ago

Area of minor segment is 10.87 cm² and area of major segment is 3132.1cm²

Arush Negi 1 year, 8 months ago

55/6

Arush Negi 1 year, 8 months ago

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Arush Negi 1 year, 8 months ago

55
  • 2 answers

Varshaa Rbm 1 year, 8 months ago

Is this what u asked for??

Varshaa Rbm 1 year, 8 months ago

X=-7/3

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