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Let the HCF be x LCM=HCF+900 LCM=x+900 --(1) And LCM+HCF=1260 LCM+x=1260 --(2) From (1) and (2) (x+900)+x=1260 2x+900=1260 2x=1260−900 2x=360 x=2360 x=180 HCF =180 And, from (1), LCM=HCF+900 LCM=180+900 LCM=1080 By formula, product of the numbers is equal to the product of their HCF and LCM. Product of numbers =HCF×LCM =180×1080 Product =194400

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How to identify polynomials

Posted by Rumpa Barmam 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepakshi Kabra 4 years, 7 months ago

Polynomials //Linear polynomial – of degree one. Quadratic Polynomial- of degree two. Cubic Polynomial – of degree three. Degree of polynomial is never negative nor fractional also variable should not be in denominator or in root

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Find the point on the x-axis which is equidistant from (2,-5)and (-2,9)

Posted by Rahul Kumar 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Yadav 4 years, 7 months ago

2,-2

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lcm for 24, 60,150

Posted by Ahmadullah Khan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepakshi Kabra 4 years, 7 months ago

600

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Chapter 8 trigonometry Hindi medium all formulas

Posted by Jatin Thakur 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepakshi Kabra 4 years, 7 months ago

https://www.examtricksadda.com/2017/02/trigonometry-formula-short-tricks-with-example-hindi.html?m=1 //Visit through this link

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All formulas of chapter 4

Posted by Aaru Rathor 4 years, 7 months ago

CBSE > Class 10 > Mathematics

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If cot A=15/8 find sinA, cosA, cosecA

Posted by Neeraj Kataria 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Vivek Pathak 4 years, 7 months ago

cotA=b/p Given,b/p=15/8 By applying Pythagoras theorem we get, P^2+b^2=h^2 8^2+15^2=h^2 54+225=h^2 h=√64+225 therefore, H=17 SinA=p/h =8/17 CosA=b/h=15/17 and, CosecA=h/b=17/15 Hope you will like this answer

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Nitin Tripathi 4 years, 7 months ago

Given that:- cot A=15/8 And we know that:- cot A=b/p So that, base is 15 & perpendicular is 8 and by the Pythagoras theorem we find 17 as a hypotenuse. Hence, •sin A=p/h=8/17 •cos A=b/h=15/17 •cosec A=h/p=17/8 Hope you understand this very simple way.

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Mandeep Kumar 4 years, 7 months ago

Cot A=b/p Sin A=p/h CosA=b/h CosecA=h/p Given Cot A=15/8 b=15 p=8 We find h from Pythagoras theorm h²=b²+p² h=17 So,SinA=8/17,Cos=15/17 and Cosec=17/8

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Probability of 52 mondays in a leap year

Posted by Ashish Kumar Singh 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepakshi Kabra 4 years, 7 months ago

1/7

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Find tan p – cot R

Posted by Dipika Das 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Nitin Tripathi 4 years, 7 months ago

Can you please write the full question

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What is linr

Posted by Govind Sharma 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Govind Sharma 4 years, 7 months ago

What is line segnment

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Solve by elimination method √5x - √7y = 0 √7x - √3y = 0 Find the value of x and y

Posted by Rakhi Mishra 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Mahima Damor 4 years, 7 months ago

First of all we will squaring all the terms = (√5x)² - (√7y)²=0 , (√7x)² - (√3y)²=0 After that is becomes = 5x–7y=0 -this will be equation 1 7x–3y = 0 -this will bhi equation 2 We multiply equation 1 from 7 and equation 2 from 5 Then it eq 1×7 subtract eq 2×5 Eq 1- +35x – 49y = 0 Eq 2- ± 35x ± 15y = 0 ————————— 0 34y = 0 Y = 34 Now we put the value of 'y' in eq 1 5x–7y = 0 5x–7×34 = 0 5x–238 = 0 X = 238/5 X = 47.6 Y = 34

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if x =2^3 3 5 ^2 ,y=2^2 3^3

Posted by Mounika K 4 years, 7 months ago

CBSE > Class 10 > Mathematics