No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Shreya Gupta 4 years, 2 months ago

Let any integer be n By Euclid geography lemma P=n.q+r Let remainder be 0,1,2,3 When remainder be 0 N=3q +0 =3q When r=1 N=3q+1
  • 1 answers

Akshay Pratap Singh 4 years, 2 months ago

Let the speed of car at A be x kmph and the speed of car at B be y kmph when the car travel in same direction Relative Speed is x−y Dist=100km t=5 hours ∴  Dist =S×T 100=(x−y)5 x−y=20⟶(I) when car travel in opp direction Relative Speed is x+y Dist=100km t=1 hours Dist=ST 100=(x+y)1 x+y=100⟶(II) Solving (I) & (II) x−y=20 x+y=100​    2x=120 x=60km/h y=40km/h Speed of the car at A =60 km/h Speed of the car at B=40 km/h The difference of speeds is 60−40=20 
  • 1 answers

A M 4 years, 2 months ago

1
  • 3 answers

Manoj Ks Manu 4 years, 2 months ago

Search in goggle

Omkar Varma 4 years, 2 months ago

Put appropriate question

Apsana Khatoon 4 years, 2 months ago

Hii
  • 1 answers

Aditya Singh 4 years, 2 months ago

The Euclidean Algorithm for finding HCF (A,B) is as follows: If A=0 then HCF (A,B)=B, since the HCF (0,B)=B, and we can stop.   If B=0 then HCF (A,B)=A, since the HCF (A,0)=A, and we can stop.   Write A in quotient remainder form (A=BQ+R) Find HCF (B,R) using the Euclidean Algorithm since  HCF (A,B)=HCF(B,R) Here, HCF of 441 and 567 can be found as follows:- 567=441×1+126 ⇒ 441=126×3+63 ⇒ 126=63×2+0 Since remainder is 0, therefore,  H.C.F of (441,567) is =63 Now H.C.F of 63 and 693 is 693=63×11+0 Therefore, H.C.F of (63,693)=63 Thus, H.C.F of (441,567,693)=63.
  • 3 answers

Kashish Garg 4 years, 2 months ago

Kya mtlb h maine is me kya glt bola

Mukul Saini 4 years, 2 months ago

Bhai ye tera bolne ka sahi tarika h tere ghar me koi Bhan nahi h kiya bta

Ranjan Kumar Bipran 4 years, 2 months ago

Bass labaour kr bsdki
  • 5 answers

Bhoomika Garg 4 years, 2 months ago

22/7 or 3.14

Atul Kumar 4 years, 2 months ago

But π≠22/7 but it is appropriate value.

Atul Kumar 4 years, 2 months ago

22/7

Mohit Chauhan 4 years, 3 months ago

3.14

Ravneet Kaur 4 years, 3 months ago

22/7
  • 1 answers

Koyya Vamsi 4 years, 3 months ago

Sector : 0⁰/360xπr²
  • 2 answers

Om Sharma 4 years, 3 months ago

Cosec A = 5/3 So, 1/sin A = 5/3 Hypotenuse/perpendicular = 5/3 Hypotenuse = 3k & perpendicular = 4k Using Pythagoras theorem, 25k² = 9k² + (base)² 16k² = (base)² √16k² = base 4k = base Cos A - Tan A 4k/5k - 3k/4k 4/5 - 3/4 (16 - 15)/20 1/20 ans.

Koppisetti Sidhu 4 years, 3 months ago

31/20
  • 1 answers

Koppisetti Sidhu 4 years, 3 months ago

2,13/7
  • 2 answers

A M 4 years, 2 months ago

Parabola

Koppisetti Sidhu 4 years, 3 months ago

General graph of quadratic polynomial is parabola
  • 1 answers

Sharanpreet Kaur 4 years, 3 months ago

The graph of a quadratic function is a U-shaped curve called a parabola. The x-intercepts are the points at which the parabola crosses the x-axis.
  • 1 answers

Koyya Vamsi 4 years, 3 months ago

Possible outcomes are 1,2,3,4,5,6,
  • 4 answers

Isha Saini 4 years, 3 months ago

89

User ....???.... 4 years, 3 months ago

2 + 87 = 89

Aman Kumar Yadav 4 years, 3 months ago

89

Rishi Raj 4 years, 3 months ago

Answer is 89
  • 1 answers

Varshini Hota 4 years, 3 months ago

This topic not coming for boards this year
  • 4 answers

Varshini Hota 4 years, 3 months ago

Yess

Nawaid Alam 4 years, 3 months ago

shut up BTS sucks watch anime.

Ankit Kumar 4 years, 3 months ago

No

A S 4 years, 3 months ago

No one
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App