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Not Fine Bro 🎭 8 months, 2 weeks ago

3²×5²×17

D.Manoj Kumar 8 months, 2 weeks ago

3×3×5×5×17
  • 4 answers

Suman Yadav 8 months, 2 weeks ago

2

Alfiya💫💫💫 . 8 months, 2 weeks ago

3

Not Fine Bro 🎭 8 months, 2 weeks ago

3

Ganesh Kandha 8 months, 2 weeks ago

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Arshpreet Anand 8 months, 2 weeks ago

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Arshpreet Anand 8 months, 2 weeks ago

You are late Should've started when you were one
  • 4 answers

D.Manoj Kumar 8 months, 2 weeks ago

It is not a Quadratic equation but then the value of 'x'will be 3/7

Khushpreet Kaur 8 months, 2 weeks ago

2 + 3 x + 1 = ( x − 2 ) 2 x 2 + 3 x + 1 = x 2 − 4 x + 4 ⇒ x 2 + 3 x + 1 − x 2 + 4 x − 4 = 0 ⇒ 7 x − 3 = 0 has its highest power of variable as 1 Hence it is not a quadratic equation

Khushpreet Kaur 8 months, 2 weeks ago

by using identity (a-b)²=a²-2ab+b² =X²–2(x)(2)+2² =x²–4x+4=x²+3x+1 By applying hit and trial method (1)²-4(1)+4=0 0=0 x-1 is zero of polynomial

Khushpreet Kaur 8 months, 2 weeks ago

by using identity (a-b)²=a²-2ab+b² =X²–2(x)(2)+2² =x²–4x+4 By splitting the mid term =x²-2x-2x+4 =x(x-2)-2(x-2) (x-2)(x-2)=
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Arush Saraswat 8 months, 2 weeks ago

Assume that .............................. That is answer find it
  • 2 answers

Not Fine Bro 🎭 8 months, 2 weeks ago

Let a and b irrational number where a and b are odd numbers....

Shreyansh Singh 8 months, 2 weeks ago

Hii sir
  • 4 answers

Not Fine Bro 🎭 8 months, 2 weeks ago

It will be very tough!! Because I know But I think you will pass by scoring around 30-40 marks

D.Manoj Kumar 8 months, 2 weeks ago

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Hari Shankar 8 months, 2 weeks ago

IT MAY VE EASY OR TOUGH DOESNT MATTER THE MATTER IS HOW U PREPARE FOR EXAMS

Srikanth Marre 8 months, 2 weeks ago

Find the sum of exponents of prime factor in the prime factorisation
  • 1 answers

Not Fine Bro 🎭 8 months, 2 weeks ago

This type of questions will not be asked in board exam
  • 3 answers

Vandit Sharma 8 months, 1 week ago

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Bhargav Kulkarni 8 months, 2 weeks ago

We know that , 1+tan2Φ=sec2Φ 1+sin2Φ/cos2Φ=1/cos2Φ Multiply cos2Φ on both sides We get cos2Φ+sin2Φ=1 sin2Φ+cos2Φ=1

Indrajeet Bera 8 months, 2 weeks ago

Let a, b, c be lengths of right angled triangle By definition sinθ=b/c(opposite sidehypotenuse) cosθ=a/c(adjacent sidehypotenuse) sin2θ+cos2θ=b2c2+a2c2=a2+b2c2 From Pythagoras theorem c2=a2+b2 ∴a2+b2c2=1 sin2θ+cos2θ=1 Hence, proved.
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Dikha Sarkar 8 months, 2 weeks ago

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Sachin Prajapati 8 months, 3 weeks ago

It depends on its highest power like If the power is- 2-then there are two zeroes 3-then there are three zero And so on.
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Arun Choudhary 8 months, 2 weeks ago

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Naincy Agarwal 8 months, 2 weeks ago

sol a2=a+d=14 ➡️a=14-d. i a+2d=18 ➡️14-d+2d=18. From i ➡️d=4 Now put d=4 in I a=14-4 a=10 Now to find sum of first 51 term Sn=n/2(2a+{n-1}d) S51=51/2(2×10+{51-1}×4) S51=51/2(20+50×4) S51=51/2(20+220) S51=51/2×240 S51=51×120 S51=6120 So sum of first 51 term of an AP will be 6120 where a=10 and d=4

Rudra King 8 months, 3 weeks ago

5610
  • 1 answers

Satyadeep Yadav 8 months, 3 weeks ago

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  • 1 answers

Zeel Patel 8 months, 3 weeks ago

√3/2 x √3/2 + 1/2 x 1/2 3/4 + 1/4 4/4 1
  • 1 answers

Manya Yadav 8 months, 4 weeks ago

Firt let 2root3 + root 5 is rational no. Then written in the form of p/q where p and q are co prime no. Then equalise The both side
  • 1 answers

Tanya Patel 8 months, 3 weeks ago

The perimeter of each semicircle will be 44 cm.
  • 1 answers

Khushi Tiwari 8 months, 4 weeks ago

Let the radius of smaller circle be (r) 2cm And, the radius of bigger circle be(R), 5cm Now, Area of circle is πr^2 So, πR^2 -πr^2 = π(R^2 - r^2) =22/7[(5)^2 - (2)^2] =22/7[25 - 9] = 22/7 ×16 = 3.14 × 16 = 50.24cm^2
  • 1 answers

Lionel Messi 8 months, 4 weeks ago

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Manya Yadav 8 months, 4 weeks ago

X = 1 and y= -2

Tarnika S 8 months, 4 weeks ago

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Nitin Kumar 9 months ago

3x-⁵/3 then multiply by 3, 9x-5 9x=5 x=5/9

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