CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

The HCF of 1.2 and 0.12 is 0.12 We will convert the given decimals into like decimals in which the number of digits after the decimal point are the same. So, now our numbers are 120 and 12. Now, we will find the HCF of 120 and 12. Clearly, the Highest Common Factor (HCF) of 120 and 12 is 12.

1Thank You

ANSWER

If cot = 15/8, then evaluate (2+2sin)(1-sin)/(1+cos)(2-2cos)

Posted by Suhana Bhojwani 4 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Pranay Shrivastava 4 years, 2 months ago

15/under root 32

0Thank You

Yash Madhok 4 years, 2 months ago

(2+2 sin A) (1-sin A)/(1+cos A) (2-2 cos A) = 2(1+sin A) (1-sin A)/2(1+cos A) (1-cos A) = (1-sin2A)/(1-cos2A) = cos2A/sin2A = cot2A = 225/64

0Thank You

ANSWER

If in triangle abc right angled at b , sinC = a²-b² / a²+b², then cosC equals to Plz help...

Posted by Osama Bin Laden 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The expression of the Polynomial represented by the graph is

Posted by Kamakshi Sinha 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What will happen if I do not attend the cbse improvement exam class x? I got the passing marks in all subjects, will cbse fail me.

Posted by Mukul Kumar 😎 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Lucky Goyal 4 years, 2 months ago

This all depends on your struggle

1Thank You

ANSWER

tan² A – 5 sec² A + 1 is equal to (a) 6 (6) -5 (c) 1 (d) -4

Posted by Deepika Sharma 4 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Pranay Shrivastava 4 years, 2 months ago

-4

1Thank You

Ram Narayan 4 years, 2 months ago

-4/cos2

1Thank You

Deepika Sharma 4 years, 2 months ago

Answer d ,(-4)

2Thank You

ANSWER

The side of square is 28 cm and radios of each circle is half of the length of the side of the square , where O and O are centre of the circle find the area of the shaded region?

Posted by Saniya Danish 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Surjeet Mohanty 4 years, 2 months ago

We know that the side of the square is 28 cm, so the area of the square will be 282=28×28=784cm2.

0Thank You

ANSWER

Find the centre of the circle passing through (5 ,-8),(2, -9)and (2, 1)

Posted by Pratap Tiwari 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Solve x and y hence find a for which y= ax-4 2/x + 2/3y = 1/6 3/x + 2/y =0

Posted by Komal Choudhary 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which of the following number have terminating decimal 16/225,5/18,2/21,7/250

Posted by Indhu Sri 4 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Kareena Dhankhad 4 years, 2 months ago

7/250 with division of 2 × 5^3 which is sign of terminating decimal

0Thank You

Student Id 4 years, 2 months ago

16/225

0Thank You

Pranay Shrivastava 4 years, 2 months ago

16/225

0Thank You

ANSWER

Ex6.6 12

Posted by N.Srinivas Srinivas 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Pranay Shrivastava 4 years, 2 months ago

Wo optional hai nahi aayega exam me

0Thank You

ANSWER

PROVETHAT: COSA÷1+SINA+1+SINA÷COSA=2SECA

Posted by Aiswarya Gigi 4 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

prove that the diagonals of a trapezium intersect each other in the same ratio

Posted by Darika S 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Solve the quadratic equation by factorisation : 1) 1/ x - 1/x-2 =3

Posted by A M 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Saniya Haseen 4 years, 2 months ago

Nhaush

3Thank You

ANSWER

A and B are respectively the points on the sides PQ and PR of a ∆PQR such that PQ = 12.5 cm, PA = 5 cm, BR = 6 cm, and PB = 4 cm. Is AB || QR? Give reason.

Posted by Adite Mishra 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

A M 4 years, 2 months ago

Yes AB||QR because PA/AQ = PB/BR [ 5/1.5=4/6] So it follows the thales theorem . By converse of thales theorem AB||QR

0Thank You

ANSWER

4x-3y=8 6x-y=29/3 By substituting method

Posted by Sujit Sahu 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Rishu Maurya 4 years, 2 months ago

4x-3y=8 ...eq(1) 6x-y=29/3 ....e(q2) From eq 1 4x-3y=8 X=8+3y/4 Putting the value of x in eq 2 we get; 6

0Thank You

ANSWER

The hcf of 4095 and 378

Posted by Amruta Patil 4 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Rinki Balhara 4 years, 2 months ago

2Thank You

Koushik . 4 years, 2 months ago

2Thank You

Ibrar Ansari 4 years, 2 months ago

The HCF of 4095 and 378 is 63.

3Thank You

ANSWER

The hcf of 4095 and 378 is

Posted by Amruta Patil 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Siddharth Roy 4 years, 2 months ago

HCF of 4095 and 378 is 63?

0Thank You

ANSWER

Two quadrants are inscribed under square has side 10m . Find the area of that region which are left .

Posted by Kanu Varshney 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Akshay Pratap Singh 4 years, 2 months ago

Area of shaded region =2[Area of quadrant − Area of triangle] =2[4π(10)2−21×10×10] =2×100[7×422−21] =200×72=7400Sq.cm.

1Thank You

ANSWER

Two quadrants are inscribed under square . Find the area of shaded portion.

Posted by Kanu Varshney 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Niharika Nidhi 4 years, 2 months ago

Area of square - area of semi circle

0Thank You

ANSWER

Ch 12 example 6 by another method

Posted by Kanu Varshney 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Kanu Varshney 4 years, 2 months ago

Pls give me and quickly

0Thank You

ANSWER

1/4,1/3

Posted by Zameer Pasha Yarab Pasha 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the centre of a circle passing through 5, - 8 2,-9 2,1

Posted by Vivan Asai 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If product of the zeroes of the polynomial kx sqaure- 11x+30 is 2, then the value of k is

Posted by Shivani Sharma 4 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Harsh Jha 4 years, 2 months ago

1Thank You

Prabhu Singh 4 years, 2 months ago

K 2

0Thank You

ANSWER

Find quadratic equation, if p and q are the roots of the equation x² - px + q = 0 when p = 1 and q = -2.

Posted by Yash Mishra 4 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Page 125 of 1971

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Install Now

Test Generator

Create papers online. It's FREE.

Try Now

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Install Now

myCBSEguide

myCBSEguide

Test Generator

CUET Mock Tests

Download myCBSEguide App

All Courses

Other Websites

CBSE Courses

Resources

Corporate

NCERT Solutions

CBSE Sample Papers